similar to: Formatting zeroes with prettyNum

You fed it two characters, "dash" and "space" and it only wanted one character so it truncated to the first character and warned you that that's what it did. If you had your space before the dash, it would have used that as your replacement character > prettyNum(0, zero.print = " - ", replace = TRUE) [1] " " Warning message: In .format.zeros(x,

Tim, The purpose of the `replace.zero` argument is to allow longer replacements. See for example the behaviour with a character vector input: > prettyNum("0", zero.print = "- ", replace.zero = TRUE) [1] "- " I'm pretty sure this is a bug, and have now posted the relevant details on r-devel. A fix would be below. Best, Mikko diff --git

FWIW, it doesn't seem to be happening on Mac OS: > format(2^30, digits=0) [1] "1.e+09" > prettyNum(12345.6, digits=0) [1] "1.e+04" A glibc misfeature? -pd > On 22 Mar 2019, at 10:10 , Martin Maechler <maechler at stat.math.ethz.ch> wrote: > > Thank you, Robert for raising this here ! > >>>>>> Robert McGehee

? Fri, 23 May 2025 11:47:33 +0000 Marttila Mikko via R-devel <r-devel at r-project.org> ?????: > When called with a numeric vector, the `replace.zero` argument is > disregarded. > > > prettyNum(0, zero.print = "- ", replace.zero = TRUE) > [1] "-" > Warning message: > In .format.zeros(x, zero.print, replace = replace.zero) : >

Thank you, Marttila and Ivan, As the original author of prettyNum() {etc ..}, I will commit such a bug fix to R-devel (and probably port it to R 4.5.0 patched) quite soon (but not yet today). Best regards, Martin Maechler >>>>> Ivan Krylov via R-devel >>>>> on Fri, 23 May 2025 17:14:57 +0300 writes: > ? Fri, 23 May 2025 11:47:33 +0000 >

Dear list, I'd like to report a bug in `prettyNum()`. When called with a numeric vector, the `replace.zero` argument is disregarded. > prettyNum(0, zero.print = "- ", replace.zero = TRUE) [1] "-" Warning message: In .format.zeros(x, zero.print, replace = replace.zero) : 'zero.print' is truncated to fit into formatted zeros; consider 'replace=TRUE' A

Thanks for the contribution Mikko! For testing future patches, you can actually do it right in the web browser, thanks to Heather Turner's R Dev Container, see instructions here https://contributor.r-project.org/r-dev-env/container_setup/ Best Toby On Mon, May 26, 2025 at 6:28?PM Martin Maechler <maechler at stat.math.ethz.ch> wrote: > Thank you, Marttila and Ivan, > > As

R developers, Seems I get a bad result ("%#4.0-1e" in particular) when trying to use prettyNum digits=0 with scientific notation. I tried on both my Linux box and on an online R evaluator and saw the same problem, so it's not limited to my box at least. I see the problem in both R 3.5.3 and R 3.3.2. options(scipen=-100) prettyNum(1, digits=0) [1] "%#4.0-1e" prettyNum(2,

Under R-1.5.0 on Solaris 2.6: R> prettyNum(123456789, big.mark=",") [1] ",123,456,789" and that bad behavior (leading comma) spills into formatC as well: R> formatC(123456789, digits=0, format="f", big.mark=",") [1] ",123,456,789" Looks to me like a bug in src/library/base/R/format.R, in function prettyNum: B.[i.big] <-

Thank you, Robert for raising this here ! >>>>> Robert McGehee >>>>> on Thu, 21 Mar 2019 20:56:19 +0000 writes: > R developers, > Seems I get a bad result ("%#4.0-1e" in particular) when trying to use prettyNum digits=0 with scientific notation. I tried on both my Linux box and on an online R evaluator and saw the same problem, so

>>>>> peter dalgaard >>>>> on Fri, 22 Mar 2019 17:30:19 +0100 writes: > FWIW, it doesn't seem to be happening on Mac OS: >> format(2^30, digits=0) > [1] "1.e+09" >> prettyNum(12345.6, digits=0) > [1] "1.e+04" > A glibc misfeature? It seems (and note we are talking about format.default()

Hi -- I'm looking for alternatives to regex for a fairly simply 'reformatting' problem. Alternatives only because a lot of folks have trouble parsing/interpreting regex expressions, and I'm looking for suggestions for something more 'transparent'. Here is an example of what I'm trying to do. Take the following string, which I call x, and for each character in the

Hi! If I use format() on numeric vector, na.encode argument does not have any e= ffect. This was reported before: - https://stat.ethz.ch/pipermail/r-help/2007-October/143881.html - http://tolstoy.newcastle.edu.au/R/e2/devel/06/09/0360.html It works for other (say character) classes! > format(c("a", NA), na.encode=3DTRUE) [1] "a " "NA" >

Hi I am not sure if it is more readable > paste(paste(unlist(strsplit(x,"")),".", sep=""), collapse="") [1] "1.0.1.1.0.1.1.1." If you did not want last dot, it is a bit shorter. > paste(unlist(strsplit(x,"")),collapse=".") [1] "1.0.1.1.0.1.1.1" > Cheers Petr Tento e-mail a jak?koliv k n?mu p?ipojen?

Full_Name: Dirk Jacob Version: R 2.8.1 and 2.9.1 OS: Win XP Submission from: (NULL) (153.96.32.62) I want to convert numbers to strings like: > inputs= c(0.3+0*(1:12) ) > (format(inputs,digits=3,scientific=T,collapse=" ")) and it works [1] "3e-01" "3e-01" "3e-01" "3e-01" "3e-01" "3e-01" "3e-01"

Hello, helpeRs, I have a vector of numbers from 1-365 (days of the year) that I would like to convert to a date. There are no NA's and no missing values. I did not insert leading zero's for numbers less than 100. Using the syntax: dat$doy.1 <- as.numeric(format(dat$doy, "%j" )) I get the following error message: Error in prettyNum(.Internal(format(x, trim, digits,

Hi there, i'm not getting along with the following problem. I'd like to print a real number, e.g. x <- 12.3 with exactly two digits after the decimal point, e.g. 12.30 I've tried the whole format(), formatC() and prettyNum() functions but did not have any success with it. This should work with all real numbers, in case even with 0.0 (-> 0.00). For cracks this thing is pretty

Hello R-helpers, I have a problem with formatting a single number to show leading zeros. For example, I want "2" displayed as "002". My numbers have 1 to 3 digits and I would like them all to display 3 digits for printing. I know I could use "paste" in a loop with several "if"s, but I was wondering if there is a single function that can do this. I have

Dataframe cust has Date-type column open.date. I wish to set up another column, with (first day of) the quarter of open.date. To be comprehensive (of course, improvement suggestions are welcome), month = function(date) { return(as.numeric(format(date,"%m"))) } first.day.of.month = function(date) { return(date + 1 - as.numeric(format(date,"%d"))) } first.day.of.quarter =

> On 22 Mar 2019, at 18:07 , Martin Maechler <maechler at stat.math.ethz.ch> wrote: > > gives (on Linux R 3.5.3, Fedora 28) > > d=10 d=7 d=2 d=1 d=0 > [1,] "123456" "123456" "123456" "1e+05" "%#4.0-1e" > [2,] "12345.6" "12345.6" "12346"