similar to: Help merging large datasets in R

Some issues: 1) Variable names cannot have spaces. "merged 1" is not valid but "merged_1" is a valid alternative. 2) You need to tell R what to merge by. It looks like you may be using data tables rather than a data frame. merged <- dataset2[dataset1, on = "id", nomatch = NA] 3) Alternatively: join functions from the dplyr package, cbind(), and rbind() can be used

> Variable names cannot have spaces Please soften your words... variables can have all sorts of characters including spaces in them, but it can be inconvenient to quote them all with back-tick quotes like `merged 1` so where possible most people avoid variable names with weird characters. People also often have to work with column names provided by an external source. It can be harder to

Hello, I am new to R and currently have the following problem: I have successfully loaded my data in R which consists of two numeric columns (LI_F and female) and one character column (Strain). So far I can plot two different set of boxplots for each of the numeric columns plotted by the groups of the character column and the commands look like that: boxplot(LI_F~Strain, ylab="LI_F",

I have 3 sets of Cartesian data, one is 'original' data and the other 2 are "smoothed"data. The smoothed data is the result of applying a smoothing algorithm to the original.One set of smoothed data is the 'old' algorithm and the other set is the 'new' algorithm. Does R have the capability of telling me which data is "smoother"? Example data (subsets

Hello all, I am wondering if there is a way to do a spatial error probit/logit model in R? I can't seem to find it in any of the packages. I can do it in MATLAB with Gibbs sampling, but would like to confirm the results. Ideally I would like to use this model to predict probability of parcel conversion in a future time period. This seems especially difficult in a binary outcome model

Hello, It's several days I try to track this bug, and even cannot cook a reproducible example. Yet, it occurs consistently in a long-running task after a variable period of time. Here is an example: ... my long-running code [as I said, cannot give something simple that produces this bug in a reproducible manner] Error in match(x, table, nomatch = 0L) : formal argument

Dear R developers, We have a big SGI Origin computation server with 32 cpu's and 64 Gb of RAM. In R 2.0.0 we could run large jobs, allocating 8 Gb of RAM was not a problem, for example by running: > v1 <- seq(1,2^29) > v2 <- seq(1,2^29) > v3 <- seq(1,2^29) > v4 <- seq(1,2^29) This yields an R process, consuming about 8 Gb of RAM: PID PGRP USERNAME

I do think keeping the default behavior is desirable for backwards compatibility; my suggestion is not to change default behavior but to add an optional argument that allows a different behavior. Although this can be implemented in a user-defined function, retaining empty matches facilitates programmatic use, and seems to be something that should be available in base R. It is available, for

When I run R CMD check R.oo on R v2.7.0 devel (2008-03-04 r44677) on WinXP I get the following error while testing examples: Error in match(x, table, nomatch = 0) : formal argument "nomatch" matched by multiple actual arguments Calls: setMethodS3 -> setMethodS3.default -> %in% -> match Execution halted How is that even possible with: > get("%in%") function (x,

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Le 18/02/2016 11:03, Richard Mudgett a ?crit : > I've been using Grandstream phones for more than 10 years, but onl y > yesterday tried to use Early Dial... and I failed. What is needed on the > Asterisk side to reply 484 to INVITE? Phones are talking to chan_p jsip > on Asterisk-13.7.1. > > > Look into the

Is there packaged code to convert geographical coordinates (e.g., longitude, latitude, elevation) to Cartesian coordinates in 3-space? I can see how to do this using 1. a spherical-to-Cartesian conversion like pracma::sph2cart(tpr) http://cran.r-project.org/web/packages/pracma/ 2. a geographical-to-spherical conversion. This seems to involve (in roughly increasing order of difficulty or

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi Bryant, Thanks for your reply. It didn't work immediately, I had to create a second context, or else it was looping between the second and first line. This seems to work: [earlydial] ; Test Early Dial exten => _.,1,Set(l_Extension=${EXTEN}) exten => _.,n,Goto(earlydial2,${l_Extension},1) [earlydial2] exten => _.,n,Goto(noMatch,1)

Hi, I'm looking for a function that will take a list of columns or data.frame and corvert it to cartesian pairlist. For example for this data.frame (see below), I'd like to get a list of all possible pairs: > sound cs rs ns 7 5 2 4 5 4 6 3 1 8 4 1 6 4 2 6 7 1 2 2 5 9 2 5 how can I get this? > mylist ((cs,rs), (cs,ns), (rs,ns))

Hi all,I had a question last week on asking for a function that will help me draw three different circles on x,y,z axis based on polar coordinates (Each X,Y,Z circle are coming from three independent measurements of 1-360 polar coordinates). It turned out that there ?is no such function in R and thus I am trying to write my own piece of code that hopefully I will be able to share. I have spent

Hello List, I am looking for efficient code to produce the Cartesian product of two or more data.frames. I'd like to be able to do this without resorting to looping. I have searched the FAQ, web, etc without luck. That being said, the help page for merge says that the function can produce what I'm looking for if the by vectors are of zero length. Would someone be so kind as to

Hi all, I'm trying to plot this two curves in a single cartesian plane, but when I plot the first one, the plot appears with no negative "y" value. When I plot the second curve, it almost does not apear in the graph. I was trying the plot.window but with no success. Can someone help me with this? If possible, I'd like to plot this curves in a perfect cartesian plane. f =

Hi, Is there a command to get the indices of intersecting elements of two vectors as intersect() will give the elements and not its indices. Thanks in advance. Praveen Surendran School of Medicine and Medical Sciences University College Dublin Belfield, Dublin 4 Ireland. [[alternative HTML version deleted]]

I have a table: C1 RowName1 3 RowName2 2 and another table: C2 RowName1 5.6 RowName1a 4.3 RowName2 NA I want to join join the tables with matching rows: C1 C2 RowName1 3 5.6 RowName2 2 NA I'm thinking of something like:

Sometimes I write code like this: > qf.a <- subset(qf, pubid %in% c(104, 106, 107, 108)) > qf.b <- subset(qf, !pubid %in% c(104, 106, 107, 108)) and I get a little worried that maybe I've remembered the precedence rules wrong, so I change it to > qf.a <- subset(qf, pubid %in% c(104, 106, 107, 108)) > qf.b <- subset(qf, !(pubid %in% c(104, 106, 107, 108))) and pretty

Looking at the code of function 'table' in R devel r71227, I see that the part "remove NA level if it was added only for excluded in factor(a, exclude=.)" is not quite right. In is.na(a) <- match(a0, c(exclude,NA), nomatch=0L) , I think that what is intended is a[a0 %in% c(exclude,NA)] <- NA . So, it should be is.na(a) <- match(a0, c(exclude,NA),