similar to: R CMD check says no visible binding for global variable

Naresh, I am not sure how you are creating your data.frame so it has no, I think, column names. There are two scenarios including one where it is not really a valid data.frame and one where it can be handled before any other use as shown below. If it cannot be used, you might need to modify how your SQL or the function you call creates it so it includes either names it chooses or that you supply.

Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns. Something like: Myquery <- ?SELECT date, price, stock FROM stocktab WHERE stock = ?ABC? AND date > ?2025-01-01?;? Prices <- dbGetQuery(con, myquery) SetDT(Prices) Prices[, date = as.Date(date)] R CMD check say ?no visible binding for global variable ?date?? Sent

There you go, once again helping strengthen ;) John Get Outlook for iOS<https://aka.ms/o0ukef> ________________________________ From: R-help <r-help-bounces at r-project.org> on behalf of avi.e.gross at gmail.com <avi.e.gross at gmail.com> Sent: Tuesday, January 28, 2025 12:01:25 AM To: 'Naresh Gurbuxani' <naresh_gurbuxani at hotmail.com>; r-help at r-project.org

That is an interesting fix Duncan suggested and it sounds now like everything WORKED as intended in data.table except that any checker being used externally is not able to del with things that look like a variable but are actually not a variable currently visible except within a function that is doing deferred evaluation. In this case, it recognizes the raw unevaluated string as being the name of

On 2025-01-28 1:55 p.m., Naresh Gurbuxani wrote: > Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns. > > Something like: > > Myquery <- ?SELECT date, price, stock FROM stocktab WHERE stock = ?ABC? AND date > ?2025-01-01?;? > > Prices <- dbGetQuery(con, myquery) > SetDT(Prices) > Prices[,

This solution worked. Thanks Sent from my iPhone > On Jan 28, 2025, at 3:09?PM, Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > > ?On 2025-01-28 1:55 p.m., Naresh Gurbuxani wrote: >> Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns. >> Something like: >> Myquery <- ?SELECT date,

R-help - I have this set of aggregated tables (sample data below via dput()). And I would like to have delayValue as the column variables with the "temp" (temp1, temp2, temp3) values as the row variables. However I would like to have the temp variables *aggregated into single rows* so that I have the frequency ("Freq" | counts) of each time each "delayValue" occurs

I am using R 2.1.1 in an windows XP environment. I have 2 dataframes, temp1 and temp2. Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric. I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe. (i.e. temp1$column

i have a time Series of IBM closing px from 1/1/2000 to today I want to graph the time serie by dividing the graph by year and month all the monthly graphs with the same year will go to one page. so from 1/1/2000 to 11/19/2010. i will have 11 pages, and each page will have 12 graphs (jan to dec) except for 2010. I am able to do it in R, but when i use sweave, I can only print the last page.

temp = "~aparch(" temp1 = paste(temp,1, sep = "") temp2 = paste(temp1,1, sep = ",") temp3 = paste(temp2, ")",sep = "") temp 3 is a character but I want to convert to formula object. How do I do this? -- View this message in context: http://r.789695.n4.nabble.com/how-to-convert-string-to-object-tp2999281p2999281.html Sent from the R help mailing

I stumbled onto this working on an update to coxph. The last 6 lines below are the question, the rest create a test data set. tmt585% R R version 2.12.2 (2011-02-25) Copyright (C) 2011 The R Foundation for Statistical Computing ISBN 3-900051-07-0 Platform: x86_64-unknown-linux-gnu (64-bit) # Lines of code from survival/tests/singtest.R > library(survival) Loading required package: splines

Hi Irucka, I tried it and was able to plot it without any errors.? Here, your code indicates you need two lines. temper[[i]][1] ?temper[[1]][1] # which is the column 1. ? Month 1???? 1 2???? 2 3???? 3 ?temper[[1]][2] #? Data1 #1?? 1.5 #2? 12.3 #3? 11.4 Suppose I use names(temper) instead of seq_along(temper) pdf("irucka.pdf") ?lapply(names(temper),function(i)

Hi all, I have a C code in Linux, it has 7 pointers and compile e run OK, but when I run in R happens problems with calloc function, it returns NULL. ############################################### > int *temp1,*temp2,*temp3,*temp4; temp1 = (int *)calloc(col,sizeof(int)); if(temp1 == NULL){ printf("\n\n No Memory1!"); exit(1); } temp2 = (int *)calloc(col,sizeof(int));

Hi, temp3<- read.table(text=" ID CTIME WEIGHT HM001 1223 24.0 HM001 1224 25.2 HM001 1225 23.1 HM001 1226 NA HM001 1227 32.1 HM001 1228 32.4 HM001 1229 1323.2 HM001 1230 27.4 HM001 1231 22.4236 #changed here to test the previous solution ",sep="",header=TRUE,stringsAsFactors=FALSE) ?tempnew<- na.omit(temp3) ?grep("\\d{4}",temp3$WEIGHT) #[1] 7 9 #not correct

On Mon, September 14, 2015 21:28, Always Learning wrote: > > On Mon, 2015-09-14 at 14:51 -0400, James B. Byrne wrote: > >> The Logwatch imapd service script distributed with CentOS-6 does not >> generate anything when I run logwatch --service all on a cyrus-imapd >> host. Is this expected behaviour? Is there a separate script for >> cyrus-imapd or are their

HI Irucka, Please check this: temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L, 2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342, 12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA, -4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L, 3L, 4L, 5L, NA), Data1 = c(1.52,

Hi, I am writing a function to plot a pdf of a distribution, GNL.pdf.fn = function(x,mu,sigma,alpha,beta,rho) { y = x-rho*mu cf.fn = function(s){ cplex = complex(1,0,1) temp1 = alpha*beta*exp(-sigma*s^2/2) temp2 = (alpha-cplex*s)*(beta+cplex*s) out = (temp1/temp2)^rho out } temp.fn = function(s){ (Mod(cf.fn(s)))*cos(Arg(cf.fn(s))-s*y) } int.fn =

Hello, I'm new to R with a (probably elementary) question. Suppose I have a dataset called /A/ with /n/ locations, and each location contains within it 3 time series of different variables (all of 100 years length); each time series is of a weather variable (for each location there is a temperature, precipitation, and pressure). For instance, location 1 has a temperature1 time series, a

Hi everyone I am new to R and have a question about missing values. I am trying to do a cluster analysis of monthly temperatures and my data are 14 columns with spatial coordinates (lat,lon) and 12 monthly values: /lat - lon - temp1 - //temp2 - temp3 - .... - //temp12/ If I omit missing values (my missing values are 99.00) with /mydata <- na.omit(mydata)/ every row with a

Hi, I have following kind of model : Y = X1 * a1 + X2 * a2 + error Here sampled data for Y, X1, X2 are like that : Y <- replicate(10, matrix(rnorm(2),2), simplify = F) X1 <- replicate(10, matrix(rnorm(4),2), simplify = F) X2 <- replicate(10, matrix(rnorm(4),2), simplify = F) My goal is to calculate LS estimates of vectors "a1" and "a2". Can anyone please guide me