similar to: aggregate produces results in unexpected format

Dear R users,   I am struggling to fit expo-linear equation to my data using "nls" function. I am always getting error message as i highlighted below in yellow color:     ### Theexpo-linear equation which i am interested to fit my data:       response_variable =  (c/r)*log(1+exp(r*(Day-tt))), where "Day" is time-variable   ## my response variable   rl <-

Dear R users, I am struggling to fit expo-linear equation to my data using "nls" function. I am always getting error message as i highlighted below in yellow color:  Theexpo-linear equation which i am interested to fit my data:       response_variable =  (c/r)*log(1+exp(r*(Day-tt))), where "Day" is time-variable my response variable rl <-

On Sat, Apr 08, 2017 at 09:11:22PM +0100, James Aylett wrote: > On 8 Apr 2017, at 19:15, Vivek Pal <vivekpal.dtu at gmail.com> wrote: > > >> and the details of which weighting schemes were available in which version > >> isn't a key part of the $set command itself. > > > > Do you suggest dropping that piece of information out? Since the reason behind

Hi, I was wondering how it was possible to access the actual cluster exemplars from the APResult class. Currently it only spits it out onto the terminal if you type the object but there is no other way to see which one is the examplar. Would appreciate any help. Thanks, Sachin [[alternative HTML version deleted]]

On Sun, Apr 09, 2017 at 11:34:07PM +0530, Vivek Pal wrote: > > Each scheme already has a human-readable name, and Xapian::Registry > > can map that to an "examplar" object of the right type, so we > > could take a string like "bm25 1 0.8", see the first word is "bm25" > > and get a BM25Weight object, then call parse_params("1 0.8") on

> It may be worth splitting that part of the $set documentation out into its > own section somehow, because it's getting a bit long - Undoubtedly; $set command has the longest section on the documentation page :) But it would be hard splitting that up because the documentation is organised in a way that each command is really contained in its own specific section. > and the details

Hello all, I am doing an aggregation where the aggregating function returns not a single numeric value but a vector of two elements using return(c(val1, val2)). I don't know how to access the individual columns of that vector in the resulting dataframe though. How is this done correctly? Thanks, robert > agg <- aggregate(formula=df$value ~ df$quarter + df$tool, + FUN=cp.cpk,

I'm having difficulty finding a solution to my problem that without using a for loop. For the amount of data I (will) have, the for loop will probably be too slow. I tried searching around before posting and couldn't find anything, hopefully it's not embarrassingly easy. Consider the data.frame, Data, below Data Sub Tr IA FixInx FixTime p1 t1 1 1 200 p1 t1 2

> Each scheme already has a human-readable name, and Xapian::Registry > can map that to an "examplar" object of the right type, so we > could take a string like "bm25 1 0.8", see the first word is "bm25" > and get a BM25Weight object, then call parse_params("1 0.8") on it to > create the correct Weight object (broadly similar to how

Hi all, currently, GetElementPtrInst has a method getIndexedType, which has a templated variant. You pass in a begin and an end iterator, and it will find the indexed type for those. However, both iterators must iterate over Value*. For some argpromotion code, I would like to pass in iterators that iterate over unsigneds instead of Value*. I currently solve this by transforming my

I have a string such as fileName<-"Agg.20.20.20-all-01". All I want to do is pull the "20.20.20" and the "all" as strings. Obviously, they aren't always those values. The "20.20.20" can be "30.30.30" but it's always after the . which is next to the second g in Agg and it's always the same length. The all might not always be

What is the recommended/optimal way to perform aggregates on data frames with chron objects? Here is an example: >raw.data 1 07/09/01 4000 2 07/09/01 2000 3 07/11/01 1000 4 07/13/01 800 5 07/13/01 700 6 07/16/01 600 7 07/17/01 500 I'm trying to construct a function that would first aggregate the data (second column) by day (grouping by the first column) according to a

Hi all, There might be a bug in DeadStoreElimination.cpp. This pass eliminates stores backwards aggressively in an end BB. It does not check dependencies on stores in an end BB though. For example, in this code snippet: ... 1. %sum.safe_r47.pre-phi = phi i64* [ %sum.safe_r47.pre, %entry.for.end_crit_edge ], [ %sum.safe_r42, %for.body ] 2. %call9 = call i32 @gettimeofday(%struct.timeval* %end,

Hi I generate a new dataframe by doing: npl.agg <- aggregate(npl$DensPlants, list(year=npl$year, sim=npl$sim), mean, na.rm=TRUE ) Now I want to plot it by using coplot(npl.agg$x ~ npl.agg$year | npl.agg$sim, type="l") but, as npl.agg$year is seen as a factor, the order of the points on the x-axis (time axis) does not follow the numerical sorting 1...100, but rather the text

Apologies for the previous mail (I sent it off too early by mistake). This is the correct example: rm(list=ls()) D_mean<-seq(-5,5,length=100) y<-exp(-D_mean^2/5) pdf("my.pdf") plot(D_mean,y,type="l",yaxt="n",lty=2,lwd=2,col="black", ylab = list(expression(paste(dN/dlogD[agg]," ["*cm^-3*"]"))), xlab = expression(paste(D[agg],"

On Thu, Oct 6, 2011 at 2:20 PM, Eli Friedman <eli.friedman at gmail.com> wrote: > On Thu, Oct 6, 2011 at 2:12 PM, Zeng Bin <ezengbin at gmail.com> wrote: >> Hi all, >> >> There might be a bug in DeadStoreElimination.cpp. This pass eliminates >> stores backwards aggressively in an end BB. It does not check dependencies >> on stores in an end BB though.

Hi all, This is my first post to the developers list. As I understand it, aggregate() currently repeats a function across cells in a dataframe but is only able to handle functions with single value returns. Aggregate() also lacks the ability to retain the names given to the returned value. I've created an agg() function (pasted below) that is apparently backwards compatible (i.e.

*Hola!!! resulta que tengo unos datos de divisas ordenados por fechas (días) los que he convertido a formato tipo YYYY-MM-DD donde DD siempre es 01:* * * * EUR.resto$date<-as.Date(EUR.resto$date) EUR.resto$mo <- substr(EUR.resto$date,6,7) EUR.resto$yr <- substr(EUR.resto$date, 1,4)

On Thu, Oct 6, 2011 at 2:12 PM, Zeng Bin <ezengbin at gmail.com> wrote: > Hi all, > > There might be a bug in DeadStoreElimination.cpp. This pass eliminates > stores backwards aggressively in an end BB. It does not check dependencies > on stores in an end BB though. For example, in this code snippet: >   ... > 1.  %sum.safe_r47.pre-phi = phi i64* [ %sum.safe_r47.pre,

I want to write a function that get 2 strings y and z and does the following R command. temp<-qq1[qq1$z==y,] for example if it get y="AMI" and z="PrimaryConditionGroup" It should do the following temp<-qq1[qq1$PrimaryConditionGroup=="AMI",] I could do it by the following function that is ugly and I wonder if there is an easier way to do it espacielly when temp