similar to: Using multiple dat files

Dear community To import multiple .dat weather files I am using list.files(). I intend to use the R package ?ClimInd? to calculate different agroclimatic indicators. Question: Is there another solution to import multiple .dat files so that I can select elements from the list, e.g. one specific weather file (example AAR_DailyWeather)? # Import multiple .dat files weather data filelist <-

?s 18:59 de 06/11/2024, Sibylle St?ckli escreveu: > Dear Rui > Dear Bert > Many thanks > Solution > filelist <- list.files(path = "O:/Data-Work/2.../Daten_RA-MeteoCH_1990-2021", > pattern='*.dat', all.files= T, full.names= T) > AAR<-read.table(filelist[1]) > It seems therefore that there is no other way than read in individually > 100 > weather

Dear community Dear Ivan Thanks a lot. The code works now. Solution: direct and full path to the .tif files. I confused back and forward slash #first import all files in a single folder as a list rastlist <- list.files(path = "C:/Users/Sibylle St?ckli/Desktop/NCCS_Impacts_Lot2_2022/InVEST/Species_Input/valpar_bee_presence", pattern='.tif$', all.files= T, full.names= T) At

Many thanks Ivan Use is.na() on getValues() outputs, combine the two masks using the | operator to get a mask of values that are missing in either raster, then negate the mask to choose the non-missing values: all.equal(getValues(r1)[!mask], getValues(r2)[!mask]) --> what do you mean by use is.na() in getValues(). So I need to call getValues a second time? I suppose you mean to first

Dear Ivan Thanks a lot. I tried now to provide the full path. However probably the "?" in the path produces the error, would that be possible? > #first import all files in a single folder as a list > rastlist <- list.files(path = "C:\Users\Sibylle St?ckli\Desktop\NCCS_Impacts_Lot2_2022\InVEST\Species_Input\valpar_bee_presence", pattern='.tif$', all.files=

Dear Ivan Thanks a lot for this very nice example. Is it true that all.equal just compares y values? Based on this help here I think so and the value I got is the difference for the y-values. https://www.statology.org/all-equal-function-r/ However, here I see x and y testing? https://www.rdocumentation.org/packages/base/versions/3.6.2/topics/all.equal I am actually interested in the x values

Dear John Kane Dear R community Here my working example 1. Example that is working with legend=?top?. However, as mentioned, the legend is in the middle of the top axis. mylist<-list(p1, p2) dev.new(width=28, height=18) fig1<- ggarrange(plotlist=mylist, common.legend = TRUE, legend="top", labels = c("(A)", "(B)"), font.label = list(size = 18, color =

"Is it true that all.equal just compares y values?" The following may be a bit more than you may have wanted, but I hope it is nevertheless useful. The first place you should go to for questions like this is the Help system, not here, i.e. ?all.equal When you do this, you will find that all.equal() is a so-called S3 generic function, which, among other things, means that it works

-------- Original-Nachricht -------- Datum: Wed, 27 Oct 2010 15:03:48 +0200 Von: "Sibylle St?ckli" <sibylle.stoeckli at gmx.ch> An: Rhelp <r-help at r-project.org> Betreff: as.list Dear R-users sorry, here Rcode included (attachment has been removed) I would like to read a txt file as list, to select rows and columns, and to create barplots. (1) selection of parameter

I'm sorry but that is not a working example. A working example needs to create the plots being used. For example, stealing some code from https://rpkgs.datanovia.com/ggpubr/reference/ggarrange.html #================================================================= data <https://rdrr.io/r/utils/data.html>("ToothGrowth")df <- ToothGrowthdf$dose <- as.factor

?? The OP's original problem is that the all.equal method for raster objects (raster:::all.equal.raster), which is a wrapper around the compareRaster() function, compares a bunch of different properties of rasters (extent, resolution, values, etc.) and only returns a single overall logical (TRUE/FALSE) value. OP wanted to see the magnitude of the difference (as you could get for more

Ah...I see. Perhaps, then, the maintainer should be contacted, as the desired functionality seems similar to that provided in other all.equal methods. I realize that this may often not elicit a (prompt) response. -- Bert On Sun, Aug 18, 2024 at 11:50?AM Ben Bolker <bbolker at gmail.com> wrote: > > The OP's original problem is that the all.equal method for raster >

? Thu, 18 Apr 2024 11:08:33 +0200 SIBYLLE ST?CKLI via R-help <r-help at r-project.org> ?????: > > #to check the index numbers of all imported raster list elements > > allrasters > list() > > > > #call single raster element > > allrasters[[1]] > Error in allrasters[[1]] : subscript out of bounds `allrasters` is an empty list, so it doesn't have a

Could you supply us with a MWE (minimal working example)of what you have so far? Thanks. On Mon, 5 Feb 2024 at 05:00, SIBYLLE ST?CKLI via R-help < r-help at r-project.org> wrote: > Dear R community > > It is possible to adjust the legend in combined ggplots using ggarrange > with > be positions top, bottom, left and right. > My question: Is there a function to change the

Hi, Just find a scaling factor that would make the two sets of data comparable. Here I divided the second row by 5 and did the same for the second axis. Charles-?douard F1 <- as.table(matrix(c(50,11,6,17,16,3,1,2237,611,403,240,280,0,0), 2,7)) barplot(F1, beside = TRUE, col = c("blue", "grey")) axis(2, at=c(0,10,20,30,40,50,60, labels=c(0,10,20,30,40,50,60))) axis(4, at =

Dear Charles-Edouard Thanks a lot. Yes indeed barplot sounds excellent. Unfortunately, the scale of the smaller axis is fixed, even If I am able to draw to axes. The idea is to expand the scale to the scale to the second axis for comparison. F1 <- as.table(matrix(c(50,11,6,17,16,3,1,2237,611,403,240,280,0,0), 2,7)) barplot(F1, beside = TRUE, col = c("blue", "grey"))

Dear Ivan Thanks a lot. I used: windowsFonts(Helvetica = windowsFont("Helvetica")) No warning now with Helvetica Additionally I used "sans", similarly no warning in the first part. But still not able to open tiff with both versions: Using "stress" as default layout > dev.off() TIFFOpen: figures/AES_network_bymembership.tiff: Cannot open. RStudioGD 2

? Fri, 23 Aug 2024 10:15:55 +0200 <sibylle.stoeckli at gmx.ch> ?????: > > s<-sf$Unterregio > > r<-allrasters_pres[[1]] > > > > > > rs <- stack(r, s) > > names(rs) <- c('r', 's') > Error in `names<-`(`*tmp*`, value = c("r", "s")) : > incorrect number of layer names It looks like at least one

? Fri, 16 Aug 2024 10:35:35 +0200 <sibylle.stoeckli at gmx.ch> ?????: > what do you mean by use is.na() in getValues(). So I need to call > getValues a second time? Not necessarily, but it's one of the options. I was thinking along the lines of: values1 <- getValues(r1) mask1 <- is.na(values1) # Do the same for r2 # Combine the masks all.equal(values1[!combined_mask],

? Fri, 16 Aug 2024 07:19:38 +0200 SIBYLLE ST?CKLI via R-help <r-help at r-project.org> ?????: > Is it possible to consider na.rm=TRUE? > > all.equal(getValues(r1), getValues(r2_resampled), tolerance = 0) > > [1] "'is.NA' value mismatch: 9544032 in current 66532795 in target" Use is.na() on getValues() outputs, combine the two masks using the | operator