similar to: Can not Create Maildir using userdb sql

Thank you for your reply. So, you mean that both user_query and password_query should have the same amount of parameter and the mail parameter from user_query should have the exact parameter as userdb_mail from password_query? And also I've to turn on userdb prefetch {} Kind Regards, Henry From: Timo Sirainen [mailto:tss at iki.fi] To: Dovecot Mailing List [mailto:dovecot at dovecot.org]

FWIW, now that privsep is mandatory I have no objection to including signal support in sshd. On Wed, 25 Jul 2018, Yonathan Bleyfuesz wrote: > Hi all, > > I would like to propose some ideas to revivify this subject. > > -First, we could add support on the client to send signal thanks to the escape characters. > (code :

Is there an option for running SUR and 2SLS regressions with weighting (I am analysing mortality in towns, hence want to weight by population size) Many thanks Jon Anson -- Yonathan (Jon) Anson Department of Social Work Ben Gurion University of the Negev 84105 Be'er Sheva, Israel. Tel: +972 8 647 93 14(w) +972 8 6489286 (h) 067 233279 (m) Fax: +972 8 647 29 33

Hi, >>> It would be nice to know what the precise technical issues are that have >>> prevented support for this from being added. From what I recall, it >>> seemed like the delay was largely due to details of the client >>> behaviour, and possibly some feature creep. It would indeed be really great to have some details on this point. Concerning the test of

Does anyone know if there is an R function that will take a matrix like this jim 1 0 0 0 0 0 jim 0 1 0 0 0 0 jim 0 0 1 0 0 0 bob 1 0 0 0 0 0 bob 0 0 1 0 0 0 harry 0 0 1 0 0 0 harry 0 0 0 1 0 0 harry 0 0 0 0 1 0 harry 0 0 0 0 0 1 and make it like this? (that is, add together rows that have the same name?) jim 1 1 1 0 0 0 bob

Dear R-helpers, I've got two functions; callTimes() calls times(), passing it an optional argument (bar) by name (bar=harry). times() then believes it has been passed a name, rather than a value ? but I want the value, not the name. Worse, if I evaluate the name, it is evaluated in the environment times() was defined, not where it is called. How can I call times(), defining its optional

Dear list, I spent about two hours searching on the message archive, with no avail. I have a list of people that have to pass an on-line test, but only a fraction of them do it. Moreover, as they input their names, the resulting string do not always match the names I have in my database. I would like to do two things: 1. Match any strings that are 90% the same Example: name1 <- "Harry

Hello, I have an unbalanced panel data set that looks like: ID,YEAR,HEIGHT Tom,2007,65 Tom,2008,66 Mary,2007,45 Mary,2008,50 Harry,2007,62 Harry,2008,62 James,2007,68 Jack,2007,70 Jordan,2008,72 That is, James, Jack, and Jordan are missing a YEAR. Is there any command that will "fill in" the missing YEAR such that the end result will be balanced and look like: ID,YEAR,HEIGHT

I have a list. my.list <- list(Tom=c(1,2,3), Dick=c(4,5,6), Harry=c(7,8,9)) I assign one of the names of the list to a variable. name <- "Harry" I can access the value of the list using the variable as follows: eval(parse(text=paste("my.list$", name, sep=""))) [1] 7 8 9 But how do I change the value of my.list$Harry using the variable name? This

Apologies for the novice question, but this is likely beyond my google searching range.. I am trying to create a table from the summaries of a file. The 2 column data table looks like; Harry 335/335 Harry 124/506 Harry 124/506 Dick 133 Tom 335/335 Tom 335/335 with 1000 unique values in col 1, 300 unique in col 2. The 'summary' doesn't seem

Hi All, I have a data frame of three columns, all of which names. The names in the three cols overlap up to a point, so I might have *Harry* in all three columns, *Tom* in cols 1 and 3 and *Bob* in col 3 only. harry paul bob anita harry tom frank jack harry tom pete ben .... I want to turn the names into numbers, BUT I want the numeric code for, say, *Harry*, to be the same on all

I predicted that y would increase as x increased. However, I only made the prediction on the ranks of the scores. The ranks don't correlate with predicted. And, I don't think a regression on the ranks is warranted. However, the actual scores do yield a significant slope for b, and a significant R^2 using a linear regression (y is the value and x is the predicted rank). What

On 18/01/15 15:18, Dr. Harry Knitter wrote: > Rowland Penny <rowlandpenny at googlemail.com> schrieb am 18.01.2015: > > >> Lets deal with the obvious first, your workgroup name, you give it as >> 'mydomain.lan' , now is that the actual workgroup name ? If so, then it >> shouldn't have the dot '.' in it, but > Never had poblems with that. And

Can anyone tell me what is wrong in this picture with error output: rsync -nvviirp --inplace harry@harvey:/cygdrive/c/Documents\ And\ Settings ./docs_settings_$(dtf) opening connection using ssh harvey -l harry rsync --server --sender -vvnpr --inplace . "/cygdrive/c/Documents And Settings" harry@harvey's password: protocol version mismatch -- is your shell clean? (see the rsync

all but one lan host (gv)can ssh connect to host 2x Included windows 10, several linux. 2x is a solaris host. That problem host (gv) can connect to all others but 2x. 2x can connect to all other encluding the problem host (gv) So gv ssh to 2x throws this error: ssh_dispatch_run_fatal: Connection to 192.168.1.42 port 22: incorrect signature. 192.168.1.42 is 2x. So incoming ssh from gv to 2x

Darren Tucker <dtucker at zip.com.au> writes: > On Tue, Nov 8, 2016 at 2:43 PM, Harry Putnam <reader at newsguy.com> wrote: >> Darren Tucker <dtucker at zip.com.au> writes: >> >>> On Tue, Nov 8, 2016 at 1:02 PM, Harry Putnam <reader at newsguy.com> wrote: >>> [...] >>>> gv harry> ssh -vv 2x >>>> >>>>

On 17/01/15 19:08, Dr. Harry Knitter wrote: > "Dr. Harry Knitter" <harry at knitter-edv-beratung.de> schrieb am 15.01.2015: >> Hllo, >> >> I have a Debian Wheezy machine with a standard samba configured as domain >> controller. (security = user) >> >> On the Windows clients a programm shall be installed that needs full access >> to all

I'm using Ubuntu 8.10 (Intrepid Ibex) and R 2.7.1. I've built a package from source (a modified version of gbm) and it contains some C++ code. I now want to cross-compile it to get a Windows version. I installed R using sudo apt-get update sudo apt-get install r-base sudo apt-get install r-base-dev So far as I can tell, I've also followed all the instructions in the guide

Hi Harry Thanks for the comments. All contents under /etc/samba/private were indeed copied over appprd#ls -l /etc/samba/private/ total 432 -rw------- 1 root root 180224 Mar 7 21:29 passdb.tdb -rw------- 1 root root 696 Mar 8 09:13 schannel_store.tdb -rw------- 1 root root 16384 Mar 7 20:29 secrets.tdb -rw------- 1 root root 14449 Mar 8 11:09

--- hgaillac-sip@yahoo.fr a ?crit : > hello, > > How asterisk could support res_snmp even this module > don't help to monitor all asterisk features? > > monitoring asterisk with snmp would be a good > thing. > Which solution ? > > Harry > --- Kristian Kielhofner <kris@krisk.org> a ?crit : > > > hgaillac-sip@yahoo.fr wrote: > > > I