similar to: Question regarding reservoir volume and water level

?s 13:27 de 07/04/2024, javad bayat escreveu: > Dear all; > I have a question about the water level of a reservoir, when the volume > changed or doubled. > There is a DEM file with the highest elevation 1267 m. The lowest elevation > is 1230 m. The current volume of the reservoir is 7,000,000 m3 at 1240 m. > Now I want to know what would be the water level if the volume rises to

Aside from the fact that the original question might well be a class exercise (or homework), the question is unanswerable given the data given by the original poster. One needs to know the dimensions of the reservoir, above and below the current waterline. Are the sides, above and below the waterline smooth? Is the region currently above the waterline that can store water a mirror image of the

John, Your reaction was what my original reaction was until I realized I had to find out what a DEM file was and that contains enough of the kind of depth-dimension data you describe albeit what may be a very irregular cross section to calculate for areas and thence volumes. If I read it correctly, this can be a very real-world problem worthy of a solution, such as in places like California

Dear all; Thank you for your reply. David has explained an interesting method. David I have DEM file of the region and I have extracted the xyz data from that. Also I can extract bathymetry data as xyz file. I have calculated the storage (volume) of reservoir at the current elevation. But the method I have used to calculate the volume is different from your method. I have crop DEM by the reservoir

Water engineer here. The standard approach is to 1) get the storage vs. elevation data from the designers of the reservoir or, barring that, 2) get the bathymetry data from USBR or state DWR, or, if available, get the DEM data from USGS if the survey was done before the reservoir was built or 3) get a boat+sonar with GPS? +lots of time and survey the bottom elevation yourself. Put the xyz

Homework? -- Sent from my Android device with K-9 Mail. Please excuse my brevity. On April 7, 2024 8:27:18 AM EDT, javad bayat <j.bayat194 at gmail.com> wrote: >Dear all; >I have a question about the water level of a reservoir, when the volume >changed or doubled. >There is a DEM file with the highest elevation 1267 m. The lowest elevation >is 1230 m. The current volume of

The volume of a polygon = 0. Polyhedra have volumes. This may be irrelevant, but if the lake is cylindrical == constant cross sectional area at all depths, then height doubles when the volume does and vice versa. Otherwise you have to know how area varies with height or use more sensible approximations thereto. Cheers, Bert On Tue, Dec 5, 2023, 20:13 javad bayat <j.bayat194 at

Dear all; I am trying to calculate the volume of a polygon shapefile according to a DEM raster. I have provided some codes at the end of this email.I dont know if the codes are correct or not. Following this, I have another question too. I want to know if the volume of the reservoir rises or doubles, what would be the elevation? I would be more than happy if anyone could help me. Sincerely "

Hi, As already mentioned, this is a great topic for R-sig-geo, where you'd probably get specialist answers like the lake morphology package https://cran.r-project.org/web/packages/lakemorpho/index.html which is explicitly designed for this kind of question. Sarah On Tue, Dec 5, 2023 at 11:13?PM javad bayat <j.bayat194 at gmail.com> wrote: > > Dear all; > I am trying to

Dear all; I have a dataframe with several columns. The columns are the elevation, volume and the area of the cells (which were placed inside a polygon). I have extracted them from DEM raster to calculate the volume under polygon and the elevation for a specific volume of the reservoir. > head(x6,2) Elevation Vol Area V_sum A_sum 1 2145 13990.38 85.83053 13990.38

hi all, how can i saving R output to docx or Jpeg format? [[alternative HTML version deleted]]

Dear R users; I am trying to fill a column based on a specific value in another column of a dataframe, but it seems there is a problem with the codes! The "Layer" and the "LU" are two different columns of the dataframe. How can I fix this? Sincerely for (i in 1:nrow(data2$Layer)){ if (data2$Layer == "Level 12") { data2$LU == "Park"

Dear R users I am trying to find a formula to calculate the angle of a polyline. Is there a way to do this? Many thanks. -- Best Regards Javad Bayat M.Sc. Environment Engineering Alternative Mail: bayat194 at yahoo.com [[alternative HTML version deleted]]

?s 21:05 de 11/06/2023, javad bayat escreveu: > Dear R users; > I am trying to fill a column based on a specific value in another column of > a dataframe, but it seems there is a problem with the codes! > The "Layer" and the "LU" are two different columns of the dataframe. > How can I fix this? > Sincerely > > > for (i in 1:nrow(data2$Layer)){ >

Dear Rui; Many thanks for your email. I used one of your codes, "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works correctly for me. Actually I need to expand the codes so as to consider all "Levels" in the "Layer" column. There are more than hundred levels in the Layer column. If I use your provided code, I have to write it

Assuming your polyline is defined by two vectors, one for the x coordinates, one for the y coordinates, you can try the following library(NISTunits) polyangles <- function(xV,yV) { stopifnot( (length(xV)==length(yV)) && (length(xV) >= 3)) v <- function(i) { c( xV[i]-xV[i-1], yV[i]-yV[i-1])} vlen <- function(v) { sqrt(sum(v*v)) } lV <- rep(NA_real_,length(xV)) for

A polyline by definition has many angles, so your question is ill-formed. And this is a question about math, not R, so is off topic here. I suggest reading Wikipedia. -- Sent from my phone. Please excuse my brevity. On January 29, 2018 11:10:02 PM PST, javad bayat <j.bayat194 at gmail.com> wrote: >Dear R users >I am trying to find a formula to calculate the angle of a polyline. Is

Hi; In the Vorbis 1.1 release notes from July 7, 2004, Monty says "The 1.1 libvorbisenc allows setting the fixed reservoir size (in bits, defaulting to two seconds worth of requested bitrate) and 'hoarding' behavior (whether the encoder tends to keep the bit reservoir more full or more empty) as well as the other encoding heuristics available through the API of 1.0.1."

Dear all; I am trying to calculate volume under each polygon of a shapefile according to a DEM. when I run the code, it gives me an error as follows. " Error in h(simpleError(msg, call)) : error in evaluating the argument 'x' in selecting a method for function 'addAttrToGeom': sp supports Z dimension only for POINT and MULTIPOINT. use `st_zm(...)` to coerce to XY dimensions

I like to use complex numbers for 2-dimensional geometry. E.g., > polyAngles2 function (xV, yV) { stopifnot((length(xV) == length(yV)) && (length(xV) >= 3)) z <- complex(re = xV, im = yV) c(NA, diff(Arg(diff(z))), NA) # radians, positive is counter-clockwise } > x <- c(0:3) > y <- c(0,0,1,1) > polyAngles2(x,y) / pi * 180 [1] NA 45 -45 NA Bill