similar to: Looping

Hello, I would like to read sets of files within a folder, perhaps using recursive methods. Right now, I rename the files before import. It would be even better to do this without renaming files, without providing explicit filenames, perhaps by importing files based on chronology, and translating each filename into a header? Please excuse my ignorance, and help cure my clunky programming

NOTE: posted this to gluster-devel when I meant to post it to gluster-users 01 | 02 mirrored --| 03 | 04 mirrored --| distributed 05 | 06 mirrored --| 1) Would this command work for that? glusterfs-volgen --name repstore1 --raid 1 clustr-01:/mnt/data01 clustr-02:/mnt/data01 --raid 1 clustr-03:/mnt/data01 clustr-04:/mnt/data01 --raid 1 clustr-05:/mnt/data01 clustr-06:/mnt/data01 So the

Suppose I start building nodes with (say) 24 drives each in them. Would the standard/recommended approach be to make each drive its own filesystem, and export 24 separate bricks, server1:/data1 .. server1:/data24 ? Making a distributed replicated volume between this and another server would then have to list all 48 drives individually. At the other extreme, I could put all 24 drives into some

Dear R community members I did find a good way to merge my 200 text data files in to a single data file with one column added will show indicator for that file. filelist = list.files(pattern = "K*cd.txt") # the file names are K1cd.txt .................to K200cd.txt data_list <-lapply(filelist, read.table, header=T, comment=";", fill=T) This will create list,

HI Irucka, Please check this: temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L, 2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342, 12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA, -4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L, 3L, 4L, 5L, NA), Data1 = c(1.52,

Hi Irucka, I tried it and was able to plot it without any errors.? Here, your code indicates you need two lines. temper[[i]][1] ?temper[[1]][1] # which is the column 1. ? Month 1???? 1 2???? 2 3???? 3 ?temper[[1]][2] #? Data1 #1?? 1.5 #2? 12.3 #3? 11.4 Suppose I use names(temper) instead of seq_along(temper) pdf("irucka.pdf") ?lapply(names(temper),function(i)

You could declare a matrix much larger than you intend to use. This works with a few megabytes of data. It is not very efficient, so scaling up may become a problem. m22 <- matrix(NA, 1:600000, ncol=6) It does not work to add a new column to the matrix, as in you get an error if you try m22[ , 7] but convert to data frame and add a column m23 <- data.frame(m22) m23$x7 <- 12 The only

Hello All, Many thanks to the help I have received so far. Here is an example data set I hope to plot Data1 Year Data SE 1 2005 2 0.01 2 2006 4 0.01 3 2007 5 0.01 4 2008 2 0.01 5 2009 3 0.01 6 2010 6 0.01 Data2 Year Data SE 1 2006 32 1 2 2007 100 2 3 2008 60 4 4 2009 67 3 5 2010 8 1 Notice Data2 has one less years worth of data than Data1 (which is my

Thanks. Will try it. Have not tried it but I think the following may work: out$results<-NULL out$results$ei<-ap out$results$vi<-vap All I need is printing by returning out (unless I turn it off). And, retrieve ap and vap as needed as shown above. Guess I need to read more about invisible. On 8/11/2024 10:09 PM, Rui Barradas wrote: > ?s 09:51 de 11/08/2024, Steven Yen escreveu:

Hello R community, I am trying to combine two CSV files that look like this: File A Row_ID_CR, Data1, Data2, Data3 1, aa, bb, cc 2, dd, ee, ff File B Row_ID_N, Src_Row_ID, DataN1 1a, 1, This is comment 1 2a, 1, This is comment 2 3a,

I have a dataset of the form below, consisting of one unique ID per row, followed by a series of visit dates. At each visit there are values for 3 dichotomous variables. Of the 8 different possible combinations of the three variables, 4 are "abnormal" and the remaining 4 are "normal". Everyone starts out abnormal, and then either continues to be abnormal at subsequent visits,

Hi This question is far less simple than the title suggests, please read carefully, thanks. I have 2 sets of data, both read into R >data1<-read.table ("1.txt", header=T, sep="\t") >data2<-read.table ("2.txt", header=T, sep="\t") >data1 Taxon stage1 stage2 stage3 stage4 T1 0 0 1 1 T2 0

Using R 2.6.2, say I have the following list of lists, "comb": data1 <- list(a = 1, b = 2, c = 3) data2 <- list(a = 4, b = 5, c = 6) data3 <- list(a = 3, b = 6, c = 9) comb <- list(data1 = data1, data2 = data2, data3 = data3) So that all names for the lowest level list are common. How can I most efficiently access all of the sublist items "a" indexed by the outer

Hello, I am having some problems to use the 'merge' function. I'm not sure if I got its working right. What I want to do is: 1) Suppose I have a dataframe like: height width 1 1.1 2.3 2 2.1 2.5 3 1.8 1.9 4 1.6 2.1 5 1.8 2.4 2) And I generate a second

Hi, R-listers I tried to plot several graphs in a sigle x-y coordinate settings, like the following: |(y) s | ****** s | ***** s | sssssssssssssssssss |_______________________________(x) where "*" and "s" denote two diffrent plots. However, when I used plot(data1); % data1 is the data points of "*"

Hello List, I am working on creating periodograms from IP network traffic logs using the Fast Fourier Transform. The FFT requires all the data points to be evenly-spaced in the time domain (constant delta-T), so I have a step where I zero-pad the data. Lately I've been wondering if there is a faster way to do this. Here's what I've got: * data1 is a data frame consisting of

1) When adding additional data sets to a plot using "plot" followed by "lines", is there a way to automate the scaling of the axes to allow for all data sets to fit within the plot area? 2) I attempted to solve this by setting xlim=c(min(c(data1,data2,data3)),max(c(data1,data2,data3))) however, there are some NAs and Infs in these data sets, and min(data1) and max(data1) both

Hi there, data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE) data1<-data.frame(data1) names(data1)<-c("areaid","x","y","date") data1 areaid x y date 1 1 1.2 1.3 3/23/2004 2 1 1.5 2.3 3/22/2004 3 2

Hi, consider the following two dataframes: x1=c("232","3454","3455","342","13") x2=c("1","1","1","0","0") data1=data.frame(x1,x2) y1=c("232","232","3454","3454","3455","342","13","13","13","13")

Hi, I have 2 dataframes of unequal length, and I would like to match a factor to them so that both dataframes will have the same number of rows. example: # create the 2 dataframes with unequal length data1 <- data.frame(letters, 1:26)[-c(5,10,19:21),] data2 <- data.frame(letters, 1:26)[-c(6,9,15:18),] data2a <- match(data1[,1], data2[,1]) data2b <- data2[data2a,] When I match