similar to: Is simplify2array working for dimension > 2?

Jean-Claude: Well, here's my "explanation". Caveat emptor! Note that: "simplify2array() is the utility called from sapply() when simplify is not false" and > sapply(a, I, simplify = "array") [,1] [,2] [1,] list,2 list,2 [2,] list,2 list,2 So it seems that simplify2array() is not intended to operate in the way that you expected, i.e. that recursive

Hello, I am currently getting a strange error when I call installed.packages(): Error in if (file.exists(dest) && file.mtime(dest) > file.mtime(lib) && : missing value where TRUE/FALSE needed Calls: installed.packages I am working with R 3.4.0 on Windows. I didn't get this error with R 3.3.3. Apparently, file.mtime() is returning NA well applied to a directory, and

Should simplify2array(higher=TRUE) treat 1 by 1 matrices differently than others? I expected a 3-dimensional array from all of the following 3 examples, not just the last 2. > str(simplify2array(list(array(11,c(1,1)), array(21,c(1,1))), higher=TRUE)) num [1:2] 11 21 > str(simplify2array(list(array(11:13,c(3,1)), array(21:23,c(3,1))), higher=TRUE)) int [1:3, 1, 1:2] 11 12 13 21 22

Running the example in the documentation causes R to crash. dario at bioinfo:~$ R R version 3.0.3 (2014-03-06) -- "Warm Puppy" Copyright (C) 2014 The R Foundation for Statistical Computing Platform: x86_64-pc-linux-gnu (64-bit) R is free software and comes with ABSOLUTELY NO WARRANTY. You are welcome to redistribute it under certain conditions. Type 'license()' or

Dear all How does one convert a "non-symmetric" list to a vector? See below: > x <- list() > x[[1]] <- letters[1:5] > x[[2]] <- letters[6:10] > x[[3]] <- letters[11:12] > x [[1]] [1] "a" "b" "c" "d" "e" [[2]] [1] "f" "g" "h" "i" "j" [[3]] [1] "k"

Hi, Suppose you created a dataframe like this: set.seed(28) ?dat1<-as.data.frame(simplify2array(list(letters[1:5],sample(1:20,5,replace=TRUE),6:10)),stringsAsFactors=FALSE) ?str(dat1) #'data.frame':??? 5 obs. of? 3 variables: # $ V1: chr? "a" "b" "c" "d" ... # $ V2: chr? "1" "2" "10" "18" ... # $ V3: chr?

i'm somehow embarrassed to even ask this, but is there any built-in method for doing this: my_list <- list() my_list[[1]] <- matrix(1:20, ncol = 5) my_list[[2]] <- matrix(20:1, ncol = 5) now, knowing that these matrices are identical in dimension, i'd like to unfold the list to a 2x4x5 (or some other permutation of the dim sizes) array. i know i can initialize the array, then

While working with sapply, the documentation states that the simplify argument will yield a vector, matrix etc "when possible". I was curious how the code actually defined "as possible" and see this within the function if (!identical(simplify, FALSE) && length(answer)) This seems superfluous to me, in particular this part: !identical(simplify, FALSE) The preceding

Wouldn't that change how simplify='array' is handled? > str(sapply(1:3, function(x)diag(x,5,2), simplify="array")) int [1:5, 1:2, 1:3] 1 0 0 0 0 0 1 0 0 0 ... > str(sapply(1:3, function(x)diag(x,5,2), simplify=TRUE)) int [1:10, 1:3] 1 0 0 0 0 0 1 0 0 0 ... > str(sapply(1:3, function(x)diag(x,5,2), simplify=FALSE)) List of 3 $ : int [1:5, 1:2] 1 0 0 0 0 0 1 0 0

You?re right, it sure does. My suggestion causes it to fail when simplify = ?array? From: William Dunlap [mailto:wdunlap at tibco.com] Sent: Tuesday, March 13, 2018 12:11 PM To: Doran, Harold <HDoran at air.org> Cc: r-help at r-project.org Subject: Re: [R] Possible Improvement to sapply Wouldn't that change how simplify='array' is handled? > str(sapply(1:3,

Hi I would like to eliminate a large number of lines of the dataframe df1 The lines to delete are given here by the values of Mat (ex : 2,4,7,10). but I have a large number (300) values of Mat dput(df1) structure(list(Mat = c(1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 10, 10, 10, 11,

On 03/13/2018 09:23 AM, Doran, Harold wrote: > While working with sapply, the documentation states that the simplify argument will yield a vector, matrix etc "when possible". I was curious how the code actually defined "as possible" and see this within the function > > if (!identical(simplify, FALSE) && length(answer)) > > This seems superfluous to me,

Hi all, In the following code, it doesn''t look like the onUpdate() event is firing. Am I doing something wrong? <ul id="testSort"> <li id="item1">item 1</li> <li id="item2">item 2</li> <li id="item3">item 3</li> <li id="item4">item 4</li> <li id="item5">item

I've installed dovecot with maildir format in /home/claude/mail. I fetch my email with fetchmail and they are placed in /var/spool/mail/claude. How can I transfer them automatically in /home/claude/mail/INBOX/new How can I setup something to transfer my email automatically as they arrive. Claude

Martin In terms of context of the actual problem, sapply is called millions of times because the work involves scoring individual students who took a test. A score for student A is generated and then student B and such and there are millions of students. The psychometric process of scoring students is complex and our code makes use of sapply many times for each student. The toy example used

I am curious if anyone knows of R code where the "{" function is redefined in a useful way. Or "(" for that matter. Thanks Mick

Le lundi 21 f?vrier 2005 ? 15:08 +0100, Claude Brisson a ?crit : > Why not move the manual on the wiki ? Because it's already written in LyX and can be easily converted to pdf, html or anything. However, the trouble shooting part could be on a wiki. Do you volunteer? Jean-Marc > Claude > > On Mon, 2005-02-21 at 21:35 +0800, James Oh wrote: > > Hi, > > > >

On Tue, 2005-01-11 at 02:07 -0500, Jean-Marc Valin wrote: > > noticed there's a 64 bit integer being used in the long term prediction. > > any chance of using a 32 bit integer without incurring some major side-effects? > > A 32-bit integer may overflow (which is why I used a 64-bit int). Of > course, it's possible to emulate it using 32-bit arithmetic. Otherwise, >

Hi all, I have tried to use the loop-unroll pass on a large example, but without success. So I have tried on smaller examples, and I did not get more success. My simplest example is attached. It comes from this C code (using llvm-gcc, but similar result with clang): int main (int argc, char *argv[]) { int i; for (i = 0; i!=5; ++i) {} return 0; } I use this command (version 2.8svn, from

Greetings! For some reason I am not managing to work out how to do this (in principle) simple task! As a result of applying strsplit() to a vector of character strings, I have a long list L (N elements), where each element is a vector of two character strings, like: L[1] = c("A1","B1") L[2] = c("A2","B2") L[3] = c("A3","B3")