similar to: Basic astronomy package recommendation wanted.

On Tue, 30 Jan 2024, Richard O'Keefe writes: > Given > - UTC timestamp > - a location (latitude,longitude,elevation) > I want to know > - the sun angles > - the moon angles > - the phase of the moon. > I looked on CRAN for astronomy, but didn't notice anything that seems > to offer what I want. I could try coding these functions myself, but > "if

There is also the package solrad that might do some of this. It is more intended for calculating solar radiation, which is probably not what you want, but may do other things you may find helpful. > On Jan 30, 2024, at 5:44?AM, Enrico Schumann <es at enricoschumann.net> wrote: > > On Tue, 30 Jan 2024, Richard O'Keefe writes: > >> Given >> - UTC timestamp

Dear R Users, Are there any tools to extract the function names called by reverse-dependencies? I would like to group these functions using clustering methods based on the co-occurrence in the reverse-dependencies. Utility: It may be possible to split complex packages into modules with fewer reverse-dependencies. Package pkgdepR may offer some of the functionality; but I did not have time to

Given - UTC timestamp - a location (latitude,longitude,elevation) I want to know - the sun angles - the moon angles - the phase of the moon. I looked on CRAN for astronomy, but didn't notice anything that seems to offer what I want. I could try coding these functions myself, but "if you didn't write it you didn't wrong it".

?.S3methods f <- function()(2) > length(.S3methods(f)) [1] 0 > length(.S3methods(print)) [1] 206 There may be better ways, but this is what came to my mind. -- Bert On Wed, Mar 8, 2023 at 11:09?AM Leonard Mada via R-help < r-help at r-project.org> wrote: > Dear R-Users, > > I want to change the args() function to return by default the arguments > of the default

Dear Rich, It depends how the data is generated. Although I am not an expert in ecology, I can explain it based on a biomedical example. Certain variables are generated geometrically (exponentially), e.g. MIC or Titer. MIC = Minimum Inhibitory Concentration for bacterial resistance Titer = dilution which still has an effect, e.g. serially diluting blood samples; Obviously, diluting the

Dear R-Users, I want to change the args() function to return by default the arguments of the default generic function: args = function(name, default = TRUE) { ?? ?# TODO: && is.function.generic(); ?? ?if(default) { ?? ???? fn = match.call()[[2]]; ?? ???? fn = paste0(as.character(fn), ".default"); ?? ???? name = fn; ?? ?} ?? ?.Internal(args(name)); } Is there a nice way

Dear Gregg, Thank you for the fast response. I believe though that isGeneric works only for S4-functions: isGeneric("plot") # FALSE I still try to get it to work. Sincerely, Leonard On 3/8/2023 9:13 PM, Gregg Powell wrote: > Yes, there is a way to check if a function is generic. You can use the isGeneric function to check if a function is generic. Here's an updated version

Dear Konrad, I presume that the system can be written as follows, where h0, d0, ga0, kga and kd are given: err1 = h + hd + hga - h0; err2 = d + hd - d0; err3 = ga + hga - ga0; err4 = hga - kga*h*ga; err5 = hd - kd*h*d; All error terms should be zero. Do you need (a) the symbolic solution or (b) is a numeric solution fine? I do not have any experience with yacas or caracas. But see below. ###

Dear R-Users, Did anyone follow more closely the SARS Cov-2 lineages? I have done a quick check of Cov-2 mutations on the list downloaded from NCBI (see GitHub page below); but it seems that the list contains the cumulative mutations only for B.1 => B.1.1, but not after the B.1.1 branch: # B.1 => B.1.1 seems cumulative diff.lineage("B.1.1", "B.1", data=z) # but B.1.1

Dear R-List Members, I am looking for collaborators to further develop the BioShapes almost-package. I added a brief description below. A.) BioShapes (Almost-) Package The aim of the BioShapes quasi-package is to facilitate the generation of graphical objects resembling biological and chemical entities, enabling the construction of diagrams based on these objects. It currently includes

Dear Thomas, Unfortunately, I do not know if any packages implement this functionality. Though, it is a topic that interests me. Unlike the "classic discriminant", I prefer to work with the reduced polynomial. This "discriminant" is generalizable to a superset of Chebysev polynomials (which I called Cardano-polynomials). x^3 - 3*c*x - 2*d = 0 x^5 - 5*c*x^3 + 5*c^2*x - 2*d =

Hi, I am an astronomer and somewhat new to boostrap statistics. I understand the basic idea of bootstrap resampling, but am uncertain if it would be useful in my case or not. My problem consists of maximizing a likelihood function based on the velocities of a number of stars. My assumed distribution of velocities of these stars is:

CRAN (and crantastic) updates this week New packages ------------ * bisectr (0.0.2) Maintainer: Winston Chang Author(s): Winston Chang <winston at stdout.org> License: GPL-2 http://crantastic.org/packages/bisectr Tools to find bad commits with git bisect * CUMP (1.0) Maintainer: Xuan Liu Author(s): Xuan Liu <liuxuan at bu.edu> and Qiong Yang <qyang at bu.edu>

> complex(real = 0, imaginary = Inf) [1] 0+Infi > Inf*1i [1] NaN+Infi >> complex(real = 0, imaginary = Inf)/5 [1] NaN+Infi See the Note in ?complex for the explanation, I think. Duncan can correct if I'm wrong. -- Bert On Thu, Sep 5, 2024 at 3:20?PM Leo Mada <leo.mada at syonic.eu> wrote: > Dear Bert, > > These behave like real divisions/multiplications: >

atan(1i) -> 0 + Inf i complex(1/5) -> 0.2 + 0i atan(1i) -> (0 + Inf i) * (0.2 + 0i) -> 0*0.2 + 0*0i + Inf i * 0.2 + Inf i * 0i infinity times zero is undefined -> 0 + 0i + Inf i + NaN * i^2 -> 0 + 0i + Inf i - NaN -> NaN + Inf i I am not sure how complex arithmetic could arrive at another answer. I advise against messing with infinities... use atan2() if you don't

On 2024-09-05 4:23 p.m., Leo Mada via R-help wrote: > Dear R Users, > > Is this desired behaviour? > I presume it's a bug. > > atan(1i) > # 0+Infi > > tan(atan(1i)) > # 0+1i > > atan(1i) / 5 > # NaN+Infi There's no need to involve atan() and tan() in this: > (0+Inf*1i)/5 [1] NaN+Infi Why do you think this is a bug? Duncan Murdoch

Dear Bert, These behave like real divisions/multiplications: complex(re=Inf, im = Inf) * 5 # Inf+Infi complex(re=-Inf, im = Inf) * 5 # -Inf+Infi The real division / multiplication should be faster and also is well behaved. I was expecting R to do the real division/multiplication on a complex number. Which R actually does for these very particular cases; but not when only Im(x) is Inf.

If one makes the reasonable assumption that Pct is much larger than Cutoff, sorting Cutoff is the expensive part e.g O(nlog2(n) for Quicksort (n = length Cutoff). I believe looping is O(n^2). Jeff's approach using findInterval may be faster. Of course implementation details matter. -- Bert On Mon, Oct 16, 2023 at 4:41?AM Leonard Mada <leo.mada at syonic.eu> wrote: > > Dear

? Sat, 1 Jun 2024 16:16:23 +0000 Leo Mada via R-help <r-help at r-project.org> ?????: > When highlighting pdf-documents with Microsoft Edge, the bounding box > is sometimes misplaced, and quite ugly so. It also lacks the ability > to draw lines or arrows. > > On the other hand, I did not get used to Acrobat Reader: it usually > involves much more effort to add specific