similar to: Strategy for persisting row filter variables in pagination?

Hey guys, I just came across this oddity, not sure what to make of it yet, but I think it might be incorrect behavior. When doing a @inst.find(:all, :include => ["hometeam", "awayteam"] ...) hometeam and awayteam are two references from a belongs_to that is of the same model and of the same table. I will get a pgerror stating that "matches", which is

I am trying to use pagination with the order option. I am following examples I''ve seen all over the web, but I am getting an error. My code seems simple: def list @upload_pages, @uploads = paginate :uploads, :per_page => 20, :order => ''id'' end Yet I keep getting this error: ___________________________________________

hi everybody, i am new to rails.. plz clear my doubt... this is my question In my table(public_topics), i have 11 rows of data.. whenever i run the following view, it shows the entire rows in the current page.. and i have set the '':per_page'' option to ''2''.so it must show two data per page..but it shows all the rows in a single page..and this case continue

Hi, please help... In controller... def index @customers = Customer.find(:all) pagination code here.... end In index.html.erb Displayes list of customers and has pagination 1,2,3,4...etc. On clicking page 2, it will again run this(Customer.find(:all)) query in controller. So, there will be lack of performance. So, how to increase the mysql performace? Can i use the index as below or any

Hi Guys, I am trying to paginate the results from a search. When I use actual constants in the search conditions, it works fine: def query @k2_result_pages, @k2_results = paginate (:k2_results, :conditions => [''e_date >= ? AND e_date <= ?'', ''2006-07-12'', ''2006-08-12''],

Can I do any "fancy" conditionals when using the Pagination helper? The problem is that I want to be able to specify a conditional based on the criteria of a parent object. Here''s an example: Object A has_many Object B''s I want to paginate through 100 B''s but I *only* want it to return the ones who''s A.flag = true I poked around through the Wiki

I am currently caching a page that indexes blog entries. Paginate was used to break the entries up. Now when you click on next at the bottom of the page it is only reloading the first page. Im hoping, against odds, that someone here knows of a way to make paginate and cache play together. -- Posted via http://www.ruby-forum.com/.

Hello, I want to know how can I paginate a set of records. It seems there is no direct way of doing this, and I am not able to understand the documentation of paginate, so any pointers on how to do this will be much appreciated. To be specific what I want is that the records returned by user.recipes, the recipes of the particular user be paginated. My attempt to do this failed because

I''ve created a class method in my model called find_filtered. The intent is that I take various params that the user has submitted, and let the model build the query and return the AR collection, which is exactly what happens. However, now I''d like to paginate the recordset. Everything I''ve been able to find about pagination presumes that you have no pre-existing AR

Hi! I''ve got a list of project on the main page and if one of them is selected i render a partial using ajax with data of selected project. How to create links to next/previous project using pagination? -- Posted via http://www.ruby-forum.com/.

i''ve figured out how to use the next and previous links with the paginator class but now i''m trying to figure out how to display all the page numbers in between. looking through the rails api, i found paginator.each() but i''m not sure how to use it, or if that''s even what i am looking for. also, is there a way to limit the amount of pages like some sites

Hi, Why can''t I use a variable to specify the :per_page attribute when using the most basic form of pagination? (if I use a hardcode number, it runs) What did I do? Thx. My code: def list_orders page_size = 20 ... order_pages, @orders = paginate(:orders, :per_page => page_size) end My Errors: undefined method `>'' for false:FalseClass RAILS_ROOT:

I''m using will_paginate in a Post class method; [code]def self.list(page) paginate :per_page => 10, :page => page, :include => :user end[/code] I can happily use the method on my posts controller index action; [code] class PostsController < ApplicationController def index @posts = Post.list(params[:page]) respond_to do |format|

I am having this problem with pagination query in my controller class. I am using SQL server and following code to create pagination fails, complains about column name ''program_name'' (which is valid column/attribute of program) The error message is: DBI::DatabaseError: S0022 (207) [Microsoft][ODBC SQL Server Driver][SQL Server]Invalid column name

I have a little web app where we need to paginate collections of items. I''m trying to sort the collection and then pass it, sorted, to a Paginator, and still be able to paginate through the collection, across several pages, with the new sort order. The only thing I''m doing differently from the regular scaffolding approach is this: @order_pages = Paginator.new(self,

Is it possible to paginate rss feeds with FeedTools. The following code generates an error about constants. latest_feeds = FeedTools::Feed.open(''http://feeds.feedburner.com/Eribium'') @news_pages, @pages = paginate :latest_feeds, :per_page => 5 -- Posted via http://www.ruby-forum.com/.

Hello, maybe that I''m a stupid, but I don''t know how I can working with pagination. In all examples is written (for example) next: def user_list @user_pages, @users = paginate(:users, :order_by => ''name'') end So, it''s OK (as a scaffold) for all set of users. But I need a little other functionality. For example I need paginate only a little bit

I currently have a call to this action, which I''d like to paginate: def get_words @catid = params[:category] @words = Category.find(@catid).words render :partial => "word_display", :collection => @words end As you can see, a word_display partial is rendered for each word. If I add the pagination call (getting the links object), how can I then get

I''m struggling with the issue of pagination and many to many relationships. I have products and categories (a many to many relationship.) When I go to a category page, I wish to load all products associated with that category and have pagination of the products. @category_products = @category.products gives me all the products associated with the category however, when I try to

Hi - I''ve just started working with Rails, having come from a Cold Fusion background. I''m curious how best to deal with a huge result set. For example, I''m building an app that contains users. I''ve used scaffolding to setup my initial pages for CRUD operations on users. All that is great. The problem is, I''m going to end up with 1000+ users in