similar to: Code editor for writing R code

Displaying 20 results from an estimated 6000 matches similar to: "Code editor for writing R code"

2023 Nov 29
2
Code editor for writing R code
Bert, Posit (formerly RStudio) has moved from RMarkdown to Quarto. They still support RMarkdown but major new features will be in Quarto. For new users a better choice would be Quarto. See https://quarto.org/docs/faq/rmarkdown.html Secondly, the OP stated he was using the VS-Code IDE, so there is no reason to point him to the Posit/RStudio IDE for this functionality which VS-Code supports very
2023 Nov 29
1
Code editor for writing R code
I believe RMarkdown can use and render latex comments. RStudio/Posix provides ide extensions (e.g. R Notebooks) that seem to do what you want, but I have no experience with them. As Ben suggested, there are likely others, depending on exactly what you want to do. -- Bert On Wed, Nov 29, 2023 at 7:58?AM Christofer Bogaso <bogaso.christofer at gmail.com> wrote: > > Hi, > >
2023 Nov 29
1
Code editor for writing R code
Presumably there's nothing stopping you *writing* LaTeX in comments -- do you want a code editor that will render and display the LaTeX as you write? (Or am I misunderstanding something?) Does anyone do classic literate programming *sensu* Knuth any more? https://rpubs.com/bbolker/3153 https://cran.r-project.org/web/packages/noweb/vignettes/noweb.pdf On 2023-11-29 10:57 a.m.,
2023 Nov 29
4
Code editor for writing R code
Hi, Currently I use VS-Code to write codes in R. While it is very good, it does not allow me to write Latex expressions in comments, which I am willing to have to write corresponding mathematical expressions as comments in my code files. Does there exist any Code editor for R, that allows me to write Latex in comments? Any information will be appreciated. Thanks,
2018 Mar 04
0
Change Function based on ifelse() condtion
The reason that it works for Apply_MC=TRUE is that in that case you call mclapply(X,FUN,...) and the mclapply() function strips off the mc.cores argument from the "..." list before calling FUN, so FUN is being called with zero arguments, exactly as it is declared. A quick workaround is to change the line Lapply_me(as.list(1:4), function(xx) { to Lapply_me(as.list(1:4),
2018 Mar 04
0
Change Function based on ifelse() condtion
That's fine. The issue is how you called Lapply_me(). What did you pass as the argument to FUN? And if you did not pass anything that how is FUN declared? You have not shown that in your email. On Sun, Mar 4, 2018 at 7:11 PM, Christofer Bogaso < bogaso.christofer at gmail.com> wrote: > My modified function looks below : > > Lapply_me = function(X = X, FUN = FUN, Apply_MC =
2018 Mar 04
3
Change Function based on ifelse() condtion
Below is my full implementation (tried to make it simple as for demonstration) Lapply_me = function(X = X, FUN = FUN, Apply_MC = FALSE, ...) { if (Apply_MC) { return(mclapply(X, FUN, ...)) } else { if (any(names(list(...)) == 'mc.cores')) { myList = list(...)[!names(list(...)) %in% 'mc.cores'] } return(lapply(X, FUN, myList)) } } Lapply_me(as.list(1:4), function(xx) { if (xx ==
2018 Mar 04
2
Change Function based on ifelse() condtion
My modified function looks below : Lapply_me = function(X = X, FUN = FUN, Apply_MC = FALSE, ...) { if (Apply_MC) { return(mclapply(X, FUN, ...)) } else { if (any(names(list(...)) == 'mc.cores')) { myList = list(...)[!names(list(...)) %in% 'mc.cores'] } return(lapply(X, FUN, myList)) } } Here, I am not passing ... anymore rather passing myList On Sun, Mar 4, 2018 at 10:37 PM,
2018 Mar 04
0
Change Function based on ifelse() condtion
Hi Christofer, Before you made the change that I suggested, your program was stopping at the statement: list(...) = list(..) .etc This means that it never tried to execute the statement: return(lapply(X,FUN,...)) Now that you have made the change, it gets past the first statement and tries to execute the statement: return(lapply(X,FUN,...)). That attempt is generating the error message because
2018 Mar 04
2
Change Function based on ifelse() condtion
@Eric - with this approach I am getting below error : Error in FUN(X[[i]], ...) : unused argument (list()) On Sun, Mar 4, 2018 at 10:18 PM, Eric Berger <ericjberger at gmail.com> wrote: > Hi Christofer, > You cannot assign to list(...). You can do the following > > myList <- list(...)[!names(list(...)) %in% 'mc.cores'] > > HTH, > Eric > > On Sun, Mar
2017 Aug 10
0
Zoo rolling window with increasing window size
Replace "sum" with your custom function's name. I don't see any reason why that wouldn't work, and the problem with my solution is not clear in your response. r <- rollapplyr(x, seq_along(x), yourCustomFunctionGoesHere) On Thu, Aug 10, 2017 at 1:39 PM, Christofer Bogaso <bogaso.christofer at gmail.com> wrote: > Hi Joshua, thanks for your prompt reply. However
2018 Mar 04
0
Change Function based on ifelse() condtion
Hi Christofer, You cannot assign to list(...). You can do the following myList <- list(...)[!names(list(...)) %in% 'mc.cores'] HTH, Eric On Sun, Mar 4, 2018 at 6:38 PM, Christofer Bogaso < bogaso.christofer at gmail.com> wrote: > Hi, > > As an example, I want to create below kind of custom Function which > either be mclapply pr lapply > > Lapply_me =
2018 Jun 01
1
Unable to take correct Web-snapshot
Thanks for that information. However how can I use R to directly get data from that API? On Fri, Jun 1, 2018 at 8:36 PM Martin M?ller Skarbiniks Pedersen < traxplayer at gmail.com> wrote: > On 1 June 2018 at 15:08, Christofer Bogaso <bogaso.christofer at gmail.com> > wrote: > > Hi again, > > > > I use the *webshot* package to take snapshot from Webpage.
2017 Oct 09
1
load() failed to load .Rdata file in AWS-Ububtu
Hi Eric, thanks for your further pointer. I have put a line with load() function just as an illustration of a bigger project of mine, which appears failing due to load() function issue. If I comment out that line my shiny app is working correctly locally and globally. otherwise, locally my shiny app is working but not with AWS. On Mon, Oct 9, 2017 at 12:37 PM, Eric Berger <ericjberger at
2017 Aug 10
3
Zoo rolling window with increasing window size
Hi Joshua, thanks for your prompt reply. However as I said, sum() function I used here just for demonstrating the problem, I have other custom function to implement, not necessarily sum() I am looking for a generic solution for above problem. Any better idea? Thanks, On Fri, Aug 11, 2017 at 12:04 AM, Joshua Ulrich <josh.m.ulrich at gmail.com> wrote: > Use a `width` of integer index
2017 Aug 03
2
Extracting numeric part from a string
... Or if you just want to stick with basic regex's without extra packages: > x <- "\"cm_ffm\":\"563.77\"" > sub("[^[:digit:]]*([[:digit:]]*.?[[:digit:]]*).*","\\1",x) [1] "563.77" Cheers, Bert On Wed, Aug 2, 2017 at 5:16 PM, Ismail SEZEN <sezenismail at gmail.com> wrote: > >> On 3 Aug 2017, at 02:59,
2017 Oct 09
0
load() failed to load .Rdata file in AWS-Ububtu
Hi Christofer, The shiny code you have written does not depend on loading the Dat.RData file. I commented out that line and ran your shiny app on my machine and it works fine. What happens if you comment out (or remove) the line load("/home/ubuntu/Dat.RData) Does your shiny app still fail? If so, then your problem is quite basic with your AWS setup. Try to work through a simple
2017 Aug 03
0
Extracting numeric part from a string
> On Aug 2, 2017, at 6:59 PM, Christofer Bogaso <bogaso.christofer at gmail.com> wrote: > > Hi again, > > I am struggling to extract the number part from below string : > > "\"cm_ffm\":\"563.77\"" > > Basically, I need to extract 563.77 from above. The underlying number > can be a whole number, and there could be comma separator
2017 Aug 03
0
Extracting numeric part from a string
> On 3 Aug 2017, at 02:59, Christofer Bogaso <bogaso.christofer at gmail.com> wrote: > > Hi again, > > I am struggling to extract the number part from below string : > > "\"cm_ffm\":\"563.77\"" > > Basically, I need to extract 563.77 from above. The underlying number > can be a whole number, and there could be comma separator as
2018 Apr 24
0
Rolling window difference for zoo time series
Zoo_TS/lag(Zoo_TS) - 1 On Tue, Apr 24, 2018 at 9:29 PM, Christofer Bogaso < bogaso.christofer at gmail.com> wrote: > Hi, > > I have a 'zoo' time series as below : > > Zoo_TS = zoo(5:1, as.Date(Sys.time())+0:4) > > Now I want to calculate First order difference of order 1, rolling > window basis i.e. > > (Zoo_TS[2] - Zoo_TS[1] ) / Zoo_TS[1] >