similar to: ggplot adjust two y-axis

Hi Sibylle, For that kind of data with two different scales, I generally use two graphs that I name gg1 and gg2 and join them using gridExtra::grid.arrange(gg1, gg2). This way, the red part of your graph is easier to interpret. Have a nice day, Charles-?douard -----Message d'origine----- De?: R-help <r-help-bounces at r-project.org> De la part de sibylle.stoeckli at gmx.ch Envoy??:

Hi, I don't know the axis mecanism well enough in ggplot but using the original barplot function you can add an axis on the right using the axis function. Here is an example: test <- as.table(matrix(c(2,10,3,11), 2,2)) barplot(test, beside = TRUE, col = scales::brewer_pal(palette = 1)(2)) axis(4, at = c(0, 5, 10), labels = c(0,50,100)) -----Message d'origine----- De?:

Dear Charles-Edouard Thanks a lot. Yes indeed barplot sounds excellent. Unfortunately, the scale of the smaller axis is fixed, even If I am able to draw to axes. The idea is to expand the scale to the scale to the second axis for comparison. F1 <- as.table(matrix(c(50,11,6,17,16,3,1,2237,611,403,240,280,0,0), 2,7)) barplot(F1, beside = TRUE, col = c("blue", "grey"))

Hi, Just find a scaling factor that would make the two sets of data comparable. Here I divided the second row by 5 and did the same for the second axis. Charles-?douard F1 <- as.table(matrix(c(50,11,6,17,16,3,1,2237,611,403,240,280,0,0), 2,7)) barplot(F1, beside = TRUE, col = c("blue", "grey")) axis(2, at=c(0,10,20,30,40,50,60, labels=c(0,10,20,30,40,50,60))) axis(4, at =

Dear friends - I'm having troubles with nlme fitting a simplified model as shown below eliciting the error Error in chol.default((value + t(value))/2) : ? the leading minor of order 1 is not positive definite - I have seen the threads on this error but it didn't help me solve the problem. The model runs well in brms and identifies the used parameters even with fixed effects for TRT?

Dear John Kane Dear R community Here my working example 1. Example that is working with legend=?top?. However, as mentioned, the legend is in the middle of the top axis. mylist<-list(p1, p2) dev.new(width=28, height=18) fig1<- ggarrange(plotlist=mylist, common.legend = TRUE, legend="top", labels = c("(A)", "(B)"), font.label = list(size = 18, color =

I'm sorry but that is not a working example. A working example needs to create the plots being used. For example, stealing some code from https://rpkgs.datanovia.com/ggpubr/reference/ggarrange.html #================================================================= data <https://rdrr.io/r/utils/data.html>("ToothGrowth")df <- ToothGrowthdf$dose <- as.factor

Could you supply us with a MWE (minimal working example)of what you have so far? Thanks. On Mon, 5 Feb 2024 at 05:00, SIBYLLE ST?CKLI via R-help < r-help at r-project.org> wrote: > Dear R community > > It is possible to adjust the legend in combined ggplots using ggarrange > with > be positions top, bottom, left and right. > My question: Is there a function to change the

Dear All, I´m using the following code: all1<-gg2[[1]][[1]]; for(i in 1:48){ all1 <- rbind(all1,gg2[[i]][[1]]) } to create a new matrix that contains all the matrices in a list called gg2. gg2 is a list that looks like >> gg2 [[1]] [[1]][[1]] <matrix one> [[2]] [[2]][[1]] <matrix two> . . . [[48]] [[48]][[1]] <matrix 48> Is there a faster way to do the rbind?

I am attempting to run a glm with a binomial model to analyze proportion data. I have been following Crawley's book closely and am wondering if there is an accepted standard for how much is too much overdispersion? (e.g. change in AIC has an accepted standard of 2). In the example, he fits several models, binomial and quasibinomial and then accepts the quasibinomial. The output for residual

Dear community Dear Ivan Thanks a lot. The code works now. Solution: direct and full path to the .tif files. I confused back and forward slash #first import all files in a single folder as a list rastlist <- list.files(path = "C:/Users/Sibylle St?ckli/Desktop/NCCS_Impacts_Lot2_2022/InVEST/Species_Input/valpar_bee_presence", pattern='.tif$', all.files= T, full.names= T) At

Dear Ivan Thanks a lot. I tried now to provide the full path. However probably the "?" in the path produces the error, would that be possible? > #first import all files in a single folder as a list > rastlist <- list.files(path = "C:\Users\Sibylle St?ckli\Desktop\NCCS_Impacts_Lot2_2022\InVEST\Species_Input\valpar_bee_presence", pattern='.tif$', all.files=

Hi, I have the follow ggplot2 code I am running: ggplot(data=bb.res.math,aes(x=factor(id.bb),y=bb.math.comb,fill=BB)) + geom_bar() + facet_grid(BB~.) + scale_fill_brewer(pal="Set1") + ylab("Average Student Residual (Math)") + xlab("Student ID") The number of unique id.bb is 2207 and so my X-axis has a couple of thousands, indistinguishable tick marks that correspond

Many thanks Ivan Use is.na() on getValues() outputs, combine the two masks using the | operator to get a mask of values that are missing in either raster, then negate the mask to choose the non-missing values: all.equal(getValues(r1)[!mask], getValues(r2)[!mask]) --> what do you mean by use is.na() in getValues(). So I need to call getValues a second time? I suppose you mean to first

Dear R users aim Barplot of insect trap catches (y variable trapcatch) at one specific station (variable FiBL_Hecke) from week 1-52 ( x variable week). It works well using the function tapply (sum trapcatch per week, males and females not separated), however, I intend to separate the y variable trapcatch in males and females (variable m_w: m and w) problem I used the function "add" to

Dear Ivan Thanks a lot for this very nice example. Is it true that all.equal just compares y values? Based on this help here I think so and the value I got is the difference for the y-values. https://www.statology.org/all-equal-function-r/ However, here I see x and y testing? https://www.rdocumentation.org/packages/base/versions/3.6.2/topics/all.equal I am actually interested in the x values

? Thu, 18 Apr 2024 11:08:33 +0200 SIBYLLE ST?CKLI via R-help <r-help at r-project.org> ?????: > > #to check the index numbers of all imported raster list elements > > allrasters > list() > > > > #call single raster element > > allrasters[[1]] > Error in allrasters[[1]] : subscript out of bounds `allrasters` is an empty list, so it doesn't have a

-------- Original-Nachricht -------- Datum: Wed, 27 Oct 2010 15:03:48 +0200 Von: "Sibylle St?ckli" <sibylle.stoeckli at gmx.ch> An: Rhelp <r-help at r-project.org> Betreff: as.list Dear R-users sorry, here Rcode included (attachment has been removed) I would like to read a txt file as list, to select rows and columns, and to create barplots. (1) selection of parameter

Dear R-users I applied vegan's varpart function to partition the effects of explanatory matrices. Adj. R square for the unique fraction [a] is 0.25. Does anyone know why the decomposition by hand using rda gives me a different result for [a] (constrained proportion is 0.32)? I used cbind() for the conditional fractions, but it should be similar to condition()? Thanks very much

"Is it true that all.equal just compares y values?" The following may be a bit more than you may have wanted, but I hope it is nevertheless useful. The first place you should go to for questions like this is the Help system, not here, i.e. ?all.equal When you do this, you will find that all.equal() is a so-called S3 generic function, which, among other things, means that it works