similar to: How to paginate a find_by_sql query?

Hello everyone, I forced to use @user = User.find_by_sql sql_query in a particular situation in my project. Now I want to paginate the records. How can I paginate the records? Please help me. Thanks in advance -- Posted via http://www.ruby-forum.com/.

Does anybody know what the correct way to cache results from Net::LDAP bind_as? I''ve been struggling for about a day now and I know it''s something really easy. But when ever I do something like this - def self.login(username, password) begin ldap = Net::LDAP.new ldap.host = "192.168.1.16" ldap.port = 389 result = ldap.bind_as(

Hello, I have 2 tables table colors : +----------------------+ | id | user_id | name | +----------------------+ | 1 | 1 | test1 | | 2 | 2 | test2 | | 3 | 3 | test3 | +----------------------+ table users : +----------------------+ | id | enabled | name | +----------------------+ | 1 | 1 | bob | | 2 | 1

hi everybody, i am new to rails.. plz clear my doubt... this is my question In my table(public_topics), i have 11 rows of data.. whenever i run the following view, it shows the entire rows in the current page.. and i have set the '':per_page'' option to ''2''.so it must show two data per page..but it shows all the rows in a single page..and this case continue

Hi, I was trying to use the :select parameter to select a calculated row, but it appears that the parameter is not picked up by the paginate method. I want to add the following to the select statement: timediff(now(), created_on) as age So I tried: @story_pages, @stories = paginate :stories, {:per_page => 10, :include => ''user'', :select =>

How to make it work with paginator (kaminari)? MySQL and full text search: Words (id, word) @words = Word.find_by_sql(["SELECT id, word, MATCH (word) AGAINST (?) AS Score FROM words WHERE MATCH (word) AGAINST (?) ORDER BY Score Desc, word!=?", params[:search],params[:search],params[:search]]) I can''t add .page(params[:page]).per(5) to the end of "find_by_sql()" so

Hi all, Is there a way to create pagination with a complex SQL, more complex than the :conditions option will support? I have two databases, houses and images. Houses has_many images, and each Image belongs_to house. I''m creating a search engine for the house records and I''d like to be able to filter out all the houses without any associated images. So far I''m

Hi all, I have a controller method that, given some parameters, constructs a big sql query and passes it to find_by_sql (with pagination). The point is that I can''t wonder how to write a functional test for this method. Has anyone passed already through this? -- Posted via http://www.ruby-forum.com/. --~--~---------~--~----~------------~-------~--~----~ You received this message

Hello, AV::paginate query first by a count, how access this value in the controller or view ? Why ? Because I''ll like to display the total number or records found w/o doing another expenssive Count. Thanks,

Hi Everybody, I am a newbie in this list so please forgive me if this is a lengthy message. Currently I am working on a project at my work place that includes viewing some oracle tables(I do not have control over to rewrite the tables) and searching the tables based on a given criteria with Rails. Up untill now everything was working great. The database consists of a lot of tables but I was

Why would I get an undefined method `find_by_sql'' for #Example: 0x981a4e4> for error when trying to use the find_by_sql method in my model? def init_dictionaries tables = find_by_sql( "SHOW TABLES FROM thesaurus" ) @@tables = tables.collect{ |t| t.Tables_in_thesaurus } end -- You received this message because you are subscribed to the Google Groups "Ruby

Hello all. I am trying to do the equivalent of: @componentlogs = Componentlog.find(:all, :conditions => [ "cl_compname like ?", @criteria ], :offset => offset, :limit => items_per_page, :order => "cl_spr DESC" ) in a find_by_sql statement. I cannot use the build in because the adaptor isn''t quite right (OCI8) When I use it I get the following error

Ok now that I have find_by_sql love working for my "Top 10 List" I want to make them a bit more DRY. Tis is what I have so far: Model: def self.topfish find_by_sql["select species.name, length,species.multiplier*length as score,caught_on from entries join species on species_id = species.id where species_id = ? order by score DESC LIMIT 10", species]

I tried to use named parameters in my SQL query , using find_by_sql Order.find_by_sql ([select * from orders where amount > ? and quantity > ?", [ @amount, @quantity ] works;.. but Order.find_by_sql ([select * from orders where amount > :amount and quantity > :quantity ", [ :amount => @amt, :quantity => @qty ] is not working a I wrong or should I use a plain select

hey, i have users who are in groups, and i have a search form, where i can search on group, user lastname, and user firstname. All this is also with pagination. these are my models class User < ActiveRecord::Base has_and_belongs_to_many :groups end class Group < ActiveRecord::Base has_and_belongs_to_many :users end in my controller i do this THIS works (but in need pagination) @users2

I have run into a very strange problem discovered through the use of the acts_as_taggable plugin, but related to quoting/sanitizing the interpolated list in a find_by_sql. Apologies for the length, but I wanted to be complete. ;-) The method from acts_as_taggable.rb is: def find_tagged_with(list) find_by_sql(["SELECT #{table_name}.* FROM #{table_name}, tags,

I was trying to do SUM based mySQL query simliar to the following: SELECT SUM(updated_on - created_on) AS total from signups If I were to run this command in the mySQL console I would get a result. However, if I were to run it using the following command in Rails: Signup.find_by_sql("SELECT SUM(updated_on - created_on) AS total from signups") The query that is written to the log is:

When you use find, you can include related objects with include so that both objects get instantiated in the results, e.g. Foo.find(:all, :include => :bar). But when you use find_by_sql, is there a way to do this? You could definitely write the find_by_sql SQL to join Foo and Bar tables: Foo.find_by_sql("SELECT foo.*, bar.* from foo, bar where foo.bar_id = bar.id") But is there a

Deniz wrote: > Hi Everybody, > I am a newbie in this list so please forgive me if this is a lengthy > message. > Currently I am working on a project at my work place that includes > viewing some oracle tables(I do not have control over to rewrite the > tables) and searching the tables based on a given criteria with Rails. > Up untill now everything was working great. The

Every example and tutorial I can find shows how to create and paginate a list of rows returned from a table. But I''m trying to write an interface on top of an existing table with 4million rows. So I need to jump right to the lesson on searching my data. That, I can''t find. Can somebody tell me the techniques available for pruning down my list a bit? I found a