similar to: Bug in print for data frames?

On 25/10/2023 2:18 a.m., Christian Asseburg wrote: > Hi! I came across this unexpected behaviour in R. First I thought it was a bug in the assignment operator <- but now I think it's maybe a bug in the way data frames are being printed. What do you think? > > Using R 4.3.1: > >> x <- data.frame(A = 1, B = 2, C = 3) >> y <- data.frame(A = 1) >> x >

Hola, Estoy intentando averiguar cómo contar el número de categorías situadas después de ciertos valores. Por ejemplo, en el siguiente vector: x <- c(3, "A", "B", 5, "A", 4, 5, "A", "A", 3) el resultado que quisiera obtener es: Valor -> Resultado 3 -> 1 A y 1 B 4 -> 0 A y 0 B 5 -> 3 A y 0 B ¿Alguien tiene alguna

Hmmm... typos and thinkos ? Maybe: mean_narm<- function(x) { m <- mean(x, na.rm = T) if (is.nan (m)) NA else m } -- Bert On Mon, Sep 16, 2024 at 4:40?PM CALUM POLWART <polc1410 at gmail.com> wrote: > > Rui's solution is good. > > Bert's suggestion is also good! > > For Berts suggestion you'd make the list bit > > list(mean = mean_narm) >

I am trying to use the aggregate function to run a function, catsbydat2, that produces the mean, minimum, maximum, and number of observations of the values in a dataframe, inJan2Test, by levels of the dataframe variable MyDay. The output should be in the form of a dataframe. #my code: # This function should process a data frame and return a data frame # containing the mean, minimum, maximum, and

> On Jun 8, 2018, at 11:52 AM, Hadley Wickham <h.wickham at gmail.com> wrote: > > On Fri, Jun 8, 2018 at 11:38 AM, Berry, Charles <ccberry at ucsd.edu> wrote: >> >> >>> On Jun 8, 2018, at 10:37 AM, Herv? Pag?s <hpages at fredhutch.org> wrote: >>> >>> Also the TRUEs cause problems if some dimensions are 0: >>>

ALCON I'm trying to figure out how to rename groups in a data frame after groups by selected variabels. I am using the dplyr library to group my data by 3 variables as follows # group by lat (StoreX)/long (StoreY) priceStore <- LapTopSales[,c(4,5,15,16)] priceStore <- priceStore[complete.cases(priceStore), ] # keep only non NA records priceStore_Grps <- priceStore %>%

Arnaud, Short answer may be that the tibble data structure will not be supporting row names and you may want to simply save those names in an additional column or externally. My first thought was to simply save the names you need and then put them back on the tibble. In your code, something like this: save.names <- names(my.ret.lst) result.tib <- as_tibble_col(unlist(my.ret.lst),

I work with a list of crypto assets daily closing prices in a xts class. Here is a limited example: asset.xts.lst <- list(BTCUSDT = structure(c(26759.63, 26862, 26852.48, 27154.15, 27973.45), dim = c(5L, 1L), index = structure(c(1697068800, 1697155200, 1697241600, 1697328000, 1697414400), tzone = "UTC", tclass = "Date"), class = c("xts", "zoo")), ETHUSDT

Hello, See if this is it: priceStore_Grps$StoreID <- paste("Store", seq_len(nrow(priceStore_Grps)), sep = "_") Hope this helps, Rui Barradas On 5/26/2018 2:03 PM, Jeff Reichman wrote: > ALCON > > > > I'm trying to figure out how to rename groups in a data frame after groups > by selected variabels. I am using the dplyr library to group my

Hum... This boils down to > as.numeric("1.23e") [1] 1.23 > as.numeric("1.23e-") [1] 1.23 > as.numeric("1.23e+") [1] 1.23 which in turn comes from this code in src/main/util.c (function R_strtod) if (*p == 'e' || *p == 'E') { int expsign = 1; switch(*++p) { case '-': expsign = -1; case

> On Jun 8, 2018, at 10:37 AM, Herv? Pag?s <hpages at fredhutch.org> wrote: > > Also the TRUEs cause problems if some dimensions are 0: > > > matrix(raw(0), nrow=5, ncol=0)[1:3 , TRUE] > Error in matrix(raw(0), nrow = 5, ncol = 0)[1:3, TRUE] : > (subscript) logical subscript too long OK. But this is easy enough to handle. > > H. > > On

I try tu use mob() with my data.frame ('data.frame': 288 obs. of 81 variables; factors, numerics and ordered factors) My response is a binary variable and I should use for modelling a logistic regression (family=binomial). I read in the "MOB" Vignette that I could use a formula like this if I would like to have only partitioning variables apart from the response.

Dear all, I have this set of data. I would like to sum the EnergykWh according date sequences. > head(dt1,20) StationName date time EnergykWh 1 PALO ALTO CA / CAMBRIDGE #1 1/14/2016 12:09 4.680496 2 PALO ALTO CA / CAMBRIDGE #1 1/14/2016 19:50 6.272414 3 PALO ALTO CA / CAMBRIDGE #1 1/14/2016 20:22 1.032782 4 PALO ALTO CA / CAMBRIDGE #1 1/15/2016 8:25 11.004884 5

Thanks for the feedback Jeff. Before I pursue a bug report, let me give a full example: ###### begin console output R version 3.4.1 (2017-06-30) -- "Single Candle" Copyright (C) 2017 The R Foundation for Statistical Computing Platform: i386-w64-mingw32/i386 (32-bit) R is free software and comes with ABSOLUTELY NO WARRANTY. You are welcome to redistribute it under certain conditions.

Hi Folks, I have just started using dplyr and could use some help getting unstuck. It could well be that dplyr is not the package to be using, but let me just pose the question and seek your advice. Here is my basic data frame. head(h) subject ageGrp ear hearingGrp sex freq L2 Ldp Phidp NF SNR 1 HALAF032 A L A F 2 0 -23.54459 55.56005 -43.08282

Hi, I am using aggregate() to add up groups of data according to year and month. It seems that the function aggregate() automatically sorts the levels of factors of the grouping elements, even if the order of the levels of factors is supplied. I am wondering if this is a bug, or if I missed something important. Below is an example that shows what I mean. Does anyone know if this is just the way

Hello there. Happy new year for everyone! I need help with a table. This table contains 300 rows and 192 columns. Being the first column the ID of my samples that can have several observations. I need to generate e NEW table that contains a single ID with the sum of the observations by columns: For example: Example ID?? A??? B? ? C? ? D? ? E? ? F? ? G.... 191 columns a1?? 0??? 0??? 0? ? 1???

> On Aug 14, 2017, at 8:37 AM, Szumiloski, John <John.Szumiloski at bms.com> wrote: > > Thanks for the feedback Jeff. Before I pursue a bug report, let me give a full example: > > ###### begin console output > > R version 3.4.1 (2017-06-30) -- "Single Candle" > Copyright (C) 2017 The R Foundation for Statistical Computing > Platform:

This sounds an awful lot like a bug. Read the Posting Guide to know what to do about bugs. And delaying making the reprex is _always_ a bad idea. -- Sent from my phone. Please excuse my brevity. On August 14, 2017 7:26:32 AM PDT, "Szumiloski, John" <John.Szumiloski at bms.com> wrote: >UseRs, > >When doing some data manipulations using the tidyverse, I am repeatedly

Hello, Sorry, but I think my first answer is wrong. You probably want something along the lines of sp <- split(priceStore_Grps, priceStore_Grps$StorePC) res <- lapply(seq_along(sp), function(i){ sp[[i]]$StoreID <- paste("Store", i, sep = "_") sp[[i]] }) res <- do.call(rbind, res) row.names(res) <- NULL Hope this helps, Rui Barradas On 5/26/2018