similar to: Adding a numeric class to a data.frame

Hi This question is far less simple than the title suggests, please read carefully, thanks. I have 2 sets of data, both read into R >data1<-read.table ("1.txt", header=T, sep="\t") >data2<-read.table ("2.txt", header=T, sep="\t") >data1 Taxon stage1 stage2 stage3 stage4 T1 0 0 1 1 T2 0

Hi experts. I have a tibble? with a column containing a nested list (<list<list<double>>>? data type to be specific). Looks something like the following (but in R/Arrow? format): ID Nestedvals 001 [[1]](1,0.1)[[2]](2,0.2)[[3]](3,0.3)[[4]](4,0.4)[[5]](5,0.5) 002 [[1]](1,0.1)[[2]](2,0.2)[[3]](3,0.3)[[4]](4,0.4) 003 [[1]](1,0.1)[[2]](2,0.2)[[3]](3,0.3) 004 [[1]](1,0.1)[[2]](2,0.2)

Muchas gracias Carlos. Pero eso haría que el signo se muestre tal como se deba mostrar , es decir: ? Manuel El 9 de octubre de 2017, 1:46, Carlos Ortega <cof en qualityexcellence.es> escribió: > Puedes incluir estos signos en una columna nueva antes de cada una de las > columnas numéricas. > Que el data.frame tuviera esta pinta... > > Signo_1, Col_1, Signo_2, Col_2,

I need to make a category browser that would allow nested categories. Is there any receipe on that? Currently, I use the :onchange event from one of the form element to update the first select (out of 4-5 selects), but I dont know how to elegantly reset all the child selects if I change the value from the first. All the categories are fetched from the DB and I would like a

Muchas gracias Jesús, Por lo que veo hay que hacer una columna diferente para los símbolos, tal como sugiere Carlos. No hay forma de ubicarlos en el mismo string, acompañando al número? Manuel El 9 de octubre de 2017, 8:52, Jesús Para Fernández < j.para.fernandez en hotmail.com> escribió: > Con > > print("\u2265") > > > lo consigues. > > Aqui tienes

Estimados miembros de la lista, Cómo se puede incluir. por ejemplo, el símbolo de menor o igual en un data.frame para luego hacer un cuadro (table con kable in rmarkadown)? columna1 <- c("a", "b", "c") columna2 <- c(<= 0.3, 0.5, 0.8) columna3 <- c(>=0.5, 0.6, 0.9) cuadro <- data.frame(columna1, columna2, columna3) kable(cuadro) Manuel --

I have searched help topics but don't know exactly what to search for. Need to use my_num to find any matching STREPs in my_df my_num <- c("101","102","103","104","105","107","108","112","113","114","115") ## "my_df" has 8,000 different STREPS in it. ## I have a

In trying to use as.Date(), I've come across the conversion of POSIXlt to POSIXct when a POSIXlt variable is included in a data frame: my_POSIX <- strptime(c("11-09-2006", "11-10-2006", "11-11-2006", "11-12-2006", "11-13-2006"), "%m-%d-%Y") str(my_POSIX) my_Date <- as.Date(my_POSIX) str(my_Date) data <- format(my_Date)

Hi folks, I'm trying to figure out how to get summarized data based on multiple columns. However, instead of giving summaries for every combination of categorical columns, I want it for each value of each categorical column regardless of the other columns. I could do this with three different commands, but i'm wondering if there's a more elegant way that I'm missing. Thanks!

Dear R users, I have got the following data frame, called my_df: gender day_birth month_birth year_birth labour 1 F 22 10 2001 1 2 M 29 10 2001 2 3 M 1 11 2001 1 4 F 3 11

I am sorry if this is a faq or tutorial somewhere, but I am unable to solve this one. What I am looking for is a count of how many different categories(numbers in this case) that appears for a given factor. Example: > l <- c("Yes", "No", "Perhaps") > x <- factor( sample(l, 10, replace=T), levels=l ) > m <- c(1:5) > y <- factor( sample(m, 10,

Hi All, I want to join a table (Dataset) that is created in R with a table that is in oracle database. Can some one help me in accomplishing this task in R? Example Code: library(RODBC) DB_CONNECT <- odbcConnect("DSN_NAME") TABLE_JOIN <- sqlQuery(DB_CONNECT, "SELECT * FROM DB_TABLE WHERE COL_1 NOT IN (SELECT COL_1 FROM DATA_SET_R) ") Regards, Madana -- View this

Hi Folks, I'm trying to find a way to remove all terms in a formula that contain a particular interaction. For example, in the formula below, I'd like to remove all terms that contain the b:c interaction. > attributes(terms( ~ a*b*c*d))$term.labels [1] "a" "b" "c" "d" "a:b" "a:c" [7]

Dear all, I have some additionale question concerning the spgrass6 package. * When you set a region in GRASS, does the readGRASS6 function in R only load data contained in the zoomed region or the whole map ? * When you have a MASK map in grass, does the readGRASS6 function in R only load data contained inside the MASK area ? Could this be the problem ? Thanks, Jessica

I have a question about how to filter the data frame: Suppose my data frame has variables like gender, age,... How to get a subset of the data frame, with only female (or male) and/or age > 50...? What is the typical syntax? I tried several condition expressions, but none of them worked... Thanks a lot! -- View this message in context:

Hi, I'd like to graph three lines on ggplot2 and I intend the lines to be "solid", "dashed", and "dotted". The legend names are "name_b", "name_a", "name_c". I'd like to legend to present in the order: the "name_b" at the top, and "name_c" at the bottom. As a consequence, the legend is indeed in the order:

Hi R list: How can I "repeat" a data frame n times (with n>1000), and obtain a new data frame where all the n data frames are binded by rows? Thank you for your help Kenneth -- Using Opera's revolutionary e-mail client: http://www.opera.com/mail/

Hello, I'm trying to modify my r-script to use RODBC instead of DBI/RMySQL (no more ready-to-use package for windows). I would like to copy a data.frame of 44 columns to a table of 45 columns (the 45th is an autoincremental column). With the following commands, colnames(df)<- a vector with the names of the 44 columns

"Does that help?" No. I am not your private consultant. You need to reply to the list, which I have cc'ed here, not just me. I am still somewhat confused by your specifications, but others may not be. Part of my confusion stems from your failure to provide a reproducible example (see e.g. the posting guide linked below). For example, I cannot tell from your text whether the Abc

r-help Forum I'm using the dplyr:: summarize_all(funs(sum)) function and am receiving a warning message that the `funs()` is deprecated as of dplyr 0.8.0. Ok what should I be using to summarize all columns by sum? Jeff [[alternative HTML version deleted]]