similar to: range() for Date and POSIXct could respect `finite = TRUE`

A tiny nit-pick: Seems to me that end date = NA would mean the event has not yet ended, whilst Inf would mean that the event is known to never terminate, ie: an eternal fact, or physical law. On Fri, Apr 28, 2023 at 10:12?AM Davis Vaughan via R-devel < r-devel at r-project.org> wrote: > Hi all, > > I noticed that `range.default()` has a nice `finite = TRUE` argument, > but it

Hi All, I think there may be some possible confusion about what allowsInf would be reporting (or maybe its just me :) ) if we did this. Consider a class "myclass", S3, for starters, with setMethod("allowsInf", "myclass", function(obj) FALSE) Then, what would myclassthing <- structure(1.5, class = "mything") myclassthing[1] <- Inf do. Assumely it

Hello, I faced some difficulties using time series objects. ---------------------------------------------------------------------------- 1. Why is the time data changed, when I, e.g., apply sqrt(arrts), but not when arrts^0.5 ? This is my examples time series: ---------------------------------------------------------------------------- > arrts Time Series: Start = 3 End = 23 Frequency

R 3.5.0 Is it intended that the Date method of as.POSIXct does not respect the tz parameter? I suggest changing as.POSIXct.Date to this: function (x, tz = "", ...) .POSIXct(unclass(x) * 86400, tz = tz) Currently, the best workaround seems to be using the character method if one doesn't want the default timezone (which is often an annoying DST timezone). This came up on

R developers, The "tzone" attribute is stripped from a POSIXct object when the subscript command is called ("[.POISXct"). This results in dates being printed in the locale specific format after a subscript operation is applied to a POSIXct object which has cause several problems for me in the past. Here is an example of this problem under R 1.9.1: > x <-

Hi! I was wondering about the behavior of the range function wrt. logical NAs: > range(c(0L, 1L, NA), finite=T) [1] 0 1 > range(c(F, T, NA), finite=T) [1] NA NA The documentation is quite clear that "finite = TRUE includes na.rm = TRUE?, so that I would have assumed that these two snippets would produce the same result. - Lukas

Full_Name: Bo Zhou Version: 2.6.1 (2007-11-26) OS: Windows XP Submission from: (NULL) (207.237.54.242) Hi, I found an arithmetic problem when I'm doing something with POSIXct The code to reproduce it is as follows (This is the recommended way of finding out time zone difference on R News 2004-1 Page 32 URL http://cran.r-project.org/doc/Rnews/Rnews_2004-1.pdf) a=Sys.time()

(Drats! Jitterbug is playing tricks with the PR# again. Attempting to refile so that we can kill PR#10509) Peter Dalgaard wrote: > Kurt.Hornik at wu-wien.ac.at wrote: > =20 >> ------- Start of forwarded message ------- >> Date: Tue, 13 Nov 2007 21:44:57 +0100 >> To: Steve Mongin <sjm at ccbr.umn.edu> >> Cc: cran at r-project.org >> Subject: Re: range(

> ?is.finite `is.finite' and `is.infinite' return a vector of the same length as `x', indicating which elements are finite or not. is.finite() of a list seems to return a vector of the length of the list, but with value FALSE if any list element isn't finite. Is this intended? > l4 <- list(NA,1,2,3); l4; length(l4); is.finite(l4) [[1]] [1] NA [[2]] [1] 1

Dear R-helpers, running a zeroinflated model of the following type: zinb = zeroinfl(count=response ~., x = ~ . - response, z = ~. - response, dist = "negbin", data = t.data, trace = TRUE) generates the following message: Zero-Inflated Count Model Using logit to model zero vs non-zero Using Negative Binomial for counts dependent variable y: Y 0 1 2 3 359 52 7 3 generating

Hi! I'm confused by this: > as.numeric(as.POSIXct(518400,origin="2001-01-01")) [1] 978822000 I guess the problem is that as.numeric() assumes a different origin, but cannot find any default origin. How can I get back the seconds from the POSIXct format? In other words, which the inverse function of as.POSIXct()? I've tried as.numeric and unclass() using a origin=

>>>>> Lukas Stadler <lukas.stadler at oracle.com> >>>>> on Mon, 23 Oct 2017 15:56:55 +0200 writes: > Hi! > I was wondering about the behavior of the range function wrt. logical NAs: >> range(c(0L, 1L, NA), finite=T) > [1] 0 1 >> range(c(F, T, NA), finite=T) > [1] NA NA > The documentation is quite

Hi list! I'm getting an error message when trying to fit an accelerated failure time parametric model using the aftreg() function from package eha: > Error in optim(beta, Fmin, method = "BFGS", control = list(trace = > as.integer(printlevel)), : > non-finite finite-difference value [2] This only happens when adding four specific covariates at the same time in the

The following code: cut(as.POSIXct("2009-11-01 04:00:00", tz="America/Los_Angeles"), "1 day") gives the error: Error in seq.int(0, to - from, by) : 'to' must be finite This is related to November 1st, 2009 being the switchover date from daylight savings time to standard time in the America/Los_Angeles time zone. In particular, in cut.POSIXt, the starting

In S3 if you are passing an evaluated formula to another function that will store it and use it in printing (such as a model-fitting function), you usually want to unclass the formula. Otherwise, the formula that gets stored looks very ugly when printed. A trick to do the unclassing is to pass form = c( myFormula ) In R this has the effect of making form a list rather than a call. It seems

Dear R users, I have a question about numerical integration in R. I am facing the 'non-finite function value' error while integrating the function xf(x) using 'integrate'. f(x) is a probability density function and assumed to follow the three parameter (min = 0) beta distribution for which I have estimated the parameters. The function is integrated

Hello, I'm trying to use fitdistr() from the MASS package to fit a gamma distribution to a set of data. The data set is too large (1167 values) to reproduce in an email, but the summary statistics are: Min. 1st Qu. Median Mean 3rd Qu. Max. 116.7 266.7 666.7 1348.0 1642.0 16720.0 The call I'm trying to make is: fitdistr(x,"gamma") and the error is: Error in optim(x =

Dear R-help, I am doing clustering via finite mixture model. Please suggest some packages in R to find clusters via finite mixture model with continuous variables. And also I wish to verify the distributional properties of the mixture distributions by fitting the model with lognormal, gamma, exponentials etc,. Thanks in advance,  warm regards,Ms.Karunambigai M PhD Scholar Dept. of Biostatistics

The bottomline here is that one can always call a base method, inexpensively and without modifying the object, in, let's say, *formal* OOP languages. In R, this is not possible in general. It would be possible if there was always a foo.default, but primitives use internal dispatch. I was wondering whether it would be possible to provide a super(x, n) function which simply causes the

Full_Name: George N. White III Version: 1.9.0 OS: Irix 6.5.21m Submission from: (NULL) (142.176.61.212) R-1.9.0 built using the SGI MIPSPro compilers Installation directory: /usr/local C compiler: c99 -OPT:IEEE_NaN_inf=ON -mips4 -n32 -O3 -OPT:Olimit_opt=on C++ compiler: CC -OPT:IEEE_NaN_inf=ON -mips4 -n32 -O3 -OPT:Olimit_opt=on -LANG:std Fortran compiler: