similar to: Feature request: Limiting output of installed.packages()

Hi All, I just upgraded to the new 1.1rc5 from 1.0 that I had been using and it advised me to increase the file descriptor limit. I'm not sure how to do this. There is a command built into tcsh that allows me to do this called limit, but sudo limit 4224 doesn't work, and usually dovecot is started from the rc.local file if I recall right, and I'm not sure how to set this up from

On Jun 11, 2017, at 7:15 AM, Robbie van der Walle <rvanderwalle at gmail.com> wrote: > > I see only a reboot. Not a shutdown. But is this normal because shutdown -u -h +0 is used? > To be honest, I haven't experimented much with this, but I saw a normal shutdown/reboot when I just tried this from the command line (10.12): reboot ~ Mon Jun 12 08:36

Dear R useRs, i have the following code to compute values needed for a contour plot ############################################################ "myContour" <- function(a, b, plist, veca, vecb, dim) { tmpb <- seq(0.5 * b, 1.5 * b, length=dim) tmpa <- seq(0.5 * a, 1.5 * a, length=dim) z <- matrix(0, nrow=dim, ncol=dim) for(i in 1:dim) { for(j in 1:dim)

I am on my Mac, in Snow leopard, 10.6.8. Whenever I try to use wine to open a program or and application this message comes up in terminal: Dynamic session lookup supported but failed: launchd did not provide a socket path, verify that org.freedesktop.dbus-session.plist is loaded! err:process:__wine_kernel_init boot event wait timed out I have no idea what this means and I cannot find anything

Nigel Kersten and I had previously worked on a plist provider spec for Mac OS X. Attached is a PDF of the current state. I would appreciate any input and criticisms. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Puppet Users" group. To post to this group, send email to puppet-users@googlegroups.com To

Hallo, I have two vectors of different lengths which contain the same set of values: X < -c(2,6,1,7,4,3,5) Y <- c(1,1,6,4,6,1,4,1,2,3,6,6,1,2,4,4,5,4,1,7,6,6,4,4,7,1,2) How can I replace the values in Y with the index (!) of the corresponding values in X. So 2 appears in X in the first coordinate, so all 2’s in Y should be replaced by 1, etc. Thank you for your help, Serguei

Hi, Refresh doesn''t seem to be working with the launched service provider on OS X Lion (10.7.4). I''ve come up with a simple "service" script, plist file and puppet script to apply to demonstrate. The problem. Here''s the shell script which logs an initial starting message and then just loops logging a "Still running…" message.

Hello, how can I get rid of all dimnames so that: $amat Var3 Var2 Var1 8 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 7 1 1 1 0 1 0 0 0 1 0 0 0 0 0 0 6 1 1 0 1 0 1 0 0 0 1 0 0 0 0 0 5 1 1 0 0 0 0 0 0 0 0 1 0 0 0 0 4 1 0 1 1 0 0 1 0 0 0 0 1 0 0 0 3 1 0 1 0 0 0 0 0 0 0 0 0 1 0 0 2 1 0 0 1 0 0 0 0 0 0 0 0 0 1 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0

Hi, Can anyone help me out re how I change the startup options for mysql (v5.0) running on my Mac? (I just want to add the "--log" option is about it). I tried doing "sudo ./Library/StartupItems/MySQLCOM/MySQLCOM restart" however this started a 2nd instances of mysql & mysqld. Here is what I see start after Mac startup if this helps: $ ps aux | grep mysql _mysql 137 0.0

Dear List, I have been trying to use p.adjust() to do BH multiple test correction and have gotten some unexpected results. I thought that the equation for this was: pBH = p*n/i where p is the original p value, n is the number of tests and i is the rank of the p value. However when I try and recreate the corrected p from my most significant value it does not match up to the one computed by the

When I create a lattice/Trellis type graph, I typically write a function that returns the graph, as in do.graph <- function(x, y, ...) { require(lattice) return(xyplot(y~x, ...)) } My question today is this: If I want two graphs on one page, one way of achieving it is to print the objects into defined areas, as in gr1 <- xyplot(rnorm(111) ~ runif(111)) gr2 <-

I've got tinc running happily on a couple linux and win computers, but no luck on OS X. I'm on Yosemite 10.10.5, and I think I followed the OS X tutorial exactly, but no luck. Here's my error message: > sudo tincd -n dpsf -D -d3 tincd 1.0.21 (Feb 3 2015 20:09:36) starting, debug level 3 Could not open /dev/tun0: No such file or directory Terminating And here's the contents

Given an x-vector with, say, 3 elements, I would like to compute the following vector of permutated products (1-x1)*(1-x2)*(1-x3) (1-x1)*(1-x2)*x3 (1-x1)*x2*(1-x3) x1*(1-x2)*(1-x3) (1-x1)*x2*x3 x1*(1-x2)*x3 x1*x2*(1-x3) x1*x2*x3 Now, I already have the correctly sorted matrix of permutations! So, the input looks something like: #input x<-c(0.3,0.1,0.2) Nx<-length(x) Ncomb<-2^Nx

Hallo, The command: x <- 3 mat <- as.matrix(expand.grid(rep(list(0:1), x))) generates a matrix with 2^x columns containing the binary representations of the decimals from 0 to (2^x-1), here from 0 to 7. But the rows are not sorted in this order. How can sort the rows the ascending order of the decimals they represent, preferably without a function which converts binaries to decimals

Dear All! my data is on pairs of countries, i and j, e.g.: y,i,j 1,AUT,BEL 2,AUT,GER 3,BEL,GER I would like to create a dummy (indicator) variable for use in regression (using factor?), such that it takes the value of 1 if the country is in the pair (i.e. EITHER an i-country OR an j-country). Thank you for your help, Serguei ________________________________________ Austrian Institute of

Say I have a FOR-loop for computing powers (just a trivial example) for(i in 1:5) { x<-i^2 y<-i^3 } How can I create a data.frame and a 3D plot of (i,x(i),y(i)), i.e. for each iteration Thanks, Serguei Kaniovski -- ___________________________________________________________________ ??sterreichisches Institut f??r Wirtschaftsforschung (WIFO) Name: Serguei Kaniovski

Hello, Where I can find more info on how to nginx and mongrel boot when the machine reboots ? In os x, please. In Linux world I found some scripts but they don''t work and don''t go in the same place as OS X. thanks, r. -- Posted via http://www.ruby-forum.com/. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the

Hallo, suppose I have a vector: x <- c(1,1,1,2,2,3,3,3,3,3,4) How can I generate a vector/sequence in which a fixed number of zeroes (say 3) is inserted between the consecutive values, so I get 1,1,1,0,0,0,2,2,0,0,0,3,3,3,3,3,0,0,0,4 thanks a lot, Serguei [[alternative HTML version deleted]]

Hi, I would like to make a suggestion for a small syntactic modification of FUN argument in the family of functions [lsv]apply(). The idea is to allow one-liner expressions without typing "function(item) {...}" to surround them. The argument to the anonymous function is simply referred as ".". Let take an example. With this new feature, the following call

Thanks Simon, Now, I see better your argument. Le 16/04/2020 ? 22:48, Simon Urbanek a ?crit?: > ... I'm not arguing against the principle, I'm arguing about your > particular proposal as it is inconsistent and not general. This sounds promising for me. May be in a (new?) future, R core will come with a correct proposal for this principle? Meanwhile, to avoid substitute(),