similar to: Split String in regex while Keeping Delimiter

On Wed, 12 Apr 2023 08:29:50 +0000 Emily Bakker <emilybakker at outlook.com> wrote: > Some example data: > ?leucocyten + gramnegatieve staven +++ grampositieve staven ++? > ?leucocyten ? grampositieve coccen +? > ? > I want to split the strings such that I get the following result: > c(?leucocyten +?, ??gramnegatieve staven +++?, > ??grampositieve staven ++?) >

I thought replacing the spaces following instances of +++,++,+,- with "\n" and then reading with scan should succeed. Like Ivan Krylov I was fairly sure that you meant the minus sign to be "-" rather than "?", but perhaps your were using MS Word as an editor which is inconsistent with effective use of R. If so, learn to use a proper programming editor, and in any case

Dear Emily, Using a look-behind solves the split problem in this case. (Note: Using Regex is in most/many cases the simplest solution.) str = c("leucocyten + gramnegatieve staven +++ grampositieve staven ++", "leucocyten ? grampositieve coccen +") tokens = strsplit(str, "(?<=[-+])\\s++", perl=TRUE) PROBLEM The current expression does NOT work for a different

Hello list, I want to make a large rulebased algorithm, to provide decision support for drug prescriptions. I have defined the algorithm in a function, with a for loop and many if statements. The structure should be as follows: 1. Iterate over a list of drug names. For each drug: 2. Get some drug related data (external dataset). Row of a dataframe. 3. Check if adaptions should be made to

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Hi, please can you help me. When I add a legend to a boxplot it appears inside the plot area, how do you get it into the margins? I have already changed the parameters so there is space for it on the margin on the right hand side of the graph. Thanks, Emily [[alternative HTML version deleted]]

I'm trying to figure out if it's possible to use a character string as an equation, e.g: eqn1string <- "x^2 + x + 5" Then I want to tell R: 1) that eqn1string is actually an equation (even though it was stored as a character string), and 2) to apply the equation to a specified value of x (e.g. given x <- 6, what is the result of the equation). Thanks in advance for any

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Good day, I need to subset a data by removing several rows. I know the %in% operator, i.e. sub <- mydata[group %in% c("A","B","E","G"), ] What I need is the opposite, that is remove rows and/or columns. What is the operator for "NOT IN"? I tried (i)! %in% and (ii) ^%in% and both resulted in a "could not find function" error.

I have a data frame with three columns, one coded as a factor. I would like to separate my data out into separate data frames according to the factor level. Below is a simple example to illustrate. I can get R to return the data in the correct format but cannot work out how to get separate data frames. I am a newcommer to programming in R so am not sure what I am missing! Thanks, Emily

Hi, I'm new to R and I have a file with many rows of values. Each row contains a title and values for a contingency table e.g. row 1= title 8 0 37796 47 which is a table called 'title' with values 8 0 37796 47 I would like to know how I can import this using R and for each row calculate a p value using the fisher test. Using each p value I will do multiple a correction. I am

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Hi Dr. Snow, I am a graduate student working on analyzing data for my thesis and came across your post on an R forum: The default link function for the glm poisson family is a log link, which means that it is fitting the model: log(mu) ~ b0 + b1 * x But the data that you generate is based on a linear link. Therefore your glm analysis does not match with how the data was generated

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Dear R-Help, I am using the RDF package/ R 2.14 with the RDF package to download data from a website, and then use R to manipulate it. Text on the website is UTF-8. The RDF package's rdf_load command is converting it into a different encoding, which converts non-ASCII characters to unicode codes. On the webpage/sparql RDF: "4.5µg of cDNA was used" In R, the RDF triple gives:

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