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Hello, I apologize in advance for not providing sample data, I'm a very new to R and can't easily generate appropriate sample data quickly. I'm hoping someone can offer advice without it. This code below works and does what I want it to do, which is for a given row in my dataframe, where the variable "peak.cort" = max, it makes the value of another variable

I could do this in various hacky ways, but what's the right way? I have a nice application of the by function, which does what I want. The output looks like this: > auc_stress lab.samples.stress$subid: 2 cortisol amylase 1 919.05 6834.8 ---------------------------------------------------------------------------------------------------------------------------

Hello, I am having a problem where code that plots lines using a different data frame plots bars with the current data frame (I am intended to plot lines). The code specifies lines (see below), so I can't figure out why the results are bars. I suspect that it may have something to do with the fact that in the data frame where the code worked as intended, the both variables specifying

Hi, I have written the following function to check whether a vector has elements satisfying monotonicity. is.monotone <- function(vec, increase=T){ # check for monotonicity in time-stamp data for cortisol collection ans <- TRUE vec.nomis <- vec[!is.na(vec)] if (increase & any(diff(vec.nomis,1) < 0, na.rm=T)) ans <- FALSE if (!increase & any(diff(vec.nomis,1) > 0,

Hi I have data in the following format Cort Day Animal 23 0 1 27 3 1 24 0 2 27 1 2 34 2 2 30 3 2 24 4 2 20 0 3 24 1 3 28 2 3 34 4 3 etc. It is measured across time(day) however no every individual is measured the same number of times. All I want to do is plot the Raw data and then run a line connecting the

Hi all, Ihave jsut been compiling dovecot 1.1.6-1.1.8 on a solaris 10 x86 machine with sun studio 12. It compiles correctly but when i want to run dovecot i am getting this error message Jan 10 17:16:16 Carolyn dovecot: [ID 762119 mail.info] Dovecot v1.1.8 starting up Jan 10 17:16:16 Carolyn dovecot: [ID 107833 mail.warning] auth(default): Growing pool 'mysql driver' with: 1024 Jan

We use Maildir++ quota, with the rules taken from our LDAP backend. We also have an old expunge script that's not quota-aware; it removes old messages from the maildir by simply deleting the files. Sometimes, a mailbox is over quota before the script runs, but well under quota after the old messages are deleted. This change does not seem to be picked up, however: When I try to deliver a new

My guess: It I clear from the link that they can use the R logo for commercial purposes. The issue is what to do about the "appropriate credit" and "link to the license." How would I do that on a hoodie? Would they need a web address or something? -----Original Message----- From: R-help <r-help-bounces at r-project.org> On Behalf Of John Fox Sent: Tuesday, March 21, 2023

I sent the following to sunmanagers@sunmanagers.org and I'm also forwarding this to the samba list. I hope you can help: ------------- Begin Forwarded Message ------------- I have an emergency and am at the end of my resources and hope you can help. I'm a samba newbie and hope you can point me to an answer. Our Samba2.0.5 server is a Sun Enterprise 450 (Solaris 7). Our PDC is an NT

Hi, I'm trying to get point & print working against a 4.0.10 Samba server (using the sernet packages if that's relevant). I have the printer itself setup and I've uploaded the driver, but associating the uploaded driver with the printer causes Windows to give an error: "Printer settings could not be saved. Access is denied". I'm seeing the same symptoms on XP and

I may be missing something but using the plain old c() combine function seems to work fine: df <- data.frame(left = 1:5, right = 6:10) df.combined <- data.frame(comb = c(df$left, df$right)) df left right 1 1 6 2 2 7 3 3 8 4 4 9 5 5 10 df.combined comb 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 -----Original

Sorry about that, let me check the correct version for the intrin0.h include guard. //Marcus ________________________________ From: Ralph Giles <giles at thaumas.net> Sent: Thursday, June 11, 2020 19:31 To: Marcus Asteborg <xnorpx at outlook.com>; opus at xiph.org <opus at xiph.org> Subject: Re: [opus] Misc patches Speaking of needing more complete ci feedback, the intrin0.h

G'Day, I am trying to find a definitive answer to what the directory permissions should be for my configuration under Centos 5.5. I see a number of the following error messages in the maillog as a consequence of permissions errors. After reading the FAQ, Wiki etc. and browsing the web I am unable to determine just exactly what the user security settings should be for the offending

Thank you, but this now sounds more difficult: what would be the point in having these ready-made functions if I have to do it manually? Anyway, How would I implement the last part? On Thu, Mar 23, 2023 at 1:23?AM Ebert,Timothy Aaron <tebert at ufl.edu> wrote: > > If you are open to other options: > The null hypothesis is that there is no difference. > If I have two equations

Hi, You were on the right track using stack(), but you just pass the entire data frame as a single object, not the separate columns: > stack(NamesWide) ? values ? ind 1 ? ?Tom Name1 2 ? Dick Name1 3 ?Larry Name2 4 ?Curly Name2 Note that stack also returns the index (second column of 'ind' values), which tells you which column in the source data frame the stacked values originated

Hello, I have three numerical variables and I would like to test if their correlation is significantly different. I have seen that there is a package that "Test the difference between two (paired or unpaired) correlations". [https://www.personality-project.org/r/html/paired.r.html] However, there is the need to convert the correlations to "z scores using the Fisher r-z

Hi, I've got a problem with a samba server I inherited which I can't solve. I think it's the configuration rather than the version because I have the same problem with a 3.0.14 and a 3.0.11 Samba server with almost identical configurations. Both authenticate against LDAP, one has an old smbpasswd file which should no longer be in use. The issue is that when I click

Hello everbody, I want to generate different subsets of my data-set and safe this subsets with names listet in a vector. Because in reality I have got about 70 subsets I want to realize this in a loop Somehow like this: names=c("nam1",

Just to repeat: you have NamesWide<-data.frame(Name1=c("Tom","Dick"),Name2=c("Larry","Curly")) and you want NamesLong<-data.frame(Names=c("Tom","Dick","Larry","Curly")) There must be something I am missing, because NamesLong <- data.frame(Names = c(NamesWide$Name1, NamesWide$Name2)) appears to

It's still hard to figure out what you want. If you have two vectors you can compute their (2x2) covariance matrix using cov(cbind(x,y)). If you want to compute all pairwise squared differences between elements of x and y you could use outer(x, y, "-")^2. Can you explain a little bit more about (1) the context for your question and (2) why you want/need to use apply() ? On