similar to: R installation

I suspect this is pretty easy, but I'm having trouble figuring it out. Basically, I have a list of data frames such as the following example: list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) I would like to turn this into data frame where the list elements are essentially rbind'ed together and the element name becomes a new variable. For example, I would like to turn the

Good morning. Novice usR. Here. I am following this string, among many, learning as I go. Quick question please? I thought that perhaps ata.frame was part of the zoo pkg, b/c when I searched it came up in help? However, evidently not or I am not using it properly. Please advise, thank you. x <- list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) x2 <- do.call(rbind,

Hi Kevin, There is probably a better way, but it can be done in two steps like this temp <- list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) temp <- lapply(names(temp), function(n, temp) { temp[[n]]$type <- n return(temp[[n]]) }, temp = temp) do.call(rbind, temp) On Wed, May 2, 2018 at 1:11 PM, Kevin E. Thorpe <kevin.thorpe at utoronto.ca> wrote: > I suspect

It looks like you made a copy/paste error below. Your ata.frame should be data.frame. Kevin On 05/04/2018 08:18 AM, Bill Poling wrote: > Good morning. > > Novice usR. Here. > > I am following this string, among many, learning as I go. > > Quick question please? > > I thought that perhaps ata.frame was part of the zoo pkg, b/c when I > searched it came up in

Greetings, I have generated several ROC curves and would like to compare the AUCs. The data are cross sectional and the outcomes are binary. I am testing which of several models provide the best discrimination. Would it be most appropriate to report AUC with 95% CI's? I have been looking in to the "net reclassification improvement" (see below for reference) but thus far I can only

Or add the type column first and then rbind: x <- list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) x2 <- do.call(rbind, lapply(names(x), function(z) data.frame(type=z, dat[[z]]))) ---------------------------------------- David L Carlson Department of Anthropology Texas A&M University College Station, TX 77843-4352 -----Original Message----- From: R-help

Typo: dat[[z]] should be x[[z]]: x2 <- do.call(rbind, lapply(names(x), function(z) data.frame(type=z, x[[z]]))) x2 type x y 1 A 1 3 2 A 2 4 3 B 5 7 4 B 6 8 David C -----Original Message----- From: R-help <r-help-bounces at r-project.org> On Behalf Of David L Carlson Sent: Wednesday, May 2, 2018 3:51 PM To: William Dunlap <wdunlap at tibco.com>; Kevin E.

Hi all, I hope you are doing well? I?m currently using the lm() function from the package stats to fit linear multifactor regressions. Unfortunately, I didn?t yet find a way to fit linear multifactor regressions with constraint coefficients? I would like the slope coefficients to be all inside an interval, let?s say, between 0 and 1. Further, if possible, the slope coefficients should add up to

> x1 <- do.call(rbind, c(x, list(make.row.names=FALSE))) > x2 <- cbind(type=rep(names(x), vapply(x, nrow, 0)), x1) > str(x2) 'data.frame': 4 obs. of 3 variables: $ type: Factor w/ 2 levels "A","B": 1 1 2 2 $ x : int 1 2 5 6 $ y : int 3 4 7 8 Bill Dunlap TIBCO Software wdunlap tibco.com On Wed, May 2, 2018 at 10:11 AM, Kevin E. Thorpe

Regarding point 3, as a moderator I have been helping Andrew get this post out to the list over the past week. His previous attempts were encoded in some way that the listserv rejected. He sent me the post via his gmail account and viewing the source I saw it had at least both plain test and HTML an I said it was worth a try to post it. Certainly on my mail client his post displays acceptably

On Wed, 2 May 2018, Kevin E. Thorpe wrote: > I suspect this is pretty easy, but I'm having trouble figuring it out. > Basically, I have a list of data frames such as the following example: > > list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) > > I would like to turn this into data frame where the list elements are > essentially rbind'ed together and the

I suspect the main difficulty the OP is having is building R with shlib support. Steve, can you build from source without the --enable-R-shlib flag on configure? Kevin On 05/23/2018 01:58 PM, Ista Zahn wrote: > On Tue, May 22, 2018 at 6:47 PM, Steve Gutreuter <sgutreuter at gmail.com> wrote: >> I would love to hear from anyone who has successfully built 3.5.0 under >>

>>>>> David L Carlson <dcarlson at tamu.edu> >>>>> on Wed, 2 May 2018 21:43:52 +0000 writes: > Typo: dat[[z]] should be x[[z]]: > > x2 <- do.call(rbind, lapply(names(x), function(z) > data.frame(type=z, x[[z]]))) > x2 > type x y > 1 A 1 3 > 2 A 2 4 > 3 B 5 7 > 4 B 6 8 > >

There is also the package solrad that might do some of this. It is more intended for calculating solar radiation, which is probably not what you want, but may do other things you may find helpful. > On Jan 30, 2024, at 5:44?AM, Enrico Schumann <es at enricoschumann.net> wrote: > > On Tue, 30 Jan 2024, Richard O'Keefe writes: > >> Given >> - UTC timestamp

If the slope coefficients sum to a constant, the regressors are dependent and so a unique solution is impossible (an infinity of solutions would result). So I think you have something going on that you don't understand and should consult a local statistician to help you formulate your problem appropriately. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people

Hi - I am conducting a meta-analysis and I have a matrix of f-statistics, Ns and dfs from a series of studies that tested for an interaction in a 2x2 anova. I'd like to test whether the 2x2 interaction is significant in the aggregate. Similarly, I have a matrix of chi-square statistics that I'd like to meta-analyze. How can I input these test statistics into the "metafor"

Hello, TO update R under Ubuntu on my macchine, I downloaded R-2.13.1. When running ./configure, I got the following error message: checking for X... no configure: error: --with-x=yes (default) and X11 headers/libs are not available But I could use X11() function in R-2-10. So where does the problem come from? Cheers, Carol

Running the following lines I got a strange plot from hist function: x<-0:30 hist(x,breaks=31) As you can see, the 0 value appears two times in the plot. The Y axis only presents 1 as the highest value when: hist(x,breaks=62) Nevertheless, it seems to have two bars between 0 and 1. Could someone please explain to me why it is happening? Many thanks in advance!

Dear R software faculty:       There is a question bothering me. That is why we can not set the property of row.names=false when we output csv data. But there exists that parameter in R help. Hoping for your reply! Best regards!                                                                         Li Nan [[alternative HTML version deleted]]

Dear All I can not download R for Linux. I do not know which file I should install? Best Regards, Soheila