similar to: return value of {....}

atan(1i) -> 0 + Inf i complex(1/5) -> 0.2 + 0i atan(1i) -> (0 + Inf i) * (0.2 + 0i) -> 0*0.2 + 0*0i + Inf i * 0.2 + Inf i * 0i infinity times zero is undefined -> 0 + 0i + Inf i + NaN * i^2 -> 0 + 0i + Inf i - NaN -> NaN + Inf i I am not sure how complex arithmetic could arrive at another answer. I advise against messing with infinities... use atan2() if you don't

On 2024-09-05 4:23 p.m., Leo Mada via R-help wrote: > Dear R Users, > > Is this desired behaviour? > I presume it's a bug. > > atan(1i) > # 0+Infi > > tan(atan(1i)) > # 0+1i > > atan(1i) / 5 > # NaN+Infi There's no need to involve atan() and tan() in this: > (0+Inf*1i)/5 [1] NaN+Infi Why do you think this is a bug? Duncan Murdoch

Dear Bert, These behave like real divisions/multiplications: complex(re=Inf, im = Inf) * 5 # Inf+Infi complex(re=-Inf, im = Inf) * 5 # -Inf+Infi The real division / multiplication should be faster and also is well behaved. I was expecting R to do the real division/multiplication on a complex number. Which R actually does for these very particular cases; but not when only Im(x) is Inf.

> complex(real = 0, imaginary = Inf) [1] 0+Infi > Inf*1i [1] NaN+Infi >> complex(real = 0, imaginary = Inf)/5 [1] NaN+Infi See the Note in ?complex for the explanation, I think. Duncan can correct if I'm wrong. -- Bert On Thu, Sep 5, 2024 at 3:20?PM Leo Mada <leo.mada at syonic.eu> wrote: > Dear Bert, > > These behave like real divisions/multiplications: >

If one makes the reasonable assumption that Pct is much larger than Cutoff, sorting Cutoff is the expensive part e.g O(nlog2(n) for Quicksort (n = length Cutoff). I believe looping is O(n^2). Jeff's approach using findInterval may be faster. Of course implementation details matter. -- Bert On Mon, Oct 16, 2023 at 4:41?AM Leonard Mada <leo.mada at syonic.eu> wrote: > > Dear

Dear Jason, The code could look something like: dummyData = data.frame(Tract=seq(1, 10, by=1), ?? ?Pct = c(0.05,0.03,0.01,0.12,0.21,0.04,0.07,0.09,0.06,0.03), ?? ?Totpop = c(4000,3500,4500,4100,3900,4250,5100,4700,4950,4800)) # Define the cutoffs # - allow for duplicate entries; by = 0.03; # by = 0.01; cutoffs <- seq(0, 0.20, by = by) # Create a new column with cutoffs dummyData$Cutoff

Dear Shadee, If you have a data.frame with the following columns: n = 100; # population size x = data.frame( ??????Sex = sample(c("M","F"), n, T), ??????Country = sample(c("AA", "BB", "US"), n, T), ??????Income = as.factor(sample(1:3, n, T)) ) # Dummy variable ONE = rep(1, nrow(x)) r = aggregate(ONE ~ Sex + Income + Country, length, data = x)

? Sat, 1 Jun 2024 16:16:23 +0000 Leo Mada via R-help <r-help at r-project.org> ?????: > When highlighting pdf-documents with Microsoft Edge, the bounding box > is sometimes misplaced, and quite ugly so. It also lacks the ability > to draw lines or arrows. > > On the other hand, I did not get used to Acrobat Reader: it usually > involves much more effort to add specific

Dear Rich, It depends how the data is generated. Although I am not an expert in ecology, I can explain it based on a biomedical example. Certain variables are generated geometrically (exponentially), e.g. MIC or Titer. MIC = Minimum Inhibitory Concentration for bacterial resistance Titer = dilution which still has an effect, e.g. serially diluting blood samples; Obviously, diluting the

Perhaps > Inf*1i [1] NaN+Infi clarifies why it is *not* a bug. (Boy, did that jog some long dusty math memories :-) ) -- Bert On Thu, Sep 5, 2024 at 2:48?PM Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > On 2024-09-05 4:23 p.m., Leo Mada via R-help wrote: > > Dear R Users, > > > > Is this desired behaviour? > > I presume it's a bug. > >

Does anyone know how to pass a list of parameters into a function? for example: somefun=function(x1,x2,x3,x4,x5,x6,x7,x8,x9){ ans=x1+x2+x3+x4+x5+x6+x7+x8+x9 return(ans) } somefun(1,2,3,4,5,6,7,8,9) # I would like this to work: temp=c(x3=3,x4=4,x5=5,x6=6,x7=7,x8=8,x9=9) somefun(x1=1,x2=2,temp) # OR I would like this to work: temp=list(x3=3,x4=4,x5=5,x6=6,x7=7,x8=8,x9=9)

Hello, right now, i have a program to collect data into a table. right now, my table is table1 <- data.frame(trial = NA, x = NA, y = NA) for each time when i want to add data into my data, i have to copy data of table into an array for each column, and then i add new data into my array, then i copy my array into the table one column by one column. For example temptrial <- table1$trial;

My mistake! It does actually something else, which is incorrect. One could still use (although the code is more difficult to read): subset(tmp <- table(sample(1:10, 100, T)), tmp > 10) Sincerely, Leonard On 10/21/2023 10:26 PM, Leonard Mada wrote: > Dear List Members, > > There was recently an issue on R-devel (which I noticed only very late): >

Dear Duncun, What if there is no interactive "session" running? I will be running my scripts automatically from crontab in Linux. THanking you, Yours sincerely, AKSHAY M KULKARNI ________________________________ From: Duncan Murdoch <murdoch.duncan at gmail.com> Sent: Monday, March 20, 2023 12:20 AM To: akshay kulkarni <akshay_e4 at hotmail.com>; R

Again, the answer is "interactivity does not matter". On March 19, 2023 12:54:28 PM PDT, akshay kulkarni <akshay_e4 at hotmail.com> wrote: >Dear Jeff, > I will not be running R command in the shell prompt. So there is no banner, no > prompt. Just running "myscript.R" from the shell prompt. or from crontab in Linux. I think you get the

On 19/03/2023 2:55 p.m., akshay kulkarni wrote: > Dear Duncun, > ? ? ? ? ? ? ? ? ? ? ? ? ?What if there is no interactive "session" > running? I will be running my scripts automatically from crontab in Linux. I was talking about the session that is created for the duration of the BATCH run, not some other session that may be running in another process. Sorry for the

Hello Akshay, R is quite inspired by LISP, where this is a common thing. It is not in fact that {...} returned something, rather any expression evalulates to some value, and for a compound statement that is the last evaluated expression. {...} might be seen as similar to LISPs (begin ...). Now this is a very different thing compared to {...} in something like C, even if it looks or behaves

Dear Valentin, But why should {....} "return" a value? It could just as well evaluate all the expressions and store the resulting objects in whatever environment the interpreter chooses, and then it would be left to the user to manipulate any object he chooses. Don't you think returning the last, or any value, is redundant? We are living in the 21st century

dear Members, Today something weird has happened on my R console. I have attached two screenshots of the same vector in my R console but they differ. Also one of my function returns negative values, even after double checking the code, which should return only positive values.. Whats wrong..? Reinstall R? Thanks for help.... AKSHAY M KULKARNI -------------- next part -------------- A

Dear Jeff, I will not be running R command in the shell prompt. So there is no banner, no > prompt. Just running "myscript.R" from the shell prompt. or from crontab in Linux. I think you get the context..... thanking you, yours sincerely AKSHAY M KULKARNI ________________________________ From: Jeff Newmiller <jdnewmil at dcn.davis.ca.us> Sent: Monday, March