similar to: Confirm Your Account Details

Displaying 20 results from an estimated 30000 matches similar to: "Confirm Your Account Details"

2006 Jan 25
0
Another crack at age calculations
I cobbled this together based on a few previous posts and some tinkering, nothing fancy (my first bit of Ruby infact) but it seams to work for my purposes. My questions is actually why can I call <%= h(child.age(child.dob)) %> in a view but not <%= h(child.age_year_month(child.dob)) %>? Both work fine in the console. Thanks for any insight, Hugh child.rb class Child < Person
2010 Feb 23
1
Problem with strptime generating missing values where none appear to exist
Dear R Helpers, I am having difficulty with strptime. I wish to find the differences between two vectors of times. I have apparently no difficulty to convert the vectors to the appropriate format using strptime. But, then difftime does not calculate all the differences. Here is the code and output:- dob=strptime(as.character(datx$BDT),'%d-%b-%y'); dob$year=dob$year-100
2011 Nov 07
2
Problem working with dates
Hello All, I've been reading books about R for awhile now and am in the process of replicating the SAS analyses from an old report. I want to be sure that I can do all the things I need to in R before using it in my daily work. So far, I've managed to read in all my data and have done some data manipulation. I'm having trouble with fixing an error in a date variable though, and was
2010 Feb 23
0
subtracting 100 from strptime year vector generates missing values in POSIXct where none appear to exist in strptime year vector
Thanks Don MacQueen for this reply to my initial query - please SEE MY REPLIES TO THESE IDEAS AND FURTHER INFORMATION BELOW >From: Don MacQueen [macq at llnl.gov] >Sent: 23 February 2010 21:25 >To: Jonathan Williams; r-help at r-project.org > >Subject: Re: [R] Problem with strptime generating missing values where none appear to exist > >What happens if you do all that NA
2004 Aug 06
0
Please confirm your message
On 22 Nov 2002 07:41 MYT you wrote: > > > Hello, this is the mailing list anti-spam filter at Xiph.Org. > We need you to confirm your e-mail message with the subject of > "RE: [icecast] directory servers". > > Please send a message to the following address, or simply use your > mailer's "Reply" feature. > > icecast confirm
2012 Sep 13
1
Parsing "back" to API strcuture
Dear R experts, I'm reading data from an online database via API and it gets delivered in this messy comma separated structure, > RAW.API <-
2006 Jun 13
0
date_select and date validation
Hi, I''ve put together a simple form that contains among other things a date_select: <%= date_select(:user, :dob, :order => [:day, :month, :year], :start_year => 1900, :end_year => Date.today.year) %> In my controller I have some code to create a user entity from the parameters posted up from the form, like so: parameters:
2001 Oct 15
0
date and chron library help...!
Dear all, I'm not sure whether this is a bug or not... But some help would be greatly appreciated. I have a dataframe, which I read in using read.xport (from the foriegn library) as the orginal data is in SAS format. 3 columns of this dataset are supposed to be dates, but read.xport doesn't recognise them as dates (all columns are read in as mode numeric). So I load up the date library
2013 Jan 21
2
Re-Activate Your Account
Dear Webmail User, Your Mail quota has reached limit, You might not be able to send or receive new mail until you re-validate your mailbox .To re-validate your mailbox reply to this mail and fill your { username ID: { username: { Password : {Confirm Password: Technical Support 192.168.0.1 ********************************************************* Kirksville R-III School Dist. Mail System
2005 Dec 18
13
calculate age based on DoB
Hi, I wrote a little helper that calulates someone''s age based on his/her date of birth. def age(dob) diff = Date.today - dob age = (diff / 365.25).floor age.to_s end It works fine, but it''s not completely accurate as it just takes the average days in a year. It should be able to calculate this more accurately, right? I can''t work it out
2012 Jan 11
2
Checking dates for entry errors
Hello Everyone, ? I have a question about how best to check dates for?entry errors. I recently discovered that R will read?the incorrectly entered date "11/23/21931" without producing a warning or an?error message at least under some circumstances. ? > as.Date("11/23/21931", format = "%m/%d/%Y") [1] "2193-11-23" > as.Date("21931-11-23")
2015 Aug 10
0
Confirm your Twitter account, Mastrodonato
Mastrodonato, Confirm your email address to complete your Twitter account. It's easy - just click on the button below. Click on the link below or copy and paste it into a browser:
2012 Jul 11
3
unable to subtract dates in R
Hi, I wanted to calculate the age of people in my dataset by subtracting the individual's date of birth from their intake into a program. After several hours, searches of help archives, and the downloading of lubiridate, I have had no luck with this. Below is the code I used. > intakeDS$DOB <- as.character(intakeDS$DOB) > intakeDS$DOB <- as.Date(intakeDS$DOB,
2011 Jul 19
3
CentOS 6
I finally switched workstations, and am running into a lot of truly annoying details with CentOS 6, and the software with it. For one, I'm doing this by webmail, and this version of Firefox *insists* on putting what I'm typing in gray, rather than black. For another, I despise the new version of thunderbird, since it now shows the full subject, if I have what they used to call the preview
2012 Nov 06
1
pivot table
Hello, I have a data which looks like below: Some of the patients have multiple diagnosis. ID(200 patients)   Diag (100 unique Diag-200 in general)   Proc (50 uniqe Proc)  DOB (200)   Gender (200)    a                           daig1 b                           diag2 c                            diag1 I want to reformat this data to : ID   diag1 diag 2 diag 3..  diagx   proc1   proc2  
2010 Aug 16
1
How can I read date format '02-Jan-02' ?
Hello, I am trying to read a database exported from SAS. It is form of csv, and the date format reads '02-Feb-99'. I used following code to convert character to date format, db$dob<-as.Date(db$dob, format="%d-%b-%y"). but it doesn't work, only seems NA. What's wrong with this code? Thank you in advance. Best, Dong-Hee Koh [[alternative HTML version deleted]]
2007 Oct 18
0
validates_format_of date
Can someone tell me why this returns ''dob is invalid'' when dob is ''01/01/1969''? validates_format_of :dob, :with => /[0-9]{2}.[0-9]{2}.[0-9] {4}/, :message => ''is invalid'' I''m trying to validate a date entred into a form. I suppose there are different ways to accomplish this, and because it doesn''t work, I''m
2004 Apr 18
0
AGI Module
Hey all, I'm sorry to bother you with something so trivial, but I seem to be having an issue with the Asterisk::AGI module. I am a relative newbie with Perl so it could be a stupid syntax mistake that I missed. It seems when I try to execute either the stream_file or the get_data subs nothing is actually done. It doesn't seem to stream the files, but on the console it says it played the
2009 Apr 16
0
Printing data as a narrative or form letter rather than as a table
How would one print the information in a table without having to view it as a table? I have a dataframe with about 30 columns and 50 rows. About 7 rows contain human subjects where something is just not right and I need to manually work out what is going on with them and maybe even call them to ensure we have the data correct. It is really inconvenient to view the 7 patients in a table. Instead, I
2005 Oct 31
0
Problem using reshape with missing values in idvar
Hello everybody, I have been recently using reshape to convert "long" data to "wide" data. Everything was going well until I reached some problematic datasets. It has taken me a couple of weeks to finally figure out what might be happening. The problem is reproducible with test cases, and on two versions of R (Windows 2.2.0 and x86-64 Fedora Core 3 R 2.2.0). The data