similar to: Expressions from boxplot() passed to bxp()

It's not new anyway. You see the same behaviour with boxplot(dat, ylab=quote(X[2])) and it boils down to the use of do.call("bxp", ...) in the internals. As a general matter, expression() exists to prevent this sort of confusion, e.g., in this construction, > X <- quote(Y+1); bquote(f(.(X))) f(Y + 1) is indistinguishable from just entering f(Y+1), so f has no way of

Hi, This is most likely only a minor technicality, but I saw the following: On page 6 of the 'parallel' vignette (http://stat.ethz.ch/R-manual/R-devel/library/parallel/doc/parallel.pdf), the random-number generator "L'Ecuyer-CMRG" is said to have seed "(x_n, x_{n-1}, x_{n-2}, y_n, y_{n-1}, y_{n-2})". However, in L'Ecuyer et al. (2002), the seed is given with

Hi Simon, thanks for your quick reply. 1) ... so you can reproduce this? 2) Do you know a way how this can be 'foreseen'? We allocate larger matrices in the copula package depending on the user's input dimension. It would be good to tell her/him "Your dimension is quite large. Be aware of killers in your neighborhood"... before the killer attacks. Thanks & cheers,

Full_Name: Steve Ellison Version: 2.4.1 OS: Windows, Linux Submission from: (NULL) (194.73.101.157) bxp() allows specifcation of box locations with at=, but neither adjusts xlim= to fit at nor does it respect xlim provided explicitly. This is because bxp() now includes explicit xlim as c(0.5, n+0.5), without checking for explicitly supplied xlim (or ylim if horizontal). This also prevents

Hi, Both under the current R-devel (r66456) and a version from about 3 months ago, I experience the following behavior: > parallel::detectCores(TRUE) Error in system(cmd, TRUE) : error in running command > traceback() 3: system(cmd, TRUE) 2: gsub("^ +", "", system(cmd, TRUE)[1]) 1: parallel::detectCores(TRUE) > This is on Ubuntu 14.04. Does anybody else see this? [I

Dear all, I have a vector of expressions and would like to "paste" some string to it before using it in a plot: vars <- vector("expression", 2) vars[1] <- expression(alpha) vars[2] <- expression(beta) plot(0, 0, main=substitute(bold("Foo" ~~ VAR), list(VAR=vars[2]) )) Although I tried hard, I just can't figure out how to solve this. The title should be

Hi, Interesting "feature" in 10.11.4. I wonder if the process is killed before or after malloc() returns. If before, it seems very blunt: "You're asking too much and I don't like it so I kill you now". If after it doesn't look much better: "You're asking a lot and I don't like it but I give it to you anyway. I'll kill you quickly later". Why

Full_Name: Christian Ritter Version: 1.3.1 OS: win/nt Submission from: (NULL) (130.104.139.32) not a bug but lack of feature: outlier symbol can't be changed in bxp in bxp: ... points(rep(x, length(out)), out, col = border) ... as you can see, no pty or pch argument is used. -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list

Dear expeRts, The following code leads to R being killed (under Mac OS X 10.11.4; R installed from source; also happened under a previous unstable version): m <- matrix(0, 100000, 100000) I expected an error that a vector of this size could not be allocated. Besides the above (a bug?), how can I find out beforehand whether or not a square matrix can be allocated? Cheers, Marius PS: Here

Good Afternoon- I was wanting to alter the boxplot to remove the lower whisker, both the whisker line and staple just on the lower end. Is there a way to do this? As my code is currently: boxplot(log_loads~ind,data=nfmaum, horizontal=TRUE, notch=T, outline=FALSE, whisker=0, main="Maumee River Near Future Climate Scenarios", ylab="Log Load",xlab="Climate Scenarios")

dear all, could somebody tell me how I can plot mild outliers as a circle(?) and extreme outliers as an asterisk(*) in a box-whisker plot? Thanks very much in advance -- View this message in context: http://www.nabble.com/mild-and-extreme-outliers-in-boxplot-tp25040545p25040545.html Sent from the R help mailing list archive at Nabble.com.

> Can you elaborate on "leads to R being killed"? You should tell to the killer not to do it again :). Hi Simon! Sure, but who do you tell it if you don't know the killer? This is all the killer left me with, the 'crime scene' if you like :-) > m <- matrix(0, 90000, 100000) Killed: 9 My colleague Wayne Oldford also tried it on his Mac machine and apparently the

Hi, I often need to extend the plot range to the right, but not to the left (for example: not below 0 so that log = "x" still works...). This could be a handy improvement of extendrange(): --- utils.R 2015-08-25 18:18:20.000000000 -0400 +++ utils.R 2018-04-25 17:21:25.000000000 -0400 @@ -30,6 +30,6 @@ ## Purpose: extend a range by a factor 'f' - on each side

bonjour, i'm a mathematic teacher and i have a question for R-developers : is it possible to have (in the future) a boxplot with whiskers from the first decile to the ninth decile, as usual in secondary french schools... by example : boxplot(serie,range=-1) for french boxplot ? cordialement, jean-pierre lyc?e jean zay orl?ans, france http://mathazay.free.fr/spip/

Dear Users Is there any way to generate lines instead of points for outliers in the boxplot function? Thanks AA. [[alternative HTML version deleted]]

Dear list, I am using a external program that outputs Q1, Q3, median, upper and lower whisker values for various datasets simultaneously in a tab delimited format. After importing this text file into R, I would like to plot a boxplot using these given values and not the original series of data points, i.e. not using something like boxplot(mydata). Is there an easy way for doing this? If I am not

Full_Name: Bob O'Hara Version: 2.6.0 OS: Windows XP Submission from: (NULL) (88.112.20.250) Using horizontal=TRUE with boxplot() confuses it as to what is an x- or y-axis. At least, xlim= and ylim= are the wrong way round, log="x" (or "y") and xaxt= work as expected, I haven't looked at anything else. Some code to see if you can reproduce the bug (or discover

I'm graphing a series of boxplots of grouped data inside a function that passes the data.frame, the names vector, and a title vector. Because both the data subset changes with each successive pass through the function, occasionally the names vector turns up with only one group to plot. This is an expected result. However, when the names argument in boxplot has only a single name, it

Hello, I have a couple more questions about boxplots. In the books I've read on statistics (I'm not a statistics expert but just a poor engineer trying to help his wife with the analysis of the data she gathered for her medieval history PhD), I seen two kinds of box plots: one using quartiles to determine the height of the rectangles and whiskers which is what the standard R boxplot does,

Dear all, How can I get a bold "1000" in the title? I would like to use a variable (as opposed to putting in "1000" directly). library(lattice) N <- 1000 xyplot(0~0, xlab.top=list(label=as.expression(bquote(bold("foo" ~ .(N) ~ "bar"))), font=2, cex=1.2)) ## => "font=2" is ignored (of course) Cheers, Marius