similar to: matplot.Date & matplot.POSIXct

????? Thanks for the reply. On 2020-01-27 19:56, Abby Spurdle wrote: > Maybe I'm missing something really obvious here, but I was unable to > create a matrix out of POSIXct object(s). > Perhaps that deserves a separate discussion...? ????? Can you provide an example? ????? The standard matplot application that concerns me is with matplot(x, y, ...) where x has class Date or

>>>>> Spencer Graves >>>>> on Mon, 27 Jan 2020 23:02:28 -0600 writes: > ????? Thanks for the reply. > On 2020-01-27 19:56, Abby Spurdle wrote: >> Maybe I'm missing something really obvious here, but I was unable to >> create a matrix out of POSIXct object(s). >> Perhaps that deserves a separate discussion...? yes,

On 2020-01-28 05:13, Martin Maechler wrote: >>>>>> Spencer Graves >>>>>> on Mon, 27 Jan 2020 23:02:28 -0600 writes: <snip> > > Still, as Abby mentioned, turning a simple function into the > default method of an S3 generic is easy to do, but comes with a > bit of cost, not just S3 dispatch which typically is negligable in > graphics,

Hi, Matplot works with x being Date class but not POSIXt. Here is the example with R version 2.5.0 Under development (unstable) (2006-12-06 r40129) Example: x <- Sys.Date() - c(1:10) y <- cbind(1:10, 10:1) class(x) ## [1] "Date" matplot(x, y) x <- strptime(as.character(x), format="%Y-%m-%d") ## [1] "POSIXt" "POSIXlt" matplot(x, y) Error in

> > Maybe I'm missing something really obvious here, but I was unable to > > create a matrix out of POSIXct object(s). > > Perhaps that deserves a separate discussion...? > Can you provide an example? ------ #date and time objects x = Sys.Date () + 1:16 y = as.POSIXct (x) #matrices str (matrix (x, 4, 4) ) str (matrix (y, 4, 4) ) ------ Creating a matrix from a Date

>matplot(timestamp,xymatrix,type='l') where timestamp is a vector filled with POSIXct objects and xymatrix is a numeric 2x2 matrix plots but the horizontal axis labels are raw unformatted timestamps. I would like to format these in any of the available codes for strftime, for instance format="%H:%M". Passing a vector of formatted strings does not work. Any obvious other

Hi list, I know that points involving NAs are not plotted in 'matplot', but when I plot them as lines, I still want the lines to connect all the points (i.e. not broken where there are NAs).? Please see the example below.? How can I achieve this in 'matplot'?? If I can't, any good alternatives so I don't have to use 'plot' + 'lines' and loop through all the

Hello R users -- I am using matplot to prepare graphs and cannot find a way to use (for example) box(lwd=3) within the matplot command and instead have been setting the box line width after drawing the graph, by using box(lwd = 3). Looking over the ?par options and the matplot() help I do not see a way to set box width within matplot. Is there such an option? Thanks for suggestions,

Hi, I apologise in advance for the na?ve question. I have large matrices that I want to plot. I currently use color2D.matplot. However, these matrices contain many values of no interest (i.e. where there is no data, the figure -999 is automatically displayed). Is there any way of removing these from the matrices to be plotted by matplot? An obvious possibility is setting them all to 0, but that

Hi, I finally came up with a nice colored matrixplot, using the color2D.matplot function of the plotrix package. But I can't assign xtics and ytics to this plot. I made sure that the matrix has correct colnames() and rownames(). Here's what I do: a=matrix(1:16, 4, 4) colnames(a) <- c("X1", "X2", "X3", X4) rownames(a) <- c("Y1",

I am using color2D.matplot to plot a matrix about 400 by 200. The values in the matrix are 0:5 and NA. The resulting plot is not color, but shaded b/w. I tried to figure out how to add colors, I would like something like c(blue, green, red, cyan, green) #example motifx <- matrix(NA, nrow=100,ncol=20) motifx[,1:5] <- 1 motifx[,6:10] <- 2 motifx[,11:15] <- 3 motifx[,15:19] <- 4

I raised this question quite some time ago but it quitly went down the river. I'll give it a second try (before keeping my modified version of matplot for ever...): matplot supports vectors (and/or character strings) for a number of arguments namely `type', `lty', `lwd', `pch', `col', `cex'. all of them act consistently in such a way that the first entries are used

Full_Name: Christophe Genolini Version: 2.8.1, but also 2.9 OS: Windows XP Submission from: (NULL) (82.225.59.146) I am using matplot with the option lend="butt", but only the first line (the black) is printed correctly : > matplot(matrix(1:9,3),type="c",lwd=10,lty=1,lend="butt") Gabor Grothendieck find the problem in matplot code: the ... is passed to plot

Hi, I was trying to get error bars in my matplot. I looked at an earlier thread, and the sample code that I made is: #------------------ library(plotrix) mat1 <- matrix(sample(1:30,10),nrow=5,ncol=2) ses <- matrix(sample(1:3,10,replace=T),nrow=5,ncol=2) vect <- seq(20,100,20) rownames(mat1) <- rownames(ses) <- vect colnames(mat1) <- colnames(ses) <- letters[1:2]

I am a true R novice aonly using it for this function ;) I am trying to use color2D.matplot to form a image of my data using the following conditions color2D.matplot(fi1, c(dr), c(dg), c(db), nslices=7, ylab='Species', xlab="gene", show.legend=TRUE) where fi1 is my matrix. I have a matrix with 36 columns and 130 rows. most entries are 1 or 0 and I am trying to get this

n <- 63 a <- 1:n x <- a-1 y <- outer(x,a) matplot(x,y,type='l') Warning message: In matplot(x, y, type = "l") : default 'pch' is smaller than number of columns and hence recycled Why is it complaining if I specifically ask for type="l", so no pch involved? Annoyance or feature? The fix (if needed) is simple. In the matplot code change: if

Dear List, I am wanting to produce a multiple line plot, and know I can do it with matplot but can't get my data in the format I need. I have a dataframe with three columns; individuals ID, x, and y. I have tried split() but it gives me a list of matrices, which is closer but not quite what I need. For example: id<-rep(seq(1,5,1),length.out=100) x<-rnorm(100,5,1)

Hello, everyone. I am trying to show the correlation matrix using color2D.matplot(). And I want to map (0,1) to (dark red to dark green). But by default color2D.matplot() will map(min element of given matrix, max element of given matrix) to (dark red to dark green). Can anyone help me with this issue? Thanks a lot! Youcheng Lin ____________ [[alternative HTML version deleted]]

Hello, I've been trying to use ggplot, but I cannot seem to get my data in the correct form. I usually have a vector x, and a matrix y and I would usually use matplot(x,y) to plot the columns of y against x. Now, if i understand correctly, I should cast x and y into a data.frame and do something like ggplot(x,y,data=data). I think I'm missing something here: do I really need to

Dear List, I am trying to plot the result of cca using matplot but failed. Pls kindly help and thanks. Elaine The error message was error in xy.coords(x, y, xlabel, ylabel, log = log) : (list) object cannot be coerced to type 'double' code rm(list=ls()) library(vegan) library(MASS) # input richness birdrich