similar to: maximum matrix size

Displaying 20 results from an estimated 2000 matches similar to: "maximum matrix size"

2018 Oct 02
0
maximum matrix size
Does this help a little? https://cran.r-project.org/doc/manuals/r-release/R-ints.html#Long-vectors One thing I seem to remember but cannot find a reference for is that long vectors can only be passed to .Call calls, not C/Fortran. I remember rewriting .C() in my WGCNA package to .Call for this very reason but perhaps the restriction has been removed. Peter On Tue, Oct 2, 2018 at 9:43 AM
2011 Jul 19
1
"may be used in an incorrect context"
R CMD check tells me * checking R code for possible problems ... NOTE agexact.fit.rds: ... may be used in an incorrect context: ?optim(init, agfitfn, ...)? Warning: <anonymous>: ... may be used in an incorrect context: ?optim(init, agfitfn, ...)? Can anyone tell me what this message means? My searches haven't turned up anything useful. This is with R 2.7 and 2.9. The message
2004 Dec 16
0
fitting problems in coxph.fit
Dear Thomas & Dear List, the fitting function `coxph.fit' called by `coxph' may fail to estimate the regression coefficients when some values of the design matrix are very large. For example library(survival) ### load example data load(url("http://www.imbe.med.uni-erlangen.de/~hothorn/coxph_fit.Rda")) method <- "efron" ### copied from `coxph.fit' coxfit
2007 Dec 17
2
Capture warning messages from coxph()
Hi, I want to fit multiple cox models using the coxph() function. To do this, I use a for-loop and save the relevant results in a separate matrix. In the example below, only two models are fitted (my actual matrix has many more columns), one gives a warning message, while the other does not. Right now, I see all the warning message(s) after the for-loop is completed but have no idea which model
2007 May 18
1
partial correlation significance
Hi, among the many (5) methods that I found in the list to do partial correlation in the following two that I had a look I am getting different t-values. Does anyone have any clues on why is that? The source code is below. Thanks. pcor3 <- function (x, test = T, p = 0.05) { nvar <- ncol(x) ndata <- nrow(x) conc <- solve(cor(x)) resid.sd <- 1/sqrt(diag(conc)) pcc <-
2008 Mar 31
2
L-BFGS-B needs finite values of 'fn'
Dear All, I am trying to solve the optimization problem below, but I am always getting the following error: Error in optim(rep(20, nvar), f, gr, method = "L-BFGS-B", lower = rep(0, : L-BFGS-B needs finite values of 'fn' Any ideas? Thanks in advance, Paul ----------------------------------------------- k <- 10000 b <- 0.3 f <- function(x) { n <- length(x)
2013 Apr 25
1
lsfit: Error in formatting error message
Hi, in R-3.0 I get the following error when calling lsfit with more observations than variables, which seems to come from an error in the formatting of the error message (note that this was not happening in 2.15.3): > nobs <- 5; nvar <- 6; lsfit(matrix(runif(nobs*nvar), ncol=nvar), runif(nobs), intercept=FALSE) Error in sprintf(ngettext(nry, "%d response", "%d
2012 Feb 07
2
predict.naiveBayes() bug in e1071 package
Hi, I'm currently using the R package e1071 to train naive bayes classifiers and came across a bug: When the posterior probabilities of all classes are small, the result from the predict.naiveBayes function become NaNs. This is an issue with the treatment of the log-transformed probabilities inside the predict.naiveBayes function. Here is an example to demonstrate the problem (you might need
2011 Feb 25
1
help please ..simple question regarding output the p-value inside a function and lm
Dear R community members and R experts I am stuck at a point and I tried with my colleagues and did not get it out. Sorry, I need your help. Here my data (just created to show the example): # generating a dataset just to show how my dataset look like, here I have x variables # x1 .........to X1000 plus ind and y ind <- c(1:100) y <- rnorm(100, 10,2) set.seed(201) P <-
2008 Jan 14
2
Permutations of variables in a dataframe
Hallo All, I would like to apply a function to all permutations of variables in a dataframe (except the first). What is the best way to achieve this? I produce the permutations using: nvar <- ncol(dat) - 1 perms <- as.matrix( expand.grid(rep( list(1:0) , nvar ))[ , nvar:1] ) Thanks in advance Serguei Test-dataframe, comma-delimited: code,wav,w,area,gdp,def,pop,coast,milspend,agr
2005 Jul 07
2
r: LOOPING
hi all i know that one should try and limit the amount of looping in R programs. i have supplied some code below. i am interested in seeing how the code cold be rewritten if we dont use the loops. a brief overview of what is done in the code. ============================================== ============================================== ============================================== 1. the input
2013 Apr 01
2
Timing of SET_VECTOR_ELT
Assume a C program invoked by .Call, that returns a list. Near the top of the program we allocate space for all the list elements. (It is my habit to use "xyz2" for the name of the R object and "xyz" for the pointer to its contents.) PROTECT(means2 = allocVector(REALSXP, nvar)); means = REAL(means2); PROTECT(u2 = allocVector(REALSXP, nvar)); u =
2012 Oct 19
1
Looping survdiff
The number of recent questions from umn.edu makes me wonder if there's homework involved.... Simpler for your example is to use get and subset. dat <- structure(..... as found below var.to.test <- names(dat)[4:6] #variables of interest nvar <- length(var.to.test) chisq <- double(nvar) for (i in 1:nvar) { tfit <- survdiff(Surv(time, completion==2) ~
2013 Dec 08
2
How to evaluate sequence of strings like this
Hello Dear R community,  This is my problem.  I have a data set (dataframe) called "mydat". It consist of 3 numerical variable.  They are Centrecode, FSUSN and Round. I want to create unique ID by combining these 3 variables. Follwing commands gives me what I need. mydat1 <- paste(mydat$Centrecode, mydat$FSUSN,mydat$Round,sep="") newds <- data.frame(mydat1)    For a
2000 Dec 01
1
bug in outer() (PR#755)
Full_Name: Matthias von Davier Version: 1.1.1 OS: nt4.0 Submission from: (NULL) (144.81.31.148) sim3pl <- function(theta,i) { p2 <- p3pl(theta,i) p1 <- runif(1) temp <- response(p1,p2) return(p1) } when calling outer(theta,items,sim3pl), where theta = rnorm(100,m,s) and items = seq(1:nvar) runif(1) is only called once (instead of 100*nvar times), even though if calling sim3pl
2009 Jan 15
2
LCA (e1071 package): error
Hello, I will use the lca method in the e1071 package. But I get the following error: Error in pas[j, ] <- drop(exp(rep(1, nvar) %*% log(mp))) : number of items to replace is not a multiple of replacement length Does anybody know this error and knows what this means? Kind regards, Tryntsje
2011 Mar 18
1
help please: put output into dataframe
Dear R community members I have been struggling on this simple question, but never get appropriate solution. So please help. # my data, though I have a large number of variables var1 <- rnorm(500, 10,4) var2 <- rnorm(500, 20, 8) var3 <- rnorm(500, 30, 18) var4 <- rnorm(500, 40, 20) datafr1 <- data.frame(var1, var2, var3, var4) # my unsuccessful codes nvar <- ncol(datafr1)
2009 Jun 15
2
Schoenfeld Residuals with tied data
Dear all, I am struggling with calculation of Schoenfeld residuals of my Cox Ph models. Based on the formula as attached, I calculated the Schoenfeld residuals for both non tied and tied data, respectively. And then I validated my results with R using the same data sets. However, I found that my results for non-tied data was ok but the results for tied data were different from R's. How
2015 Oct 22
2
C_LogLin (stats/loglin)
Hi everyone, I have a question regarding a C function of the "stats" package in R. I tried to understand the ?loglin? basic function of the ?stats? package implemented in R. The implemented function itself runs without any problem (perhaps see sample). When I ran it line by line it stopped at the lines 23-24 of the loglin-function; (the following line): z <- .Call(C_LogLin,
2013 Jun 18
2
offset en bucle
Amigos de la erre. He creado mi primer bucle con for para entrenar unos modelos con GAM. La respuesta es quasipoisson porque estoy trabajando con densidades de peces. Sin embargo, tengo un problema, no se muy bien como añadir el offset a la formula siguiente cuando creo el bucle. GAM.A1 <-gam ((DYO)~s(DMA,k=4)+ s(WOD,k=4)+s(CIN,k=4)+s(DRA,k=4)+s(DBR,k=4)