similar to: Cannot Compute Box's M (Three Days Trying...)

Thanks Duncan. Awesome ideas! I think we're getting closer! I tried what you suggested and got a possibly better error... . . . rConnection.assign("boxMVariable", myDf); String resultBV = "str(boxMVariable)"; // your suggestion. RESULTING ERROR: Error in format.default(nam.ob, width = max(ncn), justify = "left") : invalid 'width' argument (No idea

I'm not sure what you mean. Could you please be more specific? If I print the string, I get: boxM(boxMVariable[, -5], boxMVariable[, 5]) From this code: . . . // assign the data to a variable.rConnection.assign("boxMVariable", myDf); // create a string command with that variable name.String boxVariable = "boxM(boxMVariable[, -5], boxMVariable[, 5])";

Hey Duncan, Hard to debug? That's an understatement. Eyes bleeding.... In any case, I tried all your suggestions. To get "integer" for the final column, I had to change the code to get integers instead of strings. double[] d1 = ((REXPVector) ((RList) tableRead).get(0)).asDoubles(); double[] d2 = ((REXPVector) ((RList) tableRead).get(1)).asDoubles(); double[] d3 = ((REXPVector)

Thanks Duncan. I can't tell you how helpful all your terrific replies have been. I think the biggest surprise is that nobody appears to be using Java and R together like I"m trying to do. I suppose it should be a surprise since there are no books on the subject and almost no technical documentation other than a few sites here and there. ----- I originally had the "int" as the

Thanks! I just figured it out (thanks to "Beyond Compare") and was coming here to post back. The boxM test doesn't work with that (now, finally working) REXP structure, but I probably now need to create a table or something and parse that structure. So much fun! :) Thanks again. - M Sent from [ProtonMail](https://protonmail.com), Swiss-based encrypted email. > --------

On 28/10/2017 8:59 AM, Morkus wrote: > Hey Duncan, > > Hard to debug? That's an understatement. Eyes bleeding.... > > In any case, I tried all your suggestions. To get "integer" for the > final column, I had to change the code to get integers instead of strings. The last column in iris is actually a factor. That's stored as an S3-classed integer vector

On 29/10/2017 7:26 AM, Morkus wrote: > Thanks Duncan. I can't tell you how helpful all your terrific replies > have been. > > I think the biggest surprise is that nobody appears to be using Java and > R together like I"m trying to do. I suppose it should be a surprise > since there are no books on the subject and almost no technical > documentation other than a

Does it work if you supply the closing parenthesis on the call to boxM? The parser says the input is incomplete and a missing closing parenthesis would cause that error.. // create a string command with that variable name.String boxVariable = "boxM(boxMVariable [,-5], boxMVariable[,5]"; // try to execute the command... // FAILS with org.rosuda.REngine.Rserve.RserveException: eval

On 28/10/2017 6:26 AM, Morkus wrote: > I'm not sure what you mean. Could you please be more specific? You were trying to eval an expression that you constructed in Java. I was suggesting that before you eval it, you print it. > > If I print the string, I get: *boxM(boxMVariable[, -5], boxMVariable[, 5])* Right, that's what I was suggesting you do. Now you've fixed the

On 28/10/2017 7:12 AM, Morkus wrote: > Thanks Duncan. Awesome ideas! > > I think we're getting closer! > > I tried what you suggested and got a possibly better error... > . > . > . > rConnection.assign("boxMVariable", myDf); > > *String resultBV *= *"str(boxMVariable)"*; *// your suggestion.* > > *RESULTING ERROR:* > >

Just print the string you are asking to R to evaluate. It doesn't make any sense as an R expression. Fix that, and things will work. Duncan Murdoch On 27/10/2017 3:41 PM, Morkus via R-devel wrote: > It can't be this hard, right? I really need a shove in the right direction here. Been spinning wheels for three days. Cannot get past the errors. > > I'm doing something

Hi All, OK, in the "back to the drawing board" department, I found what looks like a much better solution to using R in Java. Renjin. Looking at the docs and then trying a quick example, didn't quite work. Of course I'm missing something. Although I'm telling the engine to require ("biotools") just like I would in R itself, when I get to the line of code that

Just out of curiosity, I took the default "iris" example in the RF helpfile... but seeing the admonition against using the formula interface for large data sets, I wanted to play around a bit to see how the various options affected the output. Found something interesting I couldn't find documentation for... Just like the example... > set.seed(12) # to be sure I have

Hi there: I have a question about generating mean value of a data.frame. Take iris data for example, if I have a data.frame looking like the following: --------------------- Sepal.Length Sepal.Width Petal.Length Petal.Width Species 1 5.1 3.5 1.4 0.2 setosa 2 4.9 3.0 1.4 0.2

Hi, I was wondering if it is possible to get the rowindices without using the function "which" because I don't have a restriction criteria. Here's an example of what I mean: # take 10 randomly selected instances iris[sample(1:nrow(iris), 10),] # output Sepal.Length Sepal.Width Petal.Length Petal.Width Species 76 6.6 3.0 4.4 1.4

Dear R users, I have a question on the confusion matrix generated by function randomForest. I used the entire data set to generate the forest, for example: > print(iris.rf) Call: randomForest(formula = Species ~ ., data = iris, importance = TRUE, keep.forest = TRUE) confusion setosa versicolor virginica class.error setosa 50 0 0 0.00

I'm confused, hope someone can point out what is not obvious to me. I thought I was creating a new data frame by 'deleting' rows from an existing dataframe - I've tried 2 methods. But this new data frame seems to remember values from its parent - even though there are no occurences. Where does it get the values versicolor and virginica from and give then a count of 0? What

If do: > library("e1071") > example(svm) I get: svm> data(iris) svm> attach(iris) svm> ## classification mode svm> # default with factor response: svm> model <- svm(Species ~ ., data = iris) svm> # alternatively the traditional interface: svm> x <- subset(iris, select = -Species) svm> y <- Species svm> model <- svm(x, y) svm>

In the examples below, the first loses the name attached by foo(), the second retains names attached by bar(). Is this an intentional difference? I?d prefer that the names be retained in both cases. foo <- function(x) { c(mean = base::mean(x)) } bar <- function(x) { c(mean = base::mean(x), sd = stats::sd(x))} aggregate(iris$Sepal.Length, by = list(iris$Species), FUN = foo) #>

On Fri, Mar 23, 2018 at 6:43 PM, Rui Barradas <ruipbarradas at sapo.pt> wrote: > Hello, > > Not exactly an answer but here it goes. > If you use the formula interface the names will be retained. Also if you pass named arguments: aggregate(iris["Sepal.Length"], by = iris["Species"], FUN = foo) # Species Sepal.Length # 1 setosa 5.006 # 2