similar to: duplicated factor labels.

>>>>> Paul Johnson <pauljohn32 at gmail.com> >>>>> on Wed, 14 Jun 2017 19:00:11 -0500 writes: > Dear R devel > I've been wondering about this for a while. I am sorry to ask for your > time, but can one of you help me understand this? > This concerns duplicated labels, not levels, in the factor function. > I think it

To extwnd on Martin 's explanation : In factor(), levels are the unique input values and labels the unique output values. So the function levels() actually displays the labels. Cheers Joris On 15 Jun 2017 17:15, "Martin Maechler" <maechler at stat.math.ethz.ch> wrote: >>>>> Paul Johnson <pauljohn32 at gmail.com> >>>>> on Wed, 14 Jun

Happy New Year I recognize this is a low priority issue, but... I'll fix it if you let me. There are some TABs where R style calls for 4 spaces. For example R-3.0.2/src/library/stats/R/dummy.coef.R. I never noticed this until today, when I was stranded on a deserted island with only the R source code and a Swiss Army knife (vi). Now I realize my ~.vimrc has tabstop set at 2, and it makes

Hello :-) I am trying to run the next script, it generates "random areas" inside a map of the american continent, and then plot it, it?s suppose that every frame gives you the evolution of the program but at some point it stops with the weirdest of the errors I?ve ever seen in R, I don?t even have a line like that :-| Error in if (random_matrix[x_list[random_sq] - 1,

Hi I am relatively new to R and am trying to figure out to plot 3d scatter plot using defined colors based on x-axis and y-axis values. Right now in the code below, I assign colors based on certain values in the names of the x-axis. Now if I want to extend the condition to assign a color based on the names of both x-axis and y-axis values, what should I be doing? Any help or ideas would be

Hello, Everybody: This may not be a "bug", but for me it is an unexpected outcome. A factor variable's levels do not retain their ordering after the levels function is used. I supply an example in which a factor with values "BC" "AD" (in that order) is unintentionally re-alphabetized by the levels function. To me, this is very bad behavior. Would you agree? #

I am a bit confused about how to get the format of the labels in xyplot to show as dates rather than the numeric value. e.g., x <- as.Date(c("20/01/2001","20/02/2003","21/06/2004"),"%d/%m/%Y") y <- c(1,2,3) plot(y~x) #produces formatted labels xyplot(y~x) #doesn't give formatted x labels

Dear Abby, > On Aug 30, 2019, at 8:20 PM, Abby Spurdle <spurdle.a at gmail.com> wrote: > >> I think that it would be better to handle factors, character predictors, and logical predictors consistently. > > "logical predictors" can be regarded as categorical or continuous (i.e. 0 or 1). > And the model matrix should be the same, either way. I think that

Hi R world, I am such a newbie, with only 4-5 days of R experience. I did a search in forum history but couldn't find a solution to my problem... Sorry if it's obvious: I managed to draw a barplot (yey!) with xlabels of 'long' names (filenames, to be particular). To make them readable, I place them perpendicular to the axis (las=2). When I do that, however, these names don't

For example, this works: x = seq(-100, 1000, 25) y = x * x plot(x,y, xaxt="n") axis(1,x,FALSE,tcl=-0.3) axis(1,x[x %% 100 ==0]) It creates two axis objects and the values of the x-axis are the labels. The following scenario is more difficult, because it uses 'image' to plot a grid of values: a = matrix(rnorm(100),ncol=10) image(1:ncol(a), 1:nrow(a), a, xaxt="n",

Dear R-devel list members, I've discovered an inconsistency in how lm() and similar functions handle logical predictors as opposed to factor or character predictors. An "lm" object for a model that includes factor or character predictors includes the levels of a factor or unique values of a character predictor in the $xlevels component of the object, but not the FALSE/TRUE values

>>>>> Paul Johnson <pauljohn32 at gmail.com> >>>>> on Fri, 16 Jun 2017 11:02:34 -0500 writes: > On Fri, Jun 16, 2017 at 2:35 AM, Joris Meys <jorismeys at gmail.com> wrote: >> To extwnd on Martin 's explanation : >> >> In factor(), levels are the unique input values and labels the unique output >>

Hello, duplicated() does not seem to work for a long vector. For example, if you download the data from https://docs.google.com/open?id=0B6-m45Jvl3ZmNmpaSlJWMXo5bmc (a vector with about 12,000 numbers) and then run the following code which does duplicated() over the whole vector but just shows the last 30 elements: data.frame( tail(verylong, 30), tail(duplicated(verylong), 30) ) you'll see

Hi! I want to display 2 graphs with different number of data points on the x-axis. The code below scales them so it seems that testtwo has the same number of data points as testone. How can I fix that? thanks. z<-1:50; x<-1:100; plot(x,testone,type="l",xlab="",ylab="",main="",lty=4,axes=FALSE,ylim=c(-1.0,1.0),cex=1); par(new=TRUE);

>From this bug report (it's a proposal for speedup only, not a bug), https://bugs.r-project.org/bugzilla/show_bug.cgi?id=16895#c6 the fact that you can construct factors with non-unique aka "duplicated" levels in R has been re-raised. As mentioned there, we had a small discussion here (on 'R-devel') a bit more than 7 years ago, where I had said that indeed R core had

Muchísimas gracias Carlos, de verdad que te agradezco la ayuda, pero no es lo que voy buscando. Quiero colocar en el eje de abscisas la secuencia temporal de los meses, es decir, agosto septiembre, octubre, etc? pero no las fechas de las toma de datos, sino que aparezca la marca de un mes, y la siguiente marca sea la del siguiente mes, etc?, y además que las muestras estén separadas de acuerdo con

I'll go just a bit "fer-er." It appears the anomaly -- I hesitate to call it a bug -- is in the C code for duplicated.default(): > duplicated(letters[1:10],nmax=10) [1] FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE > duplicated(letters[1:10],nmax=9) [1] FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE > duplicated(letters[1:10],nmax=8) ## for

Greetings R experts, I'm having some difficulty recovering lda objects that I've saved within sublists using the save.image() function. I am running a script that exports a variety of different information as a list, included within that list is an lda object. I then take that list and create a list of that with all the different replications I've run. Unfortunately I've been

Hmm, the danger in this is that duplicated factor levels _used_ to be allowed (i.e. multiple codes with the same level). Disallowing it is what broke read.spss() on some files, because SPSS's concept of value labels is not 1-to-1 with factors. Reallowing it with different semantics could be premature. I mean, if we hadn't had the "forbidden" step, read.spss() could have changed

Hi, Some try: > names(mi$xlevels) [1] "f" > all.vars(mi$formula) [1] "D" "x" "f" "Y" > names(mx$xlevels) [1] "f" > all.vars(mx$formula) [1] "D" "x" "f" When offset is indicated out of the formula, it does not work... Marc Le 07/03/2018 ? 06:20, Bendix Carstensen a ?crit?: > I would like