similar to: [bug] droplevels() also drop object attributes (comment…)

>>>>> Martin Maechler <maechler at stat.math.ethz.ch> >>>>> on Tue, 16 May 2017 11:01:23 +0200 writes: >>>>> Serge Bibauw <sbibauw at gmail.com> >>>>> on Mon, 15 May 2017 11:59:32 -0400 writes: >> Hi, >> Just reporting a small bug? not really a big deal, but I >> don?t think that is

>>>>> Serge Bibauw <sbibauw at gmail.com> >>>>> on Mon, 15 May 2017 11:59:32 -0400 writes: > Hi, > Just reporting a small bug? not really a big deal, but I don?t think that is intended: droplevels()?also drops all object?s attributes. Yes. The help page for droplevels (or the simple definition of 'droplevels.factor') clearly

In R devel r72789, the added part in 'factor' documentation (factor.Rd) is the following. Undocumentedly for a long time, \code{factor(x)} loses all \code{\link{attributes}(x)} but \code{"names"}, and resets \code{"levels"} and \code{"class"}. In the code of function 'factor', names(x) is copied to the result. As I mentioned before, names(x) is _not_

* Be careful with "contrasts" attribute. If the number of levels is reduced, the original contrasts matrix is no longer valid. Example case: x <- factor(c("a", "a", "b", "b", "b"), levels = c("a", "b", "c")) contrasts(x) <- contr.treatment(levels(x), contrasts=FALSE)[, -2, drop=FALSE] droplevels(x) *

Dear all, Today I figured out that there is a neat function called droplevels, which, well, drops unused levels in a data frame. I tried the function with some of my data sets and it turned out that not only the unused levels were dropped but also the contrasts I set via "C". I had a look into the code, and this behaviour arises from the fact that droplevels uses simply factor to drop

Hello, Inline. Em 12-04-2017 16:40, Henric Winell escreveu: > (Let's keep the discussion on-list -- I've added back R-devel.) > > On 2017-04-12 16:39, Ulrich Windl wrote: > >>>>> Henric Winell <nilsson.henric at gmail.com> schrieb am 12.04.2017 >>>>> um 15:35 in >> Nachricht <b66fe849-bb8d-f00d-87e5-553f866d57e0 at gmail.com>:

The last line of the example in droplevels' manual page seems to be incorrect to me. I think it should read: "table(droplevels(aq$Month))". Amazingly (I don't understand) both variants seem to produce the same result (R 3.3.3): --- > aq <- transform(airquality, Month = factor(Month, labels = month.abb[5:9])) > aq <- subset(aq, Month != "Jul") >

In R devel r71124, if 'x' is a factor, droplevels(x) gives factor(x, exclude = NULL) . In R 3.3.1, it gives factor(x) . If a factor 'x' has NA and levels of 'x' doesn't contain NA, factor(x) gives the expected result for droplevels(x) , but factor(x, exclude = NULL) doesn't. As I said in https://stat.ethz.ch/pipermail/r-devel/2016-May/072796.html , factor(x,

In R devel r71157, 'droplevels' documentation, in "Arguments" section, says this about argument 'exclude'. passed to factor(); factor levels which should be excluded from the result even if present. Note that this was implicitly NA in R <= 3.3.1 which did drop NA levels even when present in x, contrary to the documentation. The current default is compatible with x[ ,

(Let's keep the discussion on-list -- I've added back R-devel.) On 2017-04-12 16:39, Ulrich Windl wrote: >>>> Henric Winell <nilsson.henric at gmail.com> schrieb am 12.04.2017 >>>> um 15:35 in > Nachricht <b66fe849-bb8d-f00d-87e5-553f866d57e0 at gmail.com>: >> On 2017-04-12 14:40, Ulrich Windl wrote: >> >>> The last line of the

>>>>> Rui Barradas <ruipbarradas at sapo.pt> >>>>> on Wed, 12 Apr 2017 17:07:45 +0100 writes: > Hello, Inline. > Em 12-04-2017 16:40, Henric Winell escreveu: >> (Let's keep the discussion on-list -- I've added back >> R-devel.) >> >> On 2017-04-12 16:39, Ulrich Windl wrote: >>

[Env: R 2.14.2 / Win Xp] In the script below, I want to select some variables from rrcov::OsloTransect, delete cases with any missing data, and subset the data frame Oslo to remove cases for two levels of the factor litho that occur with low frequency. The checks I run on my new data frame Oslo look OK, but I when I try to fit a multivariate linear model with lm(), I am getting an error:

I am basically fine with the change. How about using just the following? if(!is.character(exclude)) exclude <- as.vector(exclude, typeof(x)) # may result in NA x <- as.character(x) It looks simpler and is, more or less, equivalent. In factor.Rd, in description of argument 'exclude', "(when \code{x} is a \code{factor} already)" can be removed. A larger

Dear all, I am developing a package, which bundles my most frequently used functions. One of those is a modified version of droplevels from the base package (basically, it preserves any contrast function which was used to create the factor, contrast matrices are not kept, for they could be wrong if a level is dropped). In my NAMESPACE file I've the following directives, which should export

>>>>> Suharto Anggono Suharto Anggono via R-devel <r-devel at r-project.org> >>>>> on Sat, 27 Aug 2016 03:17:32 +0000 writes: > In R devel r71157, 'droplevels' documentation, in "Arguments" section, says this about argument 'exclude'. > passed to factor(); factor levels which should be excluded from the result even if

I find myself doing --8<---------------cut here---------------start------------->8--- tab <- table(...) tab <- tab[tab > 0] tab <- sort(tab,decreasing=TRUE) --8<---------------cut here---------------end--------------->8--- all the time. I am wondering if the "drop 0" (and maybe even sort?) can be effected by some magic argument to table() which I fail to discover

>>>>> Suharto Anggono Suharto Anggono via R-devel <r-devel at r-project.org> >>>>> on Fri, 2 Sep 2016 16:10:00 +0000 writes: > I am basically fine with the change. > How about using just the following? > if(!is.character(exclude)) > exclude <- as.vector(exclude, typeof(x)) # may result in NA > x <- as.character(x)

I have done the following using readLines directory <- "~/" files <- list.files(directory) data_frames <- vector("list", length(files)) for (i in seq_along(files)) { df <- readLines(file.path(directory, files[i])) df <- df[-(1:13)] df <- data.frame(year = substr(df,1,4), month = substr(df, 6,7), day =

Thanks Ben, Here the reproducible example. It works without notch=TRUE, but provides an error with notch=TURE Error in `geom_boxplot()`: ! Problem while converting geom to grob. ? Error occurred in the 1st layer. Caused by error in `ans[ypos] <- rep(yes, length.out = len)[ypos]`: ! replacement has length zero Run `rlang::last_trace()` to see where the error occurred. Warning message: In

Hi I am using ggplot to visualise y for a two-factorial group (Bio: 0 and 1) x = 6 years. I was able to adapt the colour of the lines (green and red) and the linetype (solid and dashed). Challenge: my code produces now two legends. One with the colors for the group and one with the linetype for the group. Does somebody have a hint how to adapt the code to produce one legend? Group 0 = red and