similar to: Getting high precision values from qnorm in the tail

I have a large Excel file with SKU numbers (stock keeping units) and forecasts which can be mimicked with the following: Period <- c(1, 2, 3, 1, 2, 3, 4, 1, 2) SKU <- c("A1","A1","A1","X4","X4","X4","X4","K2","K2") Forecast <- c(99, 103, 128, 63, 69, 72, 75, 207, 201) PeriodSKUForecast <-

I need to extract labels from Excel input data to use as dimnames later on. I can successfully read the Excel data into three matrices: capacity <- read.csv("c:\\R\\data\\capacity.csv") price.lookup <- read.csv("c:\\R\\data\\price lookup.csv") sales <- read.csv("c:\\R\\data\\sales.csv") The values to be used as dimnames are duplicated in the matrices. For

Hi Pino, On 2/26/19 5:52 PM, Mike Latimer wrote: > On 2/21/19 3:07 AM, Pino Toscano wrote: >> My question is: is using cirrus still the best choice for SUSE guests? >> If not, what about using qxl as well, as done for any non-SUSE guest? >> (We can also do that depending on the version of the guest, in case >> only newer SUSE versions work fine with qxl). > At the

Hi Mike, in 2013 you added the support for SUSE guests in the old virt-v2v (the one written in Perl); the commit doing it is attached, since the old virt-v2v was hosted on fedorahosted.org, which is no more. As part of that change, the default graphics driver was changed to be cirrus for SUSE guests, and qxl (as before) for any other. When Rich Jones rewrote virt-v2v in 2014 in OCaml, he kept

Hi, I also posted this question on the IRC #virt channel but have not received any reaction at the moment of posting this message to the mailing list. Since I last turned off my laptop (Dell XPS-15-9570 running Ubuntu 19.04) on Friday 10 May (I had to do it by long power press by the way), I am no longer able to get the display of my VMs: I am getting a black screen, even though I can see it

Trenkler, Dietrich said: > > I found the following strange behavior using qnorm() and pnorm(): > > > x<-8.21;x-qnorm(pnorm(x)) > [1] 0.0004638484 > > x<-8.28;x-qnorm(pnorm(x)) > [1] 0.07046385 > > x<-8.29;x-qnorm(pnorm(x)) > [1] 0.08046385 > > x<-8.30;x-qnorm(pnorm(x)) > [1] -Inf > qnorm(1-.Machine$double.eps) [1] 8.12589

dear all, it will just take you a minute to tell me the difference between qnorm and qqnorm. are they same or is there any difference between them?? regards

Hi everyone, I have the following problem. I have some small p-values but when I use qnorm(1-4e-30) I get an error. Is there anyway to get around this? -- Thanks, Jim. [[alternative HTML version deleted]]

The R-exts may explicitly state this but I missed it. How do I call qnorm or pnorm from Fortran? Thanks -Frank -- Frank E Harrell Jr Prof. of Biostatistics & Statistics Div. of Biostatistics & Epidem. Dept. of Health Evaluation Sciences U. Virginia School of Medicine http://hesweb1.med.virginia.edu/biostat

Dear R users, I was wondering from where I could get the C source code to compute pnbinom() and qnorm() ? (I would use R in batch mode but I find the startup time prohibitive, unless there is a way to speed it up) I searched the Web and it clearly is part of the R distribution, I just don't know how to extract them. Thanking you ! Markus Loecher Princeton, NJ [[alternative HTML version

I found the following strange behavior using qnorm() and pnorm(): > x<-8.21;x-qnorm(pnorm(x)) [1] 0.0004638484 > x<-8.22;x-qnorm(pnorm(x)) [1] 0.01046385 > x<-8.23;x-qnorm(pnorm(x)) [1] 0.02046385 > x<-8.24;x-qnorm(pnorm(x)) [1] 0.03046385 > x<-8.25;x-qnorm(pnorm(x)) [1] 0.04046385 > x<-8.26;x-qnorm(pnorm(x)) [1] 0.05046385 > x<-8.27;x-qnorm(pnorm(x))

Hi, I have this problem: X is hazardous variable N(mean 2, sd=3) >>question 1) Find the c value, so that P(X>c)=0.10. using R >>question 2) Graph the function N(2,3) and with this graph, explain what you do in question number 1. I just found question number one but not the second one. So, I'd like to make a plot form this distribution N (2,3) using the functions plot and

Hello, could You please help: I am looking for a way to formulate test accuracy measures such as test sensitivity, specificity, predictive values, and correct classification rate using p/d/qnorm. The tests' primary values follow a bimodal distribution, which is modelled by a mixture of two normal distributions: p * dnorm ((x - u1) / s1) / s1 + (1 - p) * dnorm ((x - u2) / s2) / s2)

Full_Name: Xiong Guanglei Version: 1.8.1 OS: Linux Submission from: (NULL) (202.38.103.50) qnorm(x) when x>1.0

At the top of src/nmath/qnorm.c it is stated: * Copyright (C) 1998 Ross Ihaka * Copyright (C) 2000--2005 The R Development Core Team * based on AS 111 (C) 1977 Royal Statistical Society * and on AS 241 (C) 1988 Royal Statistical Society The routine is in fact an f2c'd version of AS241 from StatLib: http://lib.stat.cmu.edu/apstat/241 and http://lib.stat.cmu.edu/apstat/ It

how R implement qnorm() I wonder anyone knows the mathematical process that R calculated the quantile? The reason I asked is soly by curiosity. I know the probability of a normal distribution is calculated through integrate the Gaussian function, which can be implemented easily (see code), while the calculation of quantile (or Zα) in R is a bit confusing as it requires inverse error function (X

Hello all, I have a question about basic statistics. Given a PDF value of 0.328161, how can I find out the value of -0.625 in R? It is like reversing the dnorm function but I do not know how to do it in R. > pdf.xb <- dnorm(-0.625) > pdf.xb [1] 0.328161 > qnorm(pdf.xb) [1] -0.444997 > pnorm(pdf.xb) [1] 0.628605 Many thanks, Edwin -- View this message in context:

Cordial saludo para cada uno. De manera amable les pido ayuda para acceder al código R usado para el algoritmo de la función qnorm. Gracias por su ayuda. César Escalante C. [[alternative HTML version deleted]]

When using XLConnect's readWorksheet, instead of it correctly reading string and numeric columns, I receive NA's with the following message: " Error when trying to evaluate cell A2 - not implemented yet" I do not know what this means. Can anyone please assist? -- __________________________ *Barry E. King, Ph.D.* Chief Modeler Qualex Consulting Services, Inc.

Hi all: I get the following error message that I am not able to resolve. Error in if (const(t, min(1e-08, mean(t)/1e+06))) { : missing value where TRUE/FALSE needed It appears right before the last data.frame statement. Below is the program that simulates data from one way random effects model and then computes normality and bootstrap confidence interval for