similar to: problem with print.generic(x)deparse(substitute(x))

Hi, Peter et al.: On 2017-01-09 4:24 AM, peter dalgaard wrote: > On 09 Jan 2017, at 10:53 , Spencer Graves <spencer.graves at prodsyse.com> wrote: > >> # Define an object of class 'dum' >> k <- 1 >> class(k) <- 'dum' >> str(k) # as expected >> >> # Define print.dum >> print.dum <- function(x, ...) >>

On 09 Jan 2017, at 10:53 , Spencer Graves <spencer.graves at prodsyse.com> wrote: > # Define an object of class 'dum' > k <- 1 > class(k) <- 'dum' > str(k) # as expected > > # Define print.dum > print.dum <- function(x, ...) > deparse(substitute(x)) > > print(k) # Prints "k" as expected > #####**** THE FOLLOWING PRINTS

In an implied call to an S3 print method, deparse(substitute(x)) returns "x", regardless of the name of object in .GlobalEnv, as indicated in the following: > Xnamed <- 1 > class(Xnamed) <- 'name.x' > print.name.x <- function(x, ...){ + namex <- deparse(substitute(x)) + cat('How can I get the name of x in .GlobalEnv?\n', +

In R-3.6.0 autoprinting was changed so that print methods for the storage modes are not called when there is no explicit class attribute. E.g., % R-3.6.0 --vanilla --quiet > print.function <- function(x, ...) { cat("Function with argument list "); cat(sep="\n ", head(deparse(args(x)), -1)); invisible(x) } > f <- function(x, ...) { sum( x * seq_along(x) ) }

It also is a problem with storage.modes "integer" and "complex": 3.6.0> print.integer <- function(x,...) "integer vector" 3.6.0> 1:10 [1] 1 2 3 4 5 6 7 8 9 10 3.6.0> print(1:10) [1] "integer vector" 3.6.0> 3.6.0> print.complex <- function(x, ...) "complex vector" 3.6.0> 1+2i [1] 1+2i 3.6.0>

Letting a user supply the autoprint function would be nice also. In a way you can already do that, using addTaskCallback(), but that doesn't let you suppress the standard autoprinting. Having the default autoprinting do its own style of method dispatch doesn't seem right. Bill Dunlap TIBCO Software wdunlap tibco.com On Tue, May 21, 2019 at 10:50 AM Lionel Henry <lionel at

Dear R helpers: I like to apply deparse(substitute()) on multiple arguments to collect the names of the arguments into a character vector. I used function test.fun as below. it works when there is only one input argument. but it does not work for multiple arguements. can someone kindly help? test.fun <- function(...){deparse(substitute(...))} test.fun(x) #this works test.fun(x,y,z) # I like

Hi, I'm writing a function that needs the input names (as characterstrings) as part of the output. With deparse(substitute( ) ) that works fine, until I replace all zeros with 0.001 (log is calculated at some time): tf <- function(input) { input[input==0] <- 0.001 ; deparse(substitute(input)) } myguess <- 42 tf(myguess) # not "myguess", but "42" Now when

Hello everyone, I encountered the following confusing behavior of 'deparse' and 'substitute' while programming with S4 classes (see example below). It seems like the presence of '...' argument in the definition of the generic generates the problem. I have no clue why, can anyone explain that to me? Are there any "workarounds"? Thanks a lot for your time!

I see that plot.default uses deparse(substitute(x)) to extract the character name of an argument and put it on the vertical axis. Hence: foo <- 1:10 plot( foo ) will put the label "foo" on the vertical axis. However, for a function that takes a "..." list as an input, I can only extract the first argument name: x <- 1:10 y <- 10:20 foo <- function(...) {

Dear list, can someone explain to me why deparse(substitute(x)) does not seem to work when x is of a user-defined S3 class? In my actual problem, my print method is part of a package, and the method is registered in the NAMESPACE, if that should make a difference. > print.testclass <- function(x,...){ xname <- deparse(substitute(x)) cat("Your object name

Hi all, I am experiencing the following quite strange (at least in my knowledge) problem in a simple function like the following: fn<-function(y,v=2){ n<-length(y) y<-y[(v+1):(n-v)] plot(y,type="l",lty=3,xlab="Time",ylab=deparse(substitute(y))) } fn(rnorm(50)) #look at the plot!!! The plot appears with numbers on the left side! If I delete the

In R code, "deparse(substitute(arg))" is the usual way to construct a label for an argument. Is there an equivalent to this in C code working on an SEXP, inside a function called by .Internal()? Duncan Murdoch

Hi the list, I am writing a function in which I need to affect a variable on a higher level. My fnction could be: ++++++++++++++++++ fooBis <- function(x){ nameObject <- deparse(substitute(x)) print(nameObject) assign(nameObject,4,envir=parent.frame()) } > fooBis(e) [1] "e" > e [1] 4 ----------------- (to simplify, this fnction can affect only the number

Dear list, When calling R from C, what appears like a spurious error can be triggered during the execution of chisq.test(x, y). This is happening when the following conditions are met: - x and y are "anonymous" C-level R vectors (they do not have a symbol), but they are protected from garbage collection - x and y are "not too small" (it was experienced as soon as they are

On 07/05/2017 3:56 PM, Spencer Graves wrote: > In an implied call to an S3 print method, deparse(substitute(x)) returns > "x", regardless of the name of object in .GlobalEnv, as indicated in the > following: > > > > Xnamed <- 1 > > class(Xnamed) <- 'name.x' > > print.name.x <- function(x, ...){ > + namex <-

Dear DevelopeRs, in continuing with my suite of packages on experimental design, I am stuck with an issue that appears to be related to package AlgDesign - I have tried to get it solved by Bob Wheeler, but he seems to be stuck as well. Whenever AlgDesign is loaded, some of my code does not work any more. For example, in a fresh R session: require(DoE.base) fac.design(nlevels=c(2,6,2))

dum is a simple data frame transferred to Splus using the dump() command in Splus and the source() in R. All fields are numeric. There are no missing data. The data frame looks like it is should: > apply(dum,2,mode) yrcl sland s02 s234 "numeric" "numeric" "numeric" "numeric" > apply(dum,2,is.vector) yrcl sland s02 s234

Dear List, I have the following function: coca <- function(x, ...) { if(is.null(class(x))) class(x) <- data.class(x) UseMethod("coca", x) } and a default method coca.default <- function(x, y, method = c("predictive", "symmetric"), reg.method = c("simpls", "eigen"), weights = NULL,

Hi, Can anyone help me with the following. I have been using R for Monte Carlo simulations and got some results I couldn't explain. Therefor I performed following short test: -------------- mean.sds <- NULL sample.sizes <- 3:30 for(N in sample.sizes){ dum <- NULL for(I in 1:5000){ x <- rnorm(N,0,1) dum <- c(dum,sd(x)) } mean.sds<- c(mean.sds,mean(dum)) }