similar to: table(exclude = NULL) always includes NA

>>>>> Martin Maechler <maechler at stat.math.ethz.ch> >>>>> on Mon, 15 Aug 2016 11:07:43 +0200 writes: >>>>> Suharto Anggono Suharto Anggono <suharto_anggono at yahoo.com> >>>>> on Sun, 14 Aug 2016 03:42:08 +0000 writes: >> useNA <- if (missing(useNA) && !missing(exclude) && !(NA %in%

useNA <- if (missing(useNA) && !missing(exclude) && !(NA %in% exclude)) "ifany" An example where it change 'table' result for non-factor input, from https://stat.ethz.ch/pipermail/r-help/2005-April/069053.html : x <- c(1,2,3,3,NA) table(as.integer(x), exclude=NaN) I bring the example up, in case that the change in result is not intended.

Looking at the code of function 'table' in R devel r71227, I see that the part "remove NA level if it was added only for excluded in factor(a, exclude=.)" is not quite right. In is.na(a) <- match(a0, c(exclude,NA), nomatch=0L) , I think that what is intended is a[a0 %in% c(exclude,NA)] <- NA . So, it should be is.na(a) <- match(a0, c(exclude,NA),

I stand corrected. The part "If set to 'NULL', it implies 'useNA="always"'." is even in the documentation in R 2.8.0. It was my fault not to check carefully. I wonder, why "always" was chosen for 'useNA' for exclude = NULL. Why exclude = NULL is so special? What about another 'exclude' of length zero, like character(0) (not c(),

This is an example from https://stat.ethz.ch/pipermail/r-help/2007-May/132573.html . With R 2.7.2: > a <- c(1, 1, 2, 2, NA, 3); b <- c(2, 1, 1, 1, 1, 1) > table(a, b, exclude = NULL) b a 1 2 1 1 1 2 2 0 3 1 0 <NA> 1 0 With R 3.3.1: > a <- c(1, 1, 2, 2, NA, 3); b <- c(2, 1, 1, 1, 1, 1) > table(a, b, exclude = NULL) b a 1 2

>>>>> Suharto Anggono Suharto Anggono <suharto_anggono at yahoo.com> >>>>> on Sun, 14 Aug 2016 03:42:08 +0000 writes: > useNA <- if (missing(useNA) && !missing(exclude) && !(NA %in% exclude)) "ifany" > An example where it change 'table' result for non-factor input, from

Good morning, Is there a way to get table() to default to including NAs - as in... table(..., useNA='ifany') or table(..., useNA='always') or table(..., exclude=NULL) ? I can't see a way under table() or options() or searching the archives (probably using the wrong keyword?). > t1 <- c(1,2,3,3,3,2,NA,NA,NA,NA) > table(t1) t1 1 2 3 1 2 3 I keep forgetting to

>>>>> Suharto Anggono Suharto Anggono via R-devel <r-devel at r-project.org> >>>>> on Thu, 11 Aug 2016 16:19:49 +0000 writes: > I stand corrected. The part "If set to 'NULL', it implies > 'useNA="always"'." is even in the documentation in R > 2.8.0. It was my fault not to check carefully. I wonder,

>>>>> Suharto Anggono Suharto Anggono via R-devel <r-devel at r-project.org> >>>>> on Sun, 7 Aug 2016 15:32:19 +0000 writes: > This is an example from https://stat.ethz.ch/pipermail/r-help/2007-May/132573.html . > With R 2.7.2: > > a <- c(1, 1, 2, 2, NA, 3); b <- c(2, 1, 1, 1, 1, 1) > > table(a, b, exclude = NULL) > b >

Hi All, my script tries to do the following on factors: > ## Check for case 3: Umsatz = 0 & Kunde = 1 > for (year in 2011:2015) { + Umsatz <- paste0("Umsatz_", year) + Kunde <- paste0("Kunde01_", year) + Check <- paste0("Check_U_0__Kd_1_", year) + + cat('Creating', Check, 'from', Umsatz, "and", Kunde,

Hi Your script is not reproducible. Creating Check_U_0__Kd_1_2011 from Umsatz_2011 and Kunde01_2011 Error in ifelse(Kunden01[[Umsatz]] == 0 & Kunden01[[Kunde]] == 1, 1, 0) : object 'Kunden01' not found > This is interesting x <- c(NA, FALSE, TRUE) names(x) <- as.character(x) outer(x, x, "&") ## AND table <NA> FALSE TRUE <NA> NA FALSE

R version 2.14.0, started with --vanilla > table(c(1,2,3,4,NA), exclude=2, useNA='ifany') 1 3 4 <NA> 1 1 1 2 This came from a local user who wanted to remove one particular response from some tables, but also wants to have NA always reported for data checking purposes. I don't think the above is what anyone would want. PS. This is on a

Hi I haven't found a way to produce a tabulation from factor data with NA values using xtabs. Please find a minimal example below, it's also on R-pubs [1]. Tested with R 3.1.2 and R-devel r67720. It doesn't seem to be documented explicitly that it's not supported. From reading the code [2] it looks like the relevant call to table() doesn't set the "useNA"

Hi, table1D() below can be up to 60x faster than base::table() for the 1D case. Here are the detailed speedups compared to base::table(). o With a logical vector of length 5M: 11x faster (or more if 'useNA="always"') o With factor/integer/numeric/character of length 1M and 9 levels (or 9 distinct values for non-factors):

In R 2.7.2, if argument 'exclude' is not specified and input is already a factor, function 'table' uses the input as is. In R 2.15.2, in the same case, function 'table' always applies function 'factor' to the input. The time spent by 'factor' is not long, but is not negligible. I suggest to change 'table' so that 'factor' is not called for

Hi I've recently started using Emacs as my text editor for writing R script. I am looking for a feature which I have seen on the standard R text editor for Mac OS. In the Mac OS editor when you start typing a function, the possible arguments for that function appear at the bottom of the window. E.g. if you type "table( " before you finish typing you can see at the bottom of the

Hi your initial ds > str(ds) 'data.frame': 2 obs. of 3 variables: $ var1: num 1 1 $ var2: logi TRUE FALSE $ var3: logi NA NA first result > str(ds) 'data.frame': 2 obs. of 6 variables: $ var1 : num 1 1 $ var2 : logi TRUE FALSE $ var3 : logi NA NA $ value_and_logical: logi TRUE TRUE $ logical_and_na : logi TRUE NA

Hi guys, I hope you can help me with this. Here is the problem: I have some data (myData) that looks similar to this: [,1] [,2] [,3] [,4] [1,] "A" "A" "B" "B" [2,] "B" "B" "B" "B" [3,] "C" "C" "C" "C" When I build a contingency table for the first and second

Hi all, I know this issue has been discussed a few times in the past already, but Martin Maechler suggested in a bug report [1] that I raise it here. Basically, there is no (easy) way of printing NAs for all variables when calling xtabs() on factors. Passing 'exclude=NULL, na.action=na.pass' works for character vectors, but not for factors. > test <-

Dear all I'm creating two way tables based on weighted survey data using svytable and want to include NAs as a level in the table. For unweighted data I use table(..., useNA="ifany"). Is there any equivalent for svytable? If not, is there a solution using a different function? Thanks Tim -- Tim Elwell-Sutton The University of Hong Kong Office: 3906 2053 Mob: 6084 5654