Displaying 20 results from an estimated 1100 matches similar to: "Assignment operator and deep copy for calling C functions"
2012 Apr 14
1
deep copy?
Is putting a variable into a list a deep copy (and is tracemem the
correct way to confirm)?
warmstrong at krypton:~/dvl/R.packages$ R
> x <- rnorm(1000)
> tracemem(x)
[1] "<0x3214c90>"
> x.list <- list(x.in.list=x)
tracemem[0x3214c90 -> 0x2af0a20]:
>
Is it possible to put a variable into a list without causing a deep
copy (i.e. if you _really_ want the
2016 Aug 05
2
Extra copies of objects in environments when using $ operator?
My understanding is that R will not make copies of lists if there is
only one reference to the object. However, I've encountered a case
where R does make copies, even though (I think) there should be only
one reference to the object. I hope that someone could shed some light
on why this is happening.
I'll start with a simple example. Below, x is a list with one element,
and changing that
2010 Nov 23
1
Possibility for memory improvement: x <- as.vector(x) always(?) duplicates
Hi,
I've noticed that as.vector() always allocates a new object, e.g.
> x <- 1:10;
> x <- as.vector(x);
> tracemem(x);
[1] "<0x0000000005622db8"
> x <- as.vector(x);
tracemem[0x0000000005622db8 -> 0x0000000005622ec0]: as.vector
> x <- as.vector(x);
tracemem[0x0000000005622ec0 -> 0x0000000005622f18]: as.vector
> x <- as.vector(x);
2012 Jul 12
2
Understanding tracemem
Hi all,
I've been trying to get a better handle on what manipulations lead R
to duplicate a vector, creating small experiments and using tracemem
to observe what happens (all in 2.15.1). That's lead me to a few
questions, illustrated using the snippet below.
x <- 1:10
tracemem(x)
# [1] "<0x1058f8238>"
x[5] <- 5
# tracemem[0x1058f8238 -> 0x105994ab0]:
x[11] <-
2012 Jan 17
1
names<- appears to copy 3 times?
Hi,
$ R --vanilla
R version 2.14.1 (2011-12-22)
Platform: i686-pc-linux-gnu (32-bit)
> DF = data.frame(a=1:3,b=4:6)
> DF
a b
1 1 4
2 2 5
3 3 6
> tracemem(DF)
[1] "<0x8898098>"
> names(DF)[2]="B"
tracemem[0x8898098 -> 0x8763e18]:
tracemem[0x8763e18 -> 0x8766be8]:
tracemem[0x8766be8 -> 0x8766b68]:
> DF
a B
1 1 4
2 2 5
3 3 6
>
Are those 3
2006 Jul 31
5
use tracemem to dump content in function read/write
Hi Expert
I want to use dtrace to monitor the content change of one file. I made following scripts,
#!/usr/sbin/dtrace -s
inline int MYPID = $1;
syscall::write:entry
/pid == MYPID/
{
tracemem(arg1, arg2);
printf("\n");
}
It always has an following error
bash-3.00$ sudo dumpFIFO.dtrace 3836
dtrace: failed to compile script ./dumpFIFO.dtrace: line 19: tracemem( ) argument #2
2006 Jun 29
2
tracemem() not exactly what I had in mind
I was trying to use tracemem to look at mblk contents. First, I tried to use
mblk->b_wptr - mblk->b_rptr as the size, and was told that it had to be a
constant. Foo. (RFE #1).
Then, I tried to use 8 as the size, and kept getting decimal numbers printed.
Stumbled on #pragma D option rawbytes=true (is the =true necessary, btw?) and
that didn''t help.
Then, in desperation, I
2008 Feb 26
11
Is there way to trace memory in the dtrace ?
N_conreq:entry {
self->x=1;
calledaddr=(struct xaddrf *)arg3;
callingaddr=(struct xaddrf *)arg4;
trace(calledaddr->link_id);
tracemem(calledaddr->DTE_MAC.lsap_add, 80);
trace(callingaddr->link_id);
tracemem(callingaddr->DTE_MAC.lsap_add, 80);
}
0 -> N_conreq 255
2010 Sep 01
6
Why is vector assignment in R recreates the entire vector ?
Hello all,
A friend recently brought to my attention that vector assignment actually
recreates the entire vector on which the assignment is performed.
So for example, the code:
x[10]<- NA # The original call (short version)
Is really doing this:
x<- replace(x, list=10, values=NA) # The original call (long version)
# assigning a whole new vector to x
Which is actually doing this:
x<-
2008 Jan 23
2
R binary version with R_MEMORY_PROFILING
Hi all,
Where can I find an R binary version (>2.4.0 ) for windows that compiled
with R_MEMORY_PROFILING?
Within our application we are experiencing serious problems with memory
usage. And being able to use "Rprofmem" and "tracemem" command seems like
our best option.
Thanks,
Yoni
[[alternative HTML version deleted]]
2016 Aug 05
0
Extra copies of objects in environments when using $ operator?
On Fri, 5 Aug 2016, Winston Chang wrote:
> My understanding is that R will not make copies of lists if there is
> only one reference to the object. However, I've encountered a case
> where R does make copies, even though (I think) there should be only
> one reference to the object. I hope that someone could shed some light
> on why this is happening.
>
> I'll start
2013 May 18
1
Copy on assignment to large field of reference class
Dear all
I am trying to find the best way to handle large fields in reference
classes.
As the code below shows assignment via <<- causes many copies to be made if
the subsetting is extensive (in modb1). This can cause R to run out of
memory. Creating a local copy and using the optimisation in <- is the best
solution I have found so far (in modb2) - but it is not really much better
than
2008 Apr 07
0
Some memory questions: data.frame and lists.
Hi there,
I seek your expert opinion on the following memory related questions. The
output below was gotten from R-2.6.2, compiled with
--enable-memory-profiling on Ubuntu Linux.
=======================================================================
>>> Code and output 1:
> gc( )
used (Mb) gc trigger (Mb) max used (Mb)
Ncells 131180 7.1 350000 18.7 350000 18.7
2006 May 26
1
memory profiling
I'm interested in playing around with memory profiling in R-devel (as described
at http://developer.r-project.org/memory-profiling.html) and was trying to
figure out how to compile R-devel so that I can use the 'tracemem()' function.
But I can't figure out how/where to set R_MEMORY_PROFILING. Is it on the
configure command line?
Thanks for any help,
-roger
--
Roger D. Peng
2012 Jun 06
2
suggest that as.double( something double ) not make a copy
I've been playing with passing arguments to .C(), and found that replacing
as.double(x)
with
if(is.double(x)) x else as.double(x)
saves time and avoids one copy, in the case that x is already double.
I suggest modifying as.double to avoid the extra copy and just
return x, when x is already double. Similarly for as.integer, etc.
[[alternative HTML version deleted]]
2014 Jun 17
0
PATCH: Avoiding extra copies (NAMED bumped) with source(..., print.eval=FALSE) ...and with print.eval=TRUE?
OBJECTIVE:
To update source(..., print.eval=FALSE) to not use withVisible()
unless really needed. This avoids unnecessary increases of reference
counts/NAMED introduced by withVisible(), which in turn avoids
unnecessary memory allocations and garbage collection overhead. This
has an impact on all source():ed scripts, e.g. pre-allocation of large
matrices to save memory does *not always* help in
2008 Apr 14
3
Doing the right amount of copy for large data frames.
Hi there,
Problem ::
When one tries to change one or some of the columns of a data.frame, R makes
a copy of the whole data.frame using the '*tmp*' mechanism (this does not
happen for components of a list, tracemem( ) on R-2.6.2 says so).
Suggested solution ::
Store the columns of the data.frame as a list inside of an environment slot
of an S4 class, and define the '[',
2020 Jan 09
6
Get memory address of an R data frame
Hello,
I would like for my C function to be able to manipulate some values stored in an R data frame.
To achieve this, a need the (real) memory address where the R data frame stores its data (hopefully in a contiguous way). Then, from R, I call the C function and passing this memory address as a parameter.
The question: how can we get the memory address of the R data frame?
Thank you!
L.
2020 Jan 09
0
Get memory address of an R data frame
Hi Lille,
Is it possible you're looking for tracemem() or inspect() ?
> x <- data.frame(z = 1:10)> tracemem(x)[1] "<0x55aa743e0bc0>"
> x[1] <- 2Ltracemem[0x55aa743e0bc0 -> 0x55aa778f6ad0]:
tracemem[0x55aa778f6ad0 -> 0x55aa778f6868]: [<-.data.frame [<-
tracemem[0x55aa778f6868 -> 0x55aa778f5b48]: [<-.data.frame [<-
>
2011 Jul 25
2
Best practices for writing R functions (really copying)
Gabriel Becker writes:
AFAIK R does not automatically copy function arguments. R actually tries
very hard to avoid copying while maintaining "pass by value" functionality.
... R only copies data when you modify an object, not
when you simply pass it to a function.
This is a bit misleading. R tries to avoid copying by maintaining a
count of how many references there are to an