Displaying 5 results from an estimated 5 matches similar to: "match()/%in% with language objects?"
2015 Aug 26
1
match()/%in% with language objects?
>>>>> William Dunlap <wdunlap at tibco.com>
>>>>> on Tue, 25 Aug 2015 09:47:23 -0700 writes:
> match(x,table) and x%in%table work when x and table are lists of language
> objects or expressions. E.g.,
> expression(quote(1+2), quote(log2(16))) %in% expression(3, quote(1+2), c(4L,5L,6L,7L))
> #[1] TRUE FALSE
>
2015 Aug 25
0
match()/%in% with language objects?
match(x,table) and x%in%table work when x and table are lists of language
objects or expressions. E.g.,
expression(quote(1+2), quote(log2(16))) %in% expression(3, quote(1+2),
c(4L,5L,6L,7L))
#[1] TRUE FALSE
list(quote(1+2), quote(log2(16))) %in% list(3, quote(1+2), c(4L,5L,6L,7L))
#[1] TRUE FALSE
match(list(quote(1+2), quote(log2(16))), list(3, quote(1+2),
c(4L,5L,6L,7L)))
#[1] 2
2017 Dec 07
2
parallel computing with foreach()
I have used foreach() for parallel computing but in the current problem, it
is not working. Given the volume and type of the data involved in the
analysis, I will try to give below the complete code without reproducible
example.
In short, each R environment will draw a set of separate files, perform the
analysis and dump in separate folders.
splist <- c("juoc", "juos",
2017 Dec 07
0
parallel computing with foreach()
Your code generates an error that has nothing to do with dopar. I have
no idea what your function stack is supposed to do; you may be
inadvertently calling utils::stack which would produce this kind of
error:
> stack(1:25, RAT = FALSE)
Error in data.frame(values = unlist(unname(x)), ind, stringsAsFactors = FALSE) :
arguments imply differing number of rows: 25, 0
HTH,
Peter
On Wed, Dec 6,
2009 Mar 27
3
color vectors other than gray()
I'm trying to create a graph where different cells of a grid (a shapefile)
will be painted with a color share scale, where the most easy way is to use
gray().
Can I somehow get a vector (gradient) of colors, a vector of colors with
other methods but gray()?
I'm doing this until now
quad_N_sp <-