similar to: bquote/evalq behavior changed in R-3.2.1

In 3.1.2 eval does not store the result of the bquote-generated call in the given environment. Interestingly, in 3.2.1 eval does store the result of the bquote-generated call in the given environment. In other words if I run the given example with eval rather than evalq, on 3.1.2 "x" is never stored in "fenv," but it is when I run the same code on 3.2.1. However, the given

David, If you are referring to the solution that would be: rapply(list(test), eval, envir = fenv) I thought I explained in the question that the above code does not work. It does not throw an error, but the behavior is no different (at least in the output or result). Using the above code still results in the x object not being stored in fenv on 3.1.2. Dayne On Wed, Jul 15, 2015 at 4:40 PM,

On Jul 15, 2015, at 12:51 PM, William Dunlap wrote: > I think rapply() was changed to act like lapply() in this respect. > When I looked at the source of the difference, it was that typeof() returned 'language' in 3.2.1, while it returned 'list' in the earlier version of R. The first check in rapply's code in both version was: if (typeof(object) != "list")

I think rapply() was changed to act like lapply() in this respect. In R-3.1.3 we got rapply(list(quote(1+myNumber)), evalq, envir=list2env(list(myNumber=17))) #[1] 18 rapply(list(quote(1+myNumber)), eval, envir=list2env(list(myNumber=17))) #Error in (function (expr, envir = parent.frame(), enclos = if (is.list(envir) || : object 'myNumber' not found lapply(list(quote(1+myNumber)),

Bill, Is your conclusion to just update the code and enforce using the most recent version of R? Dayne On Wed, Jul 15, 2015 at 4:44 PM, Dayne Filer <dayne.filer at gmail.com> wrote: > David, > > If you are referring to the solution that would be: > > rapply(list(test), eval, envir = fenv) > > I thought I explained in the question that the above code does not work.

Another aspect of the change is (using TERR's RinR package): > options(REvaluators=list(makeREvaluator("R-3.1.3"), makeREvaluator("R-3.2.0"))) > RCompare(rapply(list(quote(function(x)x),list(quote(pi),quote(7-4))), function(arg)typeof(arg))) R version 3.1.3 (2015-03-09) R version 3.2.0 (2015-04-16) [1,] [1]

I am curious why you used evalq instead of eval in this code. Bill Dunlap TIBCO Software wdunlap tibco.com On Wed, Jul 15, 2015 at 11:49 AM, Dayne Filer <dayne.filer at gmail.com> wrote: > Hello, > > I upgraded from 3.1.2 to 3.2.1 and am receiving errors on code that worked > as I intended previously. Briefly, I am using bquote to generate > expressions to modify data.table

The help page of eval says: The 'evalq' form is equivalent to 'eval(quote(expr), ...)'. But the following is not equivalent. Can anyone give me some explaination? Thanks very much. > f1 <- function(x,digits=5) lapply(x, f2) > f2 <- function(x) eval(quote(print(x+1,digits=digits)),list(x=x),parent.frame(2)) > f1(list(x1=1)) [1] 2 $x1 [1] 2 > > f1 <-

Hi, When using evalq to evaluate expressions within a say data.frame context I often wish there was a 'subset' argument, much like in lm() or any ather advanced regression model. I would be grateful for a tip how to do this. Here is an illustration of what I want: n <- 100 data <- data.frame(x=rnorm(n), y=rnorm(y), z=rnorm(z)) # this works evalq({ i <- 0<x;

On Mon, Jan 26, 2015 at 12:24 PM, Hadley Wickham <h.wickham at gmail.com> wrote: > If it was any other environment than the global, you could use substitute: > > e <- new.env() > delayedAssign("foo", stop("Hey!"), assign.env = e) > substitute(foo, e) > > delayedAssign("foo", stop("Hey!")) > substitute(foo) Hmm... interesting

I ran into an interesting issue with `evalq` (and also `eval(quote(...))`): ???? f <- function() { ?????? list( ???????? sys.parent(1), ???????? evalq(sys.parent(1)), ???????? evalq((function() sys.parent(2))()),? # add an anon fun layer ???????? evalq((function() sys.parent(1))()) ?????? ) ???? } ???? res <- f() ???? str(res) ???? ## List of 4 ???? ##? $ : int 0???????? # sys.parent(1)

On 01/04/2015 1:35 PM, Gabriel Becker wrote: > Joris, > > > The second argument to evalq is envir, so that line says, roughly, "call > environment() to generate me a new environment within the environment > defined by data". I think that's not quite right. environment() returns the current environment, it doesn't create a new one. It is evalq() that created

Hi, folks. I was wondering if any of you could point me in the right direction. Using R 3.3.3 (and later), on an IBM Power LPAR, Red Hat 7 PPC64le, markdown build fails as below. > install.packages("markdown") trying URL 'https://cloud.r-project.org/src/contrib/markdown_0.8.tar.gz' Content type 'unknown' length 80583 bytes (78 KB)

I maintain the package affylmGUI. It works when installed on many previous versions of R. I have today tested exactly the same code under R-2.15.3, R-3.0.2, R-3.1.0, R-3.1.1, R-3.1.2 and R-devel. I have also tested the versions of affylmGUI downloaded by biocLite for each version of R and the same result applies. I have no errors under 2.15.3, 3.0.2, 3.1.0 and 3.1.1. The following error

Hi, I want to put text on a plot containing something like: a = b^2 = <squared numeric value of b> using bquote. Example: mu = 5 plot(1:10,1:10) text(2,8, bquote(delta == mu^2)) # This works text(2.5,8, bquote(phantom(0) == .(mu^2))) # but is unpredictable text(2,8, bquote(delta == mu^2 == .(mu^2))) # This doesn't work The last text function returns the error:

I'm still going over old emails and trying to get my head around evaluation so I'm persistent if nothing else. A while back , an expert sent me below as an exercise in understanding and I only got around to it tonight. I understand some of the output but not all of it and I put "Why not Zero ?" next to the ones that I don't understand based on my reading of the various

Hi, In order to avoid deep copies by passing large arguments to functions or returning values, I'm trying to do the assignment of variables in a given environment. The problem is when I try to assign a structure: a list for example. If I have: ind <- c("a","b") my idea is doing something like l <- alist() l[ind] <- as.list(c(20,40)) in a given

Hi, R-help, (sessionInfo at the end) I'm trying to construct a function using bquote and running into a strange error message. As an example, what I would like to do is this: z <- 2 eval(bquote(function(x, y) { x^.(z) + y }))(2, 3) However, I get the following: Error in eval(expr, envir, enclos) : invalid formal argument list for "function" However, if I change the

Hi, I need to plot the beta as the symbol, followed by the index 3 as the title of a graph. This code works> main= bquote(paste("Results for ", beta ==.(b1)) but I also need the index 3. I tried (simplified): >plot(x,y, main= bquote(paste("Results for ", beta, "3", ==.(b1)))) and a few other versions, but I can not get it to run properly. Any help would

Dear mailing list, I have found some strange behaviour which I think relates to parent frames and eval. Can anyone explain what's going on here? First example: > test.parent.funcs_ function() { outer.var_ 5 subfunc1_ function() substitute( outer.var, envir=parent.frame()) print( subfunc1()) subfunc2b_ function() eval( quote( outer.var), envir=parent.frame()) print(