similar to: xtabs and NA

Hi all, I know this issue has been discussed a few times in the past already, but Martin Maechler suggested in a bug report [1] that I raise it here. Basically, there is no (easy) way of printing NAs for all variables when calling xtabs() on factors. Passing 'exclude=NULL, na.action=na.pass' works for character vectors, but not for factors. > test <-

On Mon, Feb 9, 2015 at 8:52 AM, Kirill M?ller <kirill.mueller at ivt.baug.ethz.ch> wrote: > Hi > > > I haven't found a way to produce a tabulation from factor data with NA > values using xtabs. Please find a minimal example below, it's also on R-pubs > [1]. Tested with R 3.1.2 and R-devel r67720. > > It doesn't seem to be documented explicitly that

The problem here is Table doesn't seem to have a way to weigh the data. > ToyData Data1 Data2 Data3 Weight 101 Sam Red Banana 1.1 102 Sam Green Banana 2.1 103 Sam Blue Orange 2.1 104 Fred Red Orange 2.1 105 Fred Green Guava 2.1 106 Fred Blue Guava 2.1 107 <NA> Red Pear 50.1 108 <NA> Green Pear 50.1 109 <NA> Blue

Hello! I have a dataset with NA's in some variables (factors), for example: $ P67 : Factor w/ 2 levels "-","+": NA 2 1 NA NA 2 1 1 2 NA ... I need to use 'xtabs' like xtabs(~x$P67) It works well and produces something like this: x$P67 - + 779 1318 but i want to compute NA's too, like this: x$P67 - + NA 779 1318 137 I am trying

>>>>> Milan Bouchet-Valat <nalimilan at club.fr> >>>>> on Thu, 19 Jan 2017 13:58:31 +0100 writes: > Hi all, > I know this issue has been discussed a few times in the past already, > but Martin Maechler suggested in a bug report [1] that I raise it here. > > Basically, there is no (easy) way of printing NAs for all variables > when calling

Diverted from ESS-help. It is really about R's LANGUAGE, locales and then a wish for sessionInfo() : >>>>> Sparapani, Rodney <rsparapa at mcw.edu> >>>>> on Thu, 20 Feb 2014 19:39:33 +0000 writes: >> Just guessing: perhaps this is something that is set when >> R is initialized and not queried every time something is >>

The attached code produces corrupted pdfs (test2.pdf, test4.pdf and test5.pdf). The resulting pdf depends on how many cores are available on the machine. I don't see why there should be any difference between the pdfs (exept for the timestamp). Doing many operations involving mclapply can increase the size of the resulting pdf by ten times! Thank you for checking this. require(multicore)

Hi all, I cannot get xtabs to count NA's like I expect. Below is a sample session, and note that the last two calls to xtabs() yield exactly the same thing. I am running R-2.5.0 -- if there was a bug in xtabs that got fixed, I would love to know about it. If there is a bug tracker somewhere, I can file it too. It isn't my fault that the server is so ridiculously outdated, but I would

Dear list, I am trying to make a contingency table with xtabs but I am getting a 0 where I expect a 'NA'. Here is a simple example: options(stringsAsFactors = FALSE) rn <- LETTERS[1:4] df1 <- data.frame(r07 = rep(rn, each=4), r08 = rep(rn, 4), value = 1:16) xtabs(value ~ r07 + r08, df1) # Delete the combination [A, C] df1 <- df1[-3,] # Set 'value'

Dear all I was willing to use argument 'exclude' in function xtabs to remove some levels of factors (xtabs help page says '"exclude: a vector of values to be excluded when forming the set of levels of the classifying factors"). I tried: > mydata <- data.frame( treatment = c("B", "A", "C", "C", "B",

I have an application that would generate a cross-tabulation in array format in R. In particular, my application would give me a result similar to that of : array(5,c(2,2,2,2,2)) The above could be seen as a cross-tabulation of 5 variables with 2 levels each (could be 0 and 1). In this case, the data were such that each cell has exactly 5 observations. I Now, I want the output to look like the

Hoping someone can help me with xtabs and ftable. I'm trying to get a pair of ftables (possibly more) next to each other. For example: > dunhill_lights_xtab<-ftable(xtabs(grossedupobs ~ gender+age_group + dunhill_lights, data = ciggs)) > dunhill_lights_xtab dunhill_lights No Yes gender age_group Female

Hi, xtabs() creates a table of counts. I want a table of proportions -- that is, I want to divide every vector (along a particular dimension) by its sum. The tiny example below does that. The call to xtabs() creates a matrix "A" with dimensions ("x1","x2","y"). I transform "A" using aperm() and aaply() to get the matrix "B". The

>>>>> akshay kulkarni >>>>> on Wed, 31 May 2023 20:55:33 +0000 writes: > dear members, > I am using arfima() from forecast package to model a time > series. The following is the code: >> LYGH[[202]] > [1] 45.40 3.25 6.50 2.15 >> arfima(LYGH[[202]]) > Error in .fdcov(x, fdf$d, h, nar = nar, nma = nma,

Hi list, is it possible convert the xtabs result xtabs(breaks~tension+wool,data=warpbreaks) wool tension A B L 401 254 M 216 259 H 221 169 to a simple matrix or data frame? A B L 401 254 M 216 259 H 221 169 Thanks a lot! Gianandrea -- View this message in context: http://www.nabble.com/From-xtabs-to-matrix-tp24304588p24304588.html

Greetings- Using R 1.2.2 under linux, I get the following: > l.agg<-xtabs(cbind(r.logic.interests, r.logic.morality, + r.logic.enlightened, r.logic.capacity, r.logic.mediate) + ~ grouptype, + data=gt) Error in parse(file, n, text, prompt) : parse error I know the data are structured fine, as I can use all the elements in individual xtabs()

Full_Name: Martin Lenze Version: 1.3.0 22.06.2001 OS: win32,x86 Submission from: (NULL) (194.221.251.1) As a newbie I'm not sure, whether this is a bug, but I don't know how to get around this behaviour: > x <- list("A"=rep(c(1:5),30), + "B"=c(rep(letters[1:3],30),rep(letters[2:4],20))) > y <- as.data.frame(x) > xtabs(~A+B,y) B A a b c d 1 6 10

Hi, I have large data frame with many columns. A short example is given below: > dataH host ms01 ms31 ms33 ms34 1 cattle 4 20 9 6 2 sheep 4 3 4 5 3 cattle 4 3 4 5 4 cattle 4 3 4 5 5 sheep 4 3 5 5 6 goat 4 3 4 5 7 sheep 4 3 5 5 8 goat 4 3 4 5 9 goat 4 3 4 5 10 cattle

Full_Name: Daniel Frey Version: 1.7.1 OS: Windows 2000 Submission from: (NULL) (80.254.164.242) Generating a data frame out of a xtabs result acts unusual. Take the following sample to reproduce it: > a.a <- c("a","a","a","b","b") > a.b <- c("c","c","d","e","f") >

I presume the behavior below (no Connector values in the second table) is because I have na values in my dataframe. How do I get them to list? I found references to na.action and na.pass, but I could not figure out how I could use them with xtabs to list the na as a value. I'm sure there's a simple syntax I need, but it's not obvious to me. > # Weighted Data