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rsync does not sync the timestamp on symlink (Solaris 8). It is probablly due to the limitation of Unix implementation of symlink, but I would like to know why rsync/Unix does not do this, and what we can do about it. Is the conclusion that "rsync syncs everything except the timestamp on symlink"? Why do I need timestamp on symlink? Supposed something stopped working because something

I've got a win98 laptop and a linux box. On my linux box, I smbmount a directory from the laptop. Alas, win98 boxes crash a lot, and I move the laptop a lot... to and from work. If the laptop crashes or if I move it with a shared directory mounted on my linux box, that mount gets "Stuck".... it's present in /etc/mtab but when I cd to it and do an ls it says: 243 emily ~>ls

I have written a function to plot data which will be used for various different chemistries. A simplified version is: plot_data <- function(risk,levels,chem,sd2,measure){ plot(risk, levels,main=paste ("per", sd2, measure, "\n in usual", chem)) } The problem is with the title. This works fine if the variable "chem" is just text, but if it is an expression then

Hi, please can you help me. When I add a legend to a boxplot it appears inside the plot area, how do you get it into the margins? I have already changed the parameters so there is space for it on the margin on the right hand side of the graph. Thanks, Emily [[alternative HTML version deleted]]

I'm trying to figure out if it's possible to use a character string as an equation, e.g: eqn1string <- "x^2 + x + 5" Then I want to tell R: 1) that eqn1string is actually an equation (even though it was stored as a character string), and 2) to apply the equation to a specified value of x (e.g. given x <- 6, what is the result of the equation). Thanks in advance for any

Hello. I apologize if there is a simple answer to this question, but I haven't been able to figure it out. Our people use various clients (pine 4.50 with maildir patch, eudora, messenger, outlook, squirrelmail), and all of them work with courier-imap. But I've become very interested in dovecot after reading about it, so I'm trying it out on another server. The results are mixed.

Hello, all I am building a R package using Fortran source code. The Fortran code is a subroutine. I can use "R CMD SHLIB bar.f -o bar.o" to create the shared library. For the R package, I put the fortran file in the src/ and I use R code as follows: ".First.lib"<-function(libname,pkgname){library.dynam("barpkg",pkgname,libname)} barfun<-function(n,x){

I thought replacing the spaces following instances of +++,++,+,- with "\n" and then reading with scan should succeed. Like Ivan Krylov I was fairly sure that you meant the minus sign to be "-" rather than "?", but perhaps your were using MS Word as an editor which is inconsistent with effective use of R. If so, learn to use a proper programming editor, and in any case

Awesome, thanks Arun, that's exactly what I was looking for! On Sat, Jan 26, 2013 at 9:21 PM, arun kirshna [via R] < ml-node+s789695n4656749h63@n4.nabble.com> wrote: > Hi, > Try this: > df[]<-lapply(df,as.character) > df2<-df > df[,1][grep("@",df$names)]<- "" > df > #names emails > #1 bob bobj@cup.com > #2

I have a data frame with three columns, one coded as a factor. I would like to separate my data out into separate data frames according to the factor level. Below is a simple example to illustrate. I can get R to return the data in the correct format but cannot work out how to get separate data frames. I am a newcommer to programming in R so am not sure what I am missing! Thanks, Emily

Hi, I'm new to R and I have a file with many rows of values. Each row contains a title and values for a contingency table e.g. row 1= title 8 0 37796 47 which is a table called 'title' with values 8 0 37796 47 I would like to know how I can import this using R and for each row calculate a p value using the fisher test. Using each p value I will do multiple a correction. I am

Dear all, I have many csv files whose contents I want to change a bit en masse. So far, I've written code that can change them in a for loop, like so: # Subset of files in the folder I want to change subset = "somestring" # Retrieve list of files to change filelist=list.files() filelist = filelist[grep(subset, filelist)] for(i in 1:length(filelist)){ setwd(readdir)

Hello List, ? I have a dataset consisting of strings that I want to split while saving the delimiter. ? Some example data: ?leucocyten + gramnegatieve staven +++ grampositieve staven ++? ?leucocyten ? grampositieve coccen +? ? I want to split the strings such that I get the following result: c(?leucocyten +?, ??gramnegatieve staven +++?, ??grampositieve staven ++?) c(?leucocyten ??, ?grampositieve

Dear R-Help, I am using the RDF package/ R 2.14 with the RDF package to download data from a website, and then use R to manipulate it. Text on the website is UTF-8. The RDF package's rdf_load command is converting it into a different encoding, which converts non-ASCII characters to unicode codes. On the webpage/sparql RDF: "4.5µg of cDNA was used" In R, the RDF triple gives:

Hi, I am very new to R and the stats world. I have enjoyed working with R so far but I have come across an error message in a very simple command that I am unable to resolve. I bring data in through excel .csv files and check them to be sure R reads them correctly and has everything assigned as it is in the excel file. It looks good. But simple computations are not working > sd(VIQ) Error

Good day, I need to subset a data by removing several rows. I know the %in% operator, i.e. sub <- mydata[group %in% c("A","B","E","G"), ] What I need is the opposite, that is remove rows and/or columns. What is the operator for "NOT IN"? I tried (i)! %in% and (ii) ^%in% and both resulted in a "could not find function" error.

Hello R Community, I am using the Lavaan package in R 2.15.0 to analyze data collected from 1200 lakes across North America. My dataset includes 3 continuous independent variables (LOG_NTL, LOG_PTL, and LOG_SR_A_D) and 1 continuous dependent variable (BIOVOL) . I have successfully constructed structural equation models using the Lavaan package (example included below with code), but I have not

Hi Dr. Snow, I am a graduate student working on analyzing data for my thesis and came across your post on an R forum: The default link function for the glm poisson family is a log link, which means that it is fitting the model: log(mu) ~ b0 + b1 * x But the data that you generate is based on a linear link. Therefore your glm analysis does not match with how the data was generated

Hello, I'd like to add labels to my plot that include a male or female symbol as subscript. I'm working in Windows Vista and R 3.0.0. I am able to add the male symbol to the plot as regular text (NOT as subscript), e.g. with: mtext("Male\u2642") This displays the word "Male" followed by the male symbol on the plot. But "\u2642" does not work when I try to

Dear Emily, Using a look-behind solves the split problem in this case. (Note: Using Regex is in most/many cases the simplest solution.) str = c("leucocyten + gramnegatieve staven +++ grampositieve staven ++", "leucocyten ? grampositieve coccen +") tokens = strsplit(str, "(?<=[-+])\\s++", perl=TRUE) PROBLEM The current expression does NOT work for a different