similar to: Echo cancelling results

>> Generate a test signal (10+x sine waves per frame), where x increases by >> one for each iteration, and wraps around at 100. > > Testing with sine waves is usually not a good idea. If you intend on > cancelling speech, then test with speech. Ok, I tested more extensively with both music and two-way speech. More on this below. >> However, when peeking at the

Hi, I'm still working on visualizing the echo canceller, but I discovered something that might be interresting. During testing, i did this: Generate a test signal (10+x sine waves per frame), where x increases by one for each iteration, and wraps around at 100. Set the speaker signal for the frame to the test signal. Add 0.5*test signal to the mic signal. When watching the power graph

Hi Ted, Thanks a lot for this analysis. > In FLOAT_DIVU() it hangs at the following: > while (a.m >= b.m) > { > e++; > a.m >>= 1; > } > for the case where a and b are both zero (yes, division by zero). > This happens from mdf.c: True, that needs to be fixed even after I fix the rest. > leak_estimate =

Just tried your files and I'm not running into any infinite loops and the cancellation works fine. Unless the C6x has the same problem, I suspect a 16-bit problem. I'll check and see if I find something. About the r=0 problem, I can't find where it ends up in a denominator, so I suspect is not (directly) the problem. Jean-Marc Le lundi 08 mai 2006 ? 20:05 -0400, Jim Crichton a ?crit

On Nov 26 22:39:27, hans at stare.cz wrote: > ./test_replaygain.sh fails for me in tonegenerator(), saying: > > ./test_replaygain.sh[91]: mawk: not found > Testing FLAC replaygain 8000 (8000 x 1) ... -: ERROR: got partial sample > > Apparently, the tone-generating awk script does not work with > my system's awk, which is "awk version 20110810" as distributed

Hi, there is an interesting case when the FLAC encoder (using 1.2.0) is given simple waves. Simple waves means: I have a list of {frequency, duration, pause} tuples that define the monophonic tune. In other words, exactly one frequency is played at a time. This is the original dataset from 1989 (driving a PC speaker back then): $ ls -l ihold.sd -rw-r--r-- 1 jengelh users 20616 Aug 14 00:57

Hi Folks, I am having trouble using speex_echo_cancel. As a starting point, I am using the testecho.c source code. I compiled the 1.2beta1 version. I have not tried any other versions of speex. The document says that the order of arguments to Speex_echo_cancel is (echo_state, input_frame, echo_frame, output_frame, residue) where "input_frame" is as captured from mic and

> I built and ran the same test on the TI C64 simulator, and the echo was > canceled nicely (about 10:1 reduction in the peak amplitude during the > second of two brief speech bursts). So, my problem must again be related to > the 16-bit processing on the C5X DSPs. Good. At least we've narrowed it down a bit. > Also, the line where it is hanging is: >

My tuneR sawtooth wave function generator is broken. When I use the sine function, I get exactly what I expect: a sine wave whose frequency is defined by the freq parameter. In particular, higher frequencies have shorter wavelengths (more cycles per second means shorter waves). When I create a sawtooth wave, the opposite seems to occur: higher frequencies result in longer waves. But that?s not

I have been attempting to estimate the periodic contribution of an effect to some data but have not been able to fit a sine wave within R. It would be nice to start by being able to fit a sine wave with an amplitude and frequency. x<-seq(0,20,by=0.5) y<-2*sin(2*pi*.5*x) #amplitude =2, frequency=0.5 # This failed to converge r<-nls(y ~ A*sin(2*pi*F*x), start=list(A = 1, F = 1),

Hi everyone, I am trying to fit a sine function on one year of wind data. I have two questions below. Looking around on the net I managed to get the following: Sine Equation: y = a + b * sin( c + d*x ) b is the amplitude, c is the phase shift, d is something deal with periodicty of data*.* This can be linearised by sin( c+dx ) = cos(c) * sin(dx) + sin(c) * cos(dx). If one calls dx = x1 y

Hi, For my VoIP application machine A sends speex encoded audio of to machine B and vice versa at. Data is captured in PCM 8Khz, 16 bit and then encoded using speex 1.1.12 The packet A played and the packet A captured through mic are the input to speex echo canceller. So I am trying to remove traces of packet A played from the captured data. I have followed example testecho.c All I hear is some

Jean-Marc, I have traced the second infinite loop further. When st->adapted becomes true (mdf.c line 623), the first Yf[i] value is 4, the leak_estimate is 0xd4e, the resulting r is 3. The first value in st->Rf is 0, so e is 1, and r is set to e>>1, or 0. A little later there is a divide by r, and there is the hang. It seems that the 0 in Rf[0] is the problem, but I am not

Ccing the maintainer if the tuneR package. Looks to me like sawtooth (and square) don't behave as expected when using xunit="samples". Workaround is to use xunit="time" instead: sawtooth(110,duration=1/100,samp.rate=sample_rate,xunit="time") I looked at the code but found it to be opaque. -- Sent from my phone. Please excuse my brevity. On November 12, 2017

Hi Jim, I've just been made aware of these problems (look for the thread "speex echo cancellation limitations"). It's on my short-term TODO list. > If fftwrap.c, I ifdefed out the spx_fft_float and spx_ifft_float routines, > because there were not used and required smallft.c (which is not so small at > all) to be added to the build. Right, need to cleanup that

I'm using nls to fit periodic gene-expression data to sine waves. I need to set the upper and lower boundaries, because I do not want any negative phase and amplitude solutions. This means that I have to use the "port" algorithm. The problem is, that depending on what start value I choose for phase, the fit works for some cases, but not for others. In the example below, the fit works

Hello. I'm from Federal University of Rio Grande do Sul - Brazil and I'm trying to adapt speex_echo.h (speex-1.2beta3-win32) to our video-conference software code. We are working on amplitude values, but I realised that in order to AEC works, one has to convert amplitude to frequency and filter the echo frequencies. So, my question is: Do I have to manually convert amplitude samples to

Dear R-users, I'd like to fit a sine function to my data. The result should have a format (and thus the formula, too) y ~ a + sin(x+b) where y and x are vectors, and a and b are (yet) unknown values. The data sets (vectors x and y) are OK, and I can do a simple lm fitting lm(y~x), or lm(y~I(sin(2*pi*x/360))), succesfully My issue is that I'm not able to do the optional linear shift in

I am using 'portaudio' and 'speex' to implement a speech audio capture/playback. Preprocess works fine but not the echo canceller (associated with preprocessor). I have read 'testecho.c' but it didn't help me. What I am doing bad? This is my implementation: One thread to capture and playback, both are different functions called in different times directly from

Hi, Is there a package to perform a sine function fitting to XY data? Thx, Ashz -- View this message in context: http://r.789695.n4.nabble.com/Sine-function-fitting-tp3000156p3000156.html Sent from the R help mailing list archive at Nabble.com.