similar to: Enabling Speex VBR for VoIP

Hi, I'm trying to cover all Speex configuration options to set quality/mode/bitrate in my application and I was wondering if the following all makes sense: - abr_bitrate - use average bitrate and set it using bitrate parameter - SPEEX_SET_ABR - cbr_bitrate - use constant bitrate and set it using bitrate parameter - SPEEX_SET_BITRATE - cbr_mode - use constant bitrate and

Jean-Marc Valin <jean-marc.valin at usherbrooke.ca> wrote: > > See the SPEEX_SET_VBR and SPEEX_SET_VBR_QUALITY options. But be aware > that unless you're aggregating many VoIP calls on the same link, there's > little use for VBR in VoIP. I don't agree with this. I've used Speex's VBR mode exclusively in my P2P VoIP software for the past 4 years and never

Hi all, I have a problem when I am encoding (or decoding) stereo audio. With mono data, things are fine and everything works without any problems. When I try to decode stereo data, all I get is a static sound - similar to that of a radio not tuned to any specific station. I wonder what might be wrong? Below is the code, first, of the encoder and next that of the decoder. Any information or

Ok, I finally got the slideshow code to a state worth showing it off. The site is a very rough cut of a site I''m building for my wife''s photography, so ignore the unfinished design for now :) http://rachel.kathihill.com/ To see the ajax version, go to: http://rachel.kathihill.com/?ajax=1 To randomize the order the images show: http://rachel.kathihill.com/?random=1 To change

Hi All, I want to take a simple random sample from a large dataset, gly, but I'm getting an error message. Any help? dim(gly) [1] 112371 37 > s1 <- sample(gly,100) Error in `[.data.frame`(x, .Internal(sample(length(x), size, replace, : cannot take a sample larger than the population when 'replace = FALSE' Thanks, Rachel [[alternative HTML version

On 2010-04-11 10:09, Randy Yates wrote: > If I specify VBR mode via > > speex_encoder_ctl(pSpeexEncoder, SPEEX_SET_VBR,&isTrue); Try: speex_encoder_ctl(pSpeexEncoder, SPEEX_SET_ABR, &desiredRate);

> 16 bit ints have a range of -32768 to 32767. If you divide > -32768 by 32767.0 you end up with -1.00003051850948 which > is a bad thing. > > Try normalizing with a value of 32768.0. No. Speex expects values in the +-32767 range, not +-1.0. Just converting from int16 to float *is* the right thing to do. Jean-Marc -- Jean-Marc Valin <Jean-Marc.Valin@USherbrooke.ca>

Quick question please....A user logs into windowsXP and tries to create a folder/document and the ownership on the new file/folder defaults to nobody:nobody. I have the user set up in samba on the IRIX machine. All other users have no problem. Anyone have any suggestions? Thanks Rachel

Hi All, I'm trying to automate a data summary using summary or describe from the HMisc package. I want to stratify my data set by patient_type. I was hoping to do something like: Describe(myDataFrame ~ patient_type) I can create data subsets and run the describe function one at a time, but there's got to be a better way. Any suggestions? Rachel [[alternative HTML

Hi there Probably a very simple solution to this problem. I have a character vector eg c("name1","name2","name3") and I want to pull out these columns from a data.frame, converting each of these columns into factors also. Many thanks Rachel -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

Hi, I am trying to create a function for a goodness-of-fit test for the Pareto Distribution for some loss data that I have. So far I have the following: function(X=OTOL) { n <- length(X)-1 #calculated the number of values (extra as 0 included) i <- 2:640 #values of i j <- 1:639 #values of i-1 Y <- (n-j+1)*((X[i])-(X[j])) #First part of GoF model Y } Where OTOL is the ordered loss

Hi All, I have a factor variable with 52 levels -with long, annoying names. I want to keep only rows with some variables. I can do this using this code: test1 <- subset(nih2009,ic_name %in% c('NATIONAL EYE INSTITUTE','Veterans Affairs')) dim(test1) [1] 2396 38 But this doesn't work: t1 <- subset(nih2009, ic_name %in% c(27,51)) dim(t1) [1] 0 38 I know

I have attempted to follow posting guidelines but I have failed to find out what I am doing wrong here. I am trying to use lines.survfit to plot a second curve onto a survival curve produced by plot.survfit. In my case this is to be a progression free survival curve superimposed upon an overall survival curve, but I will illustrate my problem using the example given in the help for

[global] workgroup = IIG netbios name = TUX server string = Samba Server interfaces = 192.168.0.10/24 update encrypted = Yes logon path = \\TUX\profile\%u logon drive = H: domain logons = Yes os level = 65 preferred master = Yes domain master = Yes wins server = 127.0.0.1 wins support = Yes

I''m a rails newb and have been Googling about this, but I''m still stumped. Not showing everything here, but basically it should be a pretty common setup so I''m sure others know what I''m doing wrong. - A meter can belong to many meter_groups - A meter_group can have many meters. - A user can ''subscribe'' to viewing a meter_group (Subscription)

Hi, I would like to view matrices I am working with in a clean, easy to read, separate window. A friend showed me how to do something like I want with edit(). I can view the matrix in the 'R Data Editor': For a sample matrix: > mat=matrix(1:15,ncol=3) > mat [,1] [,2] [,3] [1,] 1 6 11 [2,] 2 7 12 [3,] 3 8 13 [4,] 4 9 14 [5,] 5 10 15

Hi! Whenever I save a graphic in ps/eps format generated by filled.contour or image, an undesired grid is added to it (not visible on the X11 screen). For example: postscript("volcano.eps") filled.contour(volcano,col=gray(seq(0,1,,50)),levels=seq(min(volcano),max(volcano),,50)) dev.off() Any ideia how to eliminate this grid? Thanks, Rachel [[alternative HTML version deleted]]

I posted several months about the problem with adding tick marks to curves using lines.survfit. This occurs when lines.survfit is used to add a curve to survival curves plotted with plot.survfit. The help for this function implies that mark.time=TRUE thus: plot(pfsfit,conf.int=FALSE,xscale=365.25,yscale=100,xlab="Years",ylab="% surviving",lty=2,mark=3)

Hello, I am trying to deal with a database table that contains a date in the form of the number of seconds since epoch. Data is inserted in this format by an existing script that I can''t change, so a schema change isn''t realistic. I would like to allow humans to view and edit this data in the form of an actual human-readable date. I figured a facade column would be the

Hello, I was wondering if someone could tell me how I can make text dependent on a variable in a R function I have created. The function will create plots, thus I would like each plot to have a unique title based on the inputted variable as well as a unique file name when saved using the savePlot function. Thanks! Rachel