similar to: Has deleted user, why I can still get info of it

Displaying 20 results from an estimated 11000 matches similar to: "Has deleted user, why I can still get info of it"

2016 Dec 07
4
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OS: CentosOS 7 I have installed samba + openldap + smbldap-tools + pam by: yum --enablerepo=extras install -y epel-release yum install -y smbldap-tools yum install -y samba openldap openldap-clients openldap-servers migrationtools yum install -y nss-pam* I know that smbldap-tools is a dead project, but I'm interested in it and would like research on it. I create users and
2016 Dec 10
0
Has deleted user, why I can still get info of it
I made a mistake in my previous post. I deleted a user by: smbldap-userdel u1 My environment: Centos 7+samba +ldap+smbldap-tools +Pam Thanks On 12/10/2016 17:22, truename wrote: I del user 'u1': # userdel u1 But: # groups u1 u1 : g1 Is 'u1' delete? Thansk _______________________________________________ CentOS mailing list CentOS at centos.org
2016 Dec 04
2
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OS: CentosOS 7 I have installed samba + openldap + smbldap-tools + pam. I create users and groups by: sudo smbldap-groupadd -a g1 sudo smbldap-groupadd -a g2 sudo smbldap-useradd -a -P -g 1001 u1 sudo smbldap-useradd -a -P -g 1002 u1 groups u1 u1 : g1 groups u2 u2 : g2 I create shared folder: cd / sudo mkdir data sudo chown u1 /data sudo chgrp g1 /data sudo chmod ugo+rwx /data I edit
2016 Dec 04
4
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Hi Rowland, Could you refer me some online docs about AD domain? Thanks At 2016-12-04 17:23:48, "Rowland Penny via samba" <samba at lists.samba.org> wrote: >On Sun, 4 Dec 2016 16:57:56 +0800 (CST) >truename via samba <samba at lists.samba.org> wrote: > >> OS: CentosOS 7 >> >> I have installed samba + openldap + smbldap-tools + pam. > >I
2016 Dec 03
3
Why I can not login my shared folder under samba + CentOS 7
The result of accessing from windows is same as accessing from Linux, after I input correct username and password and click connect button, the login dialog re-popup. Thanks On 12/02/2016 22:22, Gaiseric Vandal via samba wrote: Can you access from windows? I also notice that samba 4.2.10 is no longer a supported version. On 12/01/16 15:39, truename via samba wrote: > Following is output
2012 Dec 06
1
Anomalous outputs from rbeta when using two different random number seeds
Hi, in the code below, I am drawing 1000 samples from two beta distributions, each time using the same random number seed. Using set.seed(80) produces results I expect, in that the differences between the distributions are very small. Using set.seed(20) produces results I can't make sense of. Around half of the time, it behaves as with set.seed(80), but around half of the time, it behaves
2007 Jun 01
1
Trying to define exclude with an include list
I need to backup a set of machines that are very similar in nature. I had created an exclude list to backup everything except whats in my list. I then used the --exclude-from=myexcludefile so rsync would not copy unwanted files. eg: /tmp /var/tmp /var/lock .... long list of others /u1 I have 2 drives on each machine and up until now I have no need to be backing up the 2nd drive. Thats what the
2020 Apr 29
1
grid 4.0 generates wrong results when adding two complex units by sum()
Hi, In grid 4.0, adding two complex units by `sum()` seems to give wrong results. In the following example, `u1 + u2` gives the correct result, but `sum(u1, u2)` also `sum(unit.c(u1, u2))` give the wrong results. ``` library(grid) u1 = 0.4*sum(unit(1, "inch"), unit(1, "mm")) u2 = 0.1*sum(unit(1, "inch"), unit(1, "mm")) u1 # [1] 0.4*sum(1inches, 1mm)
2009 Feb 05
1
optimal control, maximization with several variables?
Dear all, I would like to solve the following problem, which can be done with optimal control theory or dynamic programming: max(x,y) a*u1+b*u2+c*f1(u2) s.t. 0<u1<x, 0<u2<f2(x,u2), x'=f3(u1,u2,x) which can be rewritten if optimal control theory should be applied as H=a*u1+b*u2+c*f1(u2)+lambda*(x') s.t. 0<u1<x, 0<u2<f2(x,u2) The maximum principle
2018 Mar 12
0
subsetting comparison problem
> On Mar 11, 2018, at 3:32 PM, Neha Aggarwal <aggarwalneha2000 at gmail.com> wrote: > > Hello All, > I am facing a unique problem and am unable to find any help in R help pages > or online. I will appreciate your help for the following problem: > I have 2 data-frames, samples below and there is an expected output > > R Dataframe1: > C1 C2
2008 Jan 16
3
Rmpi on Linux x86_64 GNU/Linux
I'm having trouble with R CMD INSTALL Rmpi_0.5-5.tar.gz --configure-args=~/lam lam is is installed locally. lamboot -d (or lamboot-d and also recon) works. make -k check from the lamtest suite passes all tests. Is this is problem with the -fPIC compiler as in the message? Should it be modified in the Makefile? Any help or comments are appreciated, thanks. * Installing to library
2007 May 09
3
The 'h' extension problem
Hi all, There is a problem with my dialplan. here is the dialplan: exten=> 123,1,Dial(SIP/U1,,Ttg) exten=> 123,2,Hangup exten=> h,1,AGI(onhangup.pl) The problem is whenever U1 is called or calls someone, if U1 hangsup the call then the h extension is NOT executed. but if the other person hangsup the call, then the h extension is executed (assuming that the other person is calling
2008 Dec 19
4
only root without password
Hi all, I have a very strange problem with the public key authentication with 2 machines. I generated the key, configured the authorized_keys etc.. etc.. This is all ok, now: The ssh works without the password for the "root" user, any other user cannot use the key and ssh ask me for the password !! I cannot understand why only the root is able to connect without the password. So, the ssh
2007 Nov 20
2
Rsync and snapshot backups
I'm currently using rsync to backup home directories using this: rsync -avx --delete --backup --backup-dir=/u1/home.bak /u0/home/ /u1/home >> ${log} I'm trying to move to snapshot backups using this: rsync -avx --delete --backup --backup-dir=/u1/home.bak --link-dest=../home.current /u0/home/ /u1/home_${datetime} >> ${log} This works except I no longer get deleted source
2011 Jan 27
2
help for a loop procedure
Hello everybody! I’m trying to define the optimal number of surveys to detect the highest number of species within a monitoring season/session. To do this I want to run all the possible combinations between a set of samples and to calculate the total number of species for each combination of 2, 3, 4 …n samples events, so that at the end I will be able to define which is the lowest number of
2014 Nov 18
2
Change Objects on 2 DCs without connection
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hello, I like to know what will happend if: - - one Domain with 2 DCs - - two Admins working on their Windows-ws with RSAT. - - Admin1 is connected to DC1 - - Admin2 is connected to DC2 - - Admin1 creats a user "u1" and a group "g1" - - then the two DCs will lose connection, the user and group is replicated to DC2 - - now Admin1
2006 Nov 21
2
Symbolic derivation using D in package stats - how do I properly convert the returned call into a character string?
Dear all, I am using the function 'D' in the 'stats' package to perform symbolic derivation. This works very well and it is much faster than e.g. Mathematica (at least for my purposes). First, I would like to thank the development team for this excellent function. However, I run into trouble in some cases, particularly when I am to do some operations on long expressions
2007 Apr 20
1
Estimating a Normal Mixture Distribution
Hi everyone, I am using R 2.4.1 on a MacOS X ("Tiger") operating system. In the last few day I was trying to estimate the parameters of a mixture of two normal distributions using Maximum Likelihood. The code is from Modern Applied Statistics with S (4th edition), chapter 16 ("Optimization"), the dataset is available under MASS in R. Unfortunately, when I tried out the
2003 Oct 29
1
grid: dividing units by numbers
How can I divide a unit by an number or average a vector of units, e.g.: u1 <- unit( 3, 'npc' ) u2 <- unit( 6, 'npc' ) u1 / 2 ( u1 + u2 ) / 2 mean( unit.c(u1,u2) ) I would use that e.g. to to calculate the coordinates of the midpoint of a line. Wolfram
2011 Sep 11
3
(no subject)
Dear all, Can anyone take a look at my program below? There are two functions: f1 (lambda,z,p1) and f2(p1,cl, cu). I fixed p1=0.15 for both functions. For any fixed value of lambda (between 0.01 and 0.99), I solve f1(p1=0.15, lambda=lambda, z)=0 for the corresponding cl and cu values. Then I plug the calculated cl and cu back into the function f2. Eventually, I want to find the lambda value