Displaying 20 results from an estimated 3000 matches similar to: "CentOS-6 - LogWatch"
2005 Apr 15
2
Logwatch
Having FC3 systems and utilizing Dovecot, I have come to rely on some of
the information I get from the daily logwatch run.
Logwatch, by default, doesn't properly recognize dovecot's information
in the messages file, but it is easy to tweak. The patch below will
give you some statistics regarding POP3 and IMAP usage.
I believe I grabbed all of the differences in the unified diff
2012 Oct 31
2
Aggregate Table Data into Cell Frequencies
R-help -
I have this set of aggregated tables (sample data below via dput()). And I
would like to have delayValue as the column variables with the "temp"
(temp1, temp2, temp3) values as the row variables. However I would like to
have the temp variables *aggregated into single rows* so that I have the
frequency ("Freq" | counts) of each time each "delayValue" occurs
2006 Apr 12
1
yet another problem with S4 dispatch (with setClassUnion)
Dear John and Seth, dear R-devels,
once again the question of method dispatch in S4 -- this time with
setClassUnion(); taking up your advice in
https://stat.ethz.ch/pipermail/r-devel/2006-April/037200.html
https://stat.ethz.ch/pipermail/r-devel/2006-April/037201.html
I have been too quick in stating that
>setClassUnion()---at least in my case---solves the problem;
>
The problem arises
2006 Jan 04
3
matrix math
I am using R 2.1.1 in an windows XP environment.
I have 2 dataframes, temp1 and temp2.
Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric.
I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe.
(i.e. temp1$column
2010 Oct 17
4
how to convert string to object?
temp = "~aparch("
temp1 = paste(temp,1, sep = "")
temp2 = paste(temp1,1, sep = ",")
temp3 = paste(temp2, ")",sep = "")
temp 3 is a character but I want to convert to formula object. How do I do
this?
--
View this message in context: http://r.789695.n4.nabble.com/how-to-convert-string-to-object-tp2999281p2999281.html
Sent from the R help mailing
2010 Nov 19
3
Sweave Dynamic Graph Question
i have a time Series of IBM closing px from 1/1/2000 to today
I want to graph the time serie by dividing the graph by year and month
all the monthly graphs with the same year will go to one page. so from
1/1/2000 to 11/19/2010. i will have
11 pages, and each page will have 12 graphs (jan to dec) except for 2010.
I am able to do it in R, but when i use sweave, I can only print the last
page.
2015 Sep 17
0
CentOS-6 - LogWatch Cyrus-IMAPD script was CentOS-6 - LogWatch
On Mon, September 14, 2015 14:51, James B. Byrne wrote:
> The Logwatch imapd service script distributed with CentOS-6 does not
> generate anything when I run logwatch --service all on a cyrus-imapd
> host. Is this expected behaviour? Is there a separate script for
> cyrus-imapd or are their configuration options required to get the
> existing script to work.
>
> I have found
2011 Mar 09
2
Anomaly with unique and match
I stumbled onto this working on an update to coxph. The last 6 lines
below are the question, the rest create a test data set.
tmt585% R
R version 2.12.2 (2011-02-25)
Copyright (C) 2011 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: x86_64-unknown-linux-gnu (64-bit)
# Lines of code from survival/tests/singtest.R
> library(survival)
Loading required package: splines
2013 Jan 28
6
Thank you your help.
Hi,
temp3<- read.table(text="
ID CTIME WEIGHT
HM001 1223 24.0
HM001 1224 25.2
HM001 1225 23.1
HM001 1226 NA
HM001 1227 32.1
HM001 1228 32.4
HM001 1229 1323.2
HM001 1230 27.4
HM001 1231 22.4236 #changed here to test the previous solution
",sep="",header=TRUE,stringsAsFactors=FALSE)
?tempnew<- na.omit(temp3)
?grep("\\d{4}",temp3$WEIGHT)
#[1] 7 9 #not correct
2013 Mar 07
5
multiple plots and looping assistance requested (revised codes)
Hi Irucka,
I tried it and was able to plot it without any errors.? Here, your code indicates you need two lines. temper[[i]][1]
?temper[[1]][1] # which is the column 1.
? Month
1???? 1
2???? 2
3???? 3
?temper[[1]][2]
#? Data1
#1?? 1.5
#2? 12.3
#3? 11.4
Suppose I use names(temper) instead of seq_along(temper)
pdf("irucka.pdf")
?lapply(names(temper),function(i)
2005 Dec 29
1
Problems with calloc function.
Hi all,
I have a C code in Linux, it has 7 pointers and compile e run OK, but when I
run in R happens problems with calloc function, it returns NULL.
###############################################
> int *temp1,*temp2,*temp3,*temp4;
temp1 = (int *)calloc(col,sizeof(int));
if(temp1 == NULL){
printf("\n\n No Memory1!");
exit(1);
}
temp2 = (int *)calloc(col,sizeof(int));
2013 Mar 29
1
multiple plots and looping assistance requested (single plot)
HI Irucka,
Please check this:
temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L,
2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342,
12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA,
-4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L,
3L, 4L, 5L, NA), Data1 = c(1.52,
2013 Jan 18
1
5.9 logwatch yum filter broken
After the upgrade to CentOS 5.9, all my CentOS 5 installations
report only "Unmatched Entries" in the "yum" section of their
daily logwatch mails. It seems the filter script
/usr/share/logwatch/scripts/services/yum got broken:
--------8<--------8<--------8<--------8<--------8<--------8<--------8<
[root at dns01 ~]# /usr/sbin/logwatch --print --service yum
2003 Nov 18
4
logwatch
Hi All,
I need to be able to make sense from my shorewall logs.
I have installed logwatch and it is mailing me reports but the level of
detail is just not there. I have set the detail variable to High=10 but
I get entries only from the DNS service about denied updates. What am I
getting wrong? Tom, will you be kind enough to send me your logwatch
config files?
Thanks in advance.
Ama
2012 Mar 29
1
Error, Variable is Missing
Hi, I am writing a function to plot a pdf of a distribution,
GNL.pdf.fn = function(x,mu,sigma,alpha,beta,rho)
{
y = x-rho*mu
cf.fn = function(s){
cplex = complex(1,0,1)
temp1 = alpha*beta*exp(-sigma*s^2/2)
temp2 = (alpha-cplex*s)*(beta+cplex*s)
out = (temp1/temp2)^rho
out
}
temp.fn = function(s){
(Mod(cf.fn(s)))*cos(Arg(cf.fn(s))-s*y)
}
int.fn =
2025 Jan 28
1
R CMD check says no visible binding for global variable
Naresh,
I am not sure how you are creating your data.frame so it has no, I think, column names. There are two scenarios including one where it is not really a valid data.frame and one where it can be handled before any other use as shown below. If it cannot be used, you might need to modify how your SQL or the function you call creates it so it includes either names it chooses or that you supply.
2025 Jan 27
2
R CMD check says no visible binding for global variable
I have written a function which returns an SQL query result as a data.frame. Each column of data.frame is a variable not explicitly defined.
For every column name, R CMD check says ?no visible binding for global variable <name>. Status: 1 NOTE
Is it possible to tell R CMD check that these variables are OK?
Thanks,
Naresh
Sent from my iPhone
2025 Jan 28
2
R CMD check says no visible binding for global variable
Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns.
Something like:
Myquery <- ?SELECT date, price, stock FROM stocktab WHERE stock = ?ABC? AND date > ?2025-01-01?;?
Prices <- dbGetQuery(con, myquery)
SetDT(Prices)
Prices[, date = as.Date(date)]
R CMD check say ?no visible binding for global variable ?date??
Sent
2012 Jul 14
2
Loading in Large Dataset + variables via loop
Hello, I'm new to R with a (probably elementary) question.
Suppose I have a dataset called /A/ with /n/ locations, and each location
contains within it 3 time series of different variables (all of 100 years
length); each time series is of a weather variable (for each location there
is a temperature, precipitation, and pressure). For instance, location 1
has a temperature1 time series, a
2009 Aug 21
2
"Special" LS estimation problem
Hi, I have following kind of model : Y = X1 * a1 + X2 * a2 + error
Here sampled data for Y, X1, X2 are like that :
Y <- replicate(10, matrix(rnorm(2),2), simplify = F)
X1 <- replicate(10, matrix(rnorm(4),2), simplify = F)
X2 <- replicate(10, matrix(rnorm(4),2), simplify = F)
My goal is to calculate LS estimates of vectors "a1" and "a2". Can anyone
please guide me