Displaying 20 results from an estimated 3000 matches similar to: "removing keys from ssh-agent without having key file"
2015 May 29
16
Call for testing: OpenSSH 6.9
Hi,
OpenSSH 6.9 is almost ready for release, so we would appreciate testing
on as many platforms and systems as possible. This release contains
some substantial new features and a number of bugfixes.
Snapshot releases for portable OpenSSH are available from
http://www.mindrot.org/openssh_snap/
The OpenBSD version is available in CVS HEAD:
http://www.openbsd.org/anoncvs.html
Portable OpenSSH is
2015 Jan 23
5
[Bug 2342] New: ssh-keygen gives wrong error loading public key message
https://bugzilla.mindrot.org/show_bug.cgi?id=2342
Bug ID: 2342
Summary: ssh-keygen gives wrong error loading public key
message
Product: Portable OpenSSH
Version: 6.7p1
Hardware: Other
OS: Linux
Status: NEW
Severity: enhancement
Priority: P5
Component: ssh-keygen
2015 Feb 20
2
Call for testing: OpenSSH 6.8
On Fri, 20 Feb 2015, ?smail D?nmez wrote:
> Hi,
>
> On Fri, Feb 20, 2015 at 12:21 AM, Damien Miller <djm at mindrot.org> wrote:
> > Hi,
> >
> > OpenSSH 6.8 is almost ready for release, so we would appreciate testing
> > on as many platforms and systems as possible. This release contains
> > some substantial new features and a number of bugfixes.
>
2006 Mar 11
1
Non-linear Regression : Error in eval(expr, envir, enclos)
Hi..
i have an expression of the form:
model1<-nls(y~beta1*(x1+(k1*x2)+(k1*k1*x3)+(k2*x4)+(k2*k1*x5)+(k2*k2*x6)+(k3*x7)+(k3*k4*x8)+(k3*k2*x9)+(k3*k3*x10)+ (k4*x11)+(k4*k1*x12)+(k4*k2*x13)+(k4*k3*x14)+(k4*k4*x15)+(k5*x16)+(k5*k1*x17)+(k5*k2*x18)+(k5*k3*x19)+
2010 Aug 20
5
paired samples, matching rows, merge()
Hi everyone!
I'm matching two samples to create one sample that have
pairs of observations equal for the k1 variable. Merge()
doesn't work because I dont't want to recycle the values.
x <- data.frame(k1=c(1,1,2,3,3,5),
k2=c(20,21,22,23,24,25))
x
y <- data.frame(k1=c(1,1,2,2,3,4,5,5),
k2=c(10,11,12,13,14,15,16,17))
y
merge(x,y,by="k1")
k1 k2.x k2.y
1 1 20
2007 Aug 14
2
State Space Modelling
Hey all,
I am trying to work under a State Space form, but I didn't get the help
exactly.
Have anyone eles used this functions?
I was used to work with S-PLUS, but I have some codes I need to adpt.
Thanks alot,
Bernardo
[[alternative HTML version deleted]]
2010 Dec 15
5
Solution to differential equation
Hello,
I am trying to find the analytical solution to this differential equation
dR/dt = k1*(R^k2)*(1-(R/Rmax)); R(0) = Ro
k1 and k2 are parameters that need to fitted, while Ro and Rmax are the
baseline and max value (which can be fitted or fixed). The response (R)
increases
initially at an exponential rate governed by the rate constants k1 and k2.
Response has a S-shaped curve as a function
2009 May 13
2
ode first step
Hi all,
I try to assess the parameters (K1,K2) of a model that describes the
adsorption of a molecule onto on adsorbent.
equation: dq/dt = K1*C*(qm-q)-K2*q
I know the value of 'qm' and I experimentally measure the variables 'q',
'C', and the time 't'.
t C q
1 0 144.05047 0.0000000
2 565 99.71492 0.1105625
3 988 74.99426
2012 Mar 02
5
Calculation of standard error for a function
Dear list,
If I know the standard error for k1 and k2, is there anything I can call in
R to calculate the standard error of k1/k2? Thanks.
Jun
[[alternative HTML version deleted]]
2007 Oct 23
1
How to avoid the NaN errors in dnbinom?
Hi, The code below is giving me this error message:
Error in while (err > eps) { : missing value where TRUE/FALSE needed
In addition: Warning messages:
1: In dnbinom(x, size, prob, log) : NaNs produced
2: In dnbinom(x, size, prob, log) : NaNs produced
I know from the help files that for dnbinom "Invalid size or prob will
result in return value NaN, with a warning", but I am not able
2014 Dec 04
2
[PATCH v2] v2v: When picking a default kernel, favour non-debug kernels over debug kernels (RHBZ#1170073).
---
v2v/convert_linux.ml | 18 +++++++++++++++---
1 file changed, 15 insertions(+), 3 deletions(-)
diff --git a/v2v/convert_linux.ml b/v2v/convert_linux.ml
index f670812..39a520c 100644
--- a/v2v/convert_linux.ml
+++ b/v2v/convert_linux.ml
@@ -49,13 +49,14 @@ type kernel_info = {
ki_modules : string list; (* The list of module names. *)
ki_supports_virtio : bool; (* Kernel has
2018 Feb 25
3
include
Thank you Jim,
I read the data as you suggested but I could not find K1 in col1.
rbind(preval,mydat) Col1 Col2 col3
1 <NA> <NA> <NA>
2 X1 <NA> <NA>
3 Y1 <NA> <NA>
4 K2 <NA> <NA>
5 W1 <NA> <NA>
6 Z1 K1 K2
7 Z2 <NA> <NA>
8 Z3 X1 <NA>
9 Z4 Y1 W1
On Sat, Feb 24, 2018 at 6:18 PM, Jim
2018 Feb 25
2
include
HI Jim and all,
I want to put one more condition. Include col2 and col3 if they are not
in col1.
Here is the data
mydat <- read.table(textConnection("Col1 Col2 col3
K2 X1 NA
Z1 K1 K2
Z2 NA NA
Z3 X1 NA
Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE)
The desired out put would be
Col1 Col2 col3
1 X1 0 0
2 K1 0 0
3 Y1 0 0
4 W1 0 0
6 K2 X1
2004 Oct 04
3
Beginners problem
Hi,
I'm new to R and have a problem with a little test program (see below).
Why doesn't <<- in function rk4
assign the new value to y so that it is seen in rktest. I thought that
<<- does exactly this. But it seems that I
didn't get it right. I would be very appreciative for an explanation of
that behaviour of <<-. I know how to
write the whole thing so that it
2009 Aug 03
3
Help with reshaping data.frame
I'm having trouble reshaping a data.frame from long to wide.
(I think that's the right terminology; feel free to educate me.)
I've looked at the reshape function and package and plyr package,
but I can't quite figure out how to do this after a dozen variations.
I have a data.frame with more levels than this, but similar to:
> tst
K1 K2 K3 V1 V2 V3
1 10 D a 0.08 99
2013 May 07
2
recode categorial vars into binary data
Dear R-List,
I would like to recode categorial variables into binary data, so that all values above median are coded 1 and all values below 0, separating each var into two equally large groups (e.g. good performers = 0 vs. bad performers =1).
I have not succeeded so far in finding a nice solution to do that in R. I thought there might be a better way than ordering each column and recoding the
2013 May 07
2
recode categorial vars into binary data
Dear R-List,
I would like to recode categorial variables into binary data, so that all values above median are coded 1 and all values below 0, separating each var into two equally large groups (e.g. good performers = 0 vs. bad performers =1).
I have not succeeded so far in finding a nice solution to do that in R. I thought there might be a better way than ordering each column and recoding the
2018 Feb 25
0
include
Hi Val,
My fault - I assumed that the NA would be first in the result produced
by "unique":
mydat <- read.table(textConnection("Col1 Col2 col3
Z1 K1 K2
Z2 NA NA
Z3 X1 NA
Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE)
val23<-unique(unlist(mydat[,c("Col2","col3")]))
napos<-which(is.na(val23))
preval<-data.frame(Col1=val23[-napos],
2008 Feb 01
2
the "union" of several data frame rows
Hi,
I have a question about how to obtain the union of several data frame
rows. I'm trying to create a common key for several tests composed of
different items. Here is a small scale version of the problem. These
are keys for 4 different tests, not all mutually exclusive:
id q1 q2 q3 q4 q5 q6
1 A C
2 B D
3 A D B
4 C D B D
I would like
2004 Jan 30
1
MATLAB to R
Ladies and Gentlemen,
In MATLAB, I can write:
for J=1:M
Y(J+1)=Y(J)+ h * feval(f,T(J),Y(J));
...
In R, I can write above as:
for (J in 2:M)
{
y = y + h * f(t,y)
...
}
----
In MATLAB, I can write:
for J=1:M
k1 = feval(f,T(J),Y(J));
k2 = feval(f,T(J+1),Y(J)+ h * k1
How do I write k2 in R?
k1 = f(t,y)
k2 = ?
Thanks,
/oal