similar to: Replacing a function from one module into another one

Hello and thanks for the answer, I'm still facing issues, I'll do my best to explain my situation, as I explained, I have two modules, each one with its own main and functions, I would like to replace in the *oldModule* a function call that is calling *foo2* (defined in *oldModule*) to instead call *foo3*, which is defined in the *refModule. *So in summary, I have: 1. The original

Hi Ahmad, What does that tool does besides what LLVM linker already does? I don't think my problem is in linking both modules, I think LLVM linker does the job for me, the issue is when changing the called function to call another function (in the example previously provided, to change it from foo2 to foo3, and adjusting the function parameter's references). Regards, Daniel Moya El

Thank you Ahmad, I figured out that, although the type of both p(oInst) and p(nInst) were the same, I had to: for (unsigned int i = 0; i < callOInst->getNumArgOperands(); i++) { callOInst->getArgOperand(i)->mutateType(callNInst->getArgOperand(i)->getType()); } that solves the issue at the calling instruction in the main function, but now I see that *linkModules* does not work

Hi Philip, Thank you very much for your answer, the vector declaration example worked. I'm pretty sure the ValueToValueMapTy is the last thing I need because I even saw there is another function that could help me llvm*:*:RemapFunction <http://llvm.org/doxygen/namespacellvm.html#addf0183e92893bdbcde00fc9091dda93>; but my problem is that I don't know how to populate the

Hi Philip, Thanks for the reference, I was able to follow it and copy the code that I saw necessary, but I still have some issues (references are still not updated). I created the function: void populateVMap(llvm::ValueToValueMapTy &VMap, llvm::Function *fOld, llvm::Function *fNew) { llvm::Function::arg_iterator DestI = fOld->arg_begin(); for (llvm::Function::const_arg_iterator J =

Hi Philip, The error happens when the program finishes and it automatically calls the destructors, so it is not an error specifically inside my program. Here's the full code: #include "llvm/ExecutionEngine/ExecutionEngine.h" #include "llvm/ExecutionEngine/MCJIT.h" #include "llvm/IRReader/IRReader.h" #include "llvm/Support/TargetSelect.h" #include

Thank you very much for your useful suggestions. These are exactly what I was looking for. foo <- list(foo1, foo2, foo3) lapply(foo, function(x) matrix(unlist(x), nrow = length(x), byrow = TRUE)) or lapply(foo, function(x) do.call('rbind', x)) Best, Muhammad Subianto On 4/11/06, Muhammad Subianto <msubianto at gmail.com> wrote: > Dear all, > I have a result my experiment

Dear all, I have a result my experiment like this below (here my toy example): foo1 <- list() foo1[[1]] <- c(10, 20, 30) foo1[[2]] <- c(11, 21, 31) foo2 <- list() foo2[[1]] <- c(100, 200, 300) foo2[[2]] <- c(110, 210, 310) foo3 <- list() foo3[[1]] <- c(1000, 2000, 3000) foo3[[2]] <- c(1100, 2100, 3100) list(foo1,foo2,foo3) The result: > list(foo1,foo2,foo3) [[1]]

Dear List: In short, I am writing a number of functions as building blocks for other functions and have some questions about scoping and passing arguments. Suppose I have functions foo1, foo2, and foo3 such that: foo1<-function(a=1,b=TRUE,c=FALSE){#do stuff}; foo2<-function(x=1,y=FALSE,z=c(1,2,3,4)){#do stuff}; foo3<-function(lambda,...){lambda*foo1()*foo2()}; I want to be able to

I have a general style question about R coding. Suppose I'm writing a function (foo1) that calls other functions (foo2, foo3, ...) which have complicated argument lists (e.g. optim(), plot()), _and_ I may be calling several different functions in the body of foo1. Since foo2 and foo3 have different sets of arguments, I can't just use "..." ; I did write some code a while ago

Hi all, For some reason, I would like to use functions bellow (see example code bellow), but instead I get the following error message: *Error in foo2(...) : unused argument(s) (arg3 = 3)* #--------------------- # example code #--------------------- foo1 <- function(arg1,...) { print(arg1) foo2(...) foo3(...) } foo2 <- function(arg2) { print(arg2) } foo3 <- function(arg3) {

i believe the following is true but would appreciate confirmation that it is intended behavior and will continue: if a default argument is employed in the definition of a generic function, and the generic is called with the argument in question (call it 'ARG') missing, then the method for signature (..., ARG = "missing", ...) will be called by 'standardGeneric'

Hi the list In the DESCRIPTION file of my package foo0, I have: Depends: foo1 Imports: foo2 Suggest: foo3 Enhence: foo4 If I understand correctly, to install foo0 on my computer, I need to already have foo1, foo2, foo3. foo4 is not necessary. I my R sesssion, when I will write: library(foo0), then the package foo1 will be attach. foo2, foo3 and foo4 will not. Is that correct? But what is

My apologies for asking what is doubtless a dumb question, but I have scant experience in R. It would be very convenient in doing lots of plots to be able to do them in a loop that stepped through a vector of variable names. For example one could say x<-("mydates") y<-c("foo1","foo2","foo3") #where "foon" were vectors

I have the following list of strings: x <- c("foo, foo2, foo3", "bar", "qux, qux1") what I want to do is to obtain foo, bar qux Namely for each element in the vector obtain only string before the first comma. What's the way to do it? - G.V. [[alternative HTML version deleted]]

Hi, this relates to the question "How to set a former environment?" asked yesterday. What is the best way to to return a function with a minimal environment from a function? Here is a dummy example: foo <- function(huge) { scale <- mean(huge) function(x) { scale * x } } fcn <- foo(1:10e5) The problem with this approach is that the environment of 'fcn' does not

Hi all, Working with S4 object, I definine two class foo1 and foo2. I define '[' (resp. '[<-') for the two classes. Then I define a third class foo3 that inherit from both foo1 and foo2. Is there a way to make '[' (resp. '[<-') for foo3 inherit from '[' (resp. '[<-') for foo1 and foo2? Thanks Christophe

Hi to all Authors@R: c(person("fooa","foob", role = c("aut","cre"), email = "fooa.foob@fooc.de"), person("foo1","foo2", role = c("ctb"), email = "foo1.foo2@foo3.de")) Author: fooa foob, with contributions from foo1 foo2 using r CMD check --as-cran .. (R 3.1

Let's say I have, for some reason, a bunch of scalars (i.e. single-valued variables) and I want to merge them all into a single vector of values. Can someone recommend a better function, or simpler way, to do so than the following? Suppose my scalars' names are foo1, foo2, foo3, foo1high, foo2high, foo3lo2, etc. Then I can do: >ls(pat='foo')->thels

Hello, This is my first post to the help request list, so I'm going to err on the side of giving too much information. I'm working on writing a simulation in which agents will make repeated production and exchange decisions with randomly chosen partners. The idea is, all agents can produce two goods which they want to consume, they choose a value t in [0,10] which sets their production