Displaying 20 results from an estimated 80 matches similar to: "[LLVMdev] Strange code generation issue"
2015 Feb 23
3
[LLVMdev] Eliminating redundant loads
On 23 February 2015 at 01:29, Kamal Sharma <kgs1.rice at gmail.com> wrote:
> Hi Dibyendu,
>
> It would be very helpful if you could post the original source code or
> snippet.
> That way, one can investigate deeper to understand the problem.
>
> Regards,
> Kamal Sharma
>
Hi Kamal,
Sure. I guess I ought to create a test that one can look in isolation.
I am
2015 Feb 22
2
[LLVMdev] Eliminating redundant loads
On 22 February 2015 at 20:58, David Jones <djones at xtreme-eda.com> wrote:
> Not sure if this is your problem, but it was mine:
>
> You must create (or obtain) a DataLayout *and install it into the Module*.
>
> It is possible to generate machine code for IR and not install the
> DataLayout into the Module. Rather, the DataLayout is used locally at the
> point where code
2015 Feb 22
2
[LLVMdev] Eliminating redundant loads
Hi,
I am generating following code:
%base = getelementptr inbounds %ravi.CallInfo* %6, i32 0, i32 4, i32 0
%7 = load %ravi.TValue** %base
%8 = bitcast %ravi.TValue* %7 to i8*
%9 = bitcast %ravi.TValue* %5 to i8*
call void @llvm.memcpy.p0i8.p0i8.i32(i8* %8, i8* %9, i32 16, i32 8, i1 false)
%10 = load %ravi.CallInfo** %L_ci
%base1 = getelementptr inbounds %ravi.CallInfo* %10, i32 0,
2015 Feb 23
2
[LLVMdev] Eliminating redundant loads
On 22 February 2015 at 22:54, Hal Finkel <hfinkel at anl.gov> wrote:
>> I tried setting the module's DataLayout to the engine's DataLayout.
>> Don't see any improvement.
>> The memcpy() is to perform a struct assign, so I tried replacing that
>> with member by member store.
>> But even then the loads are not being eliminated so I guess the
>>
2007 Jun 20
2
Extracting t-tests on coefficients in lm
I am writing a resampling program for multiple regression using lm(). I
resample the data 10,000 times, each time extracting the regression
coefficients. At present I extract the individual regression
coefficients using
brg = lm(Newdv~Teach + Exam + Knowledge + Grade + Enroll)
bcoef[i,] = brg$coef
This works fine.
But now I want to extract the t tests on these coefficients. I cannot
2009 Mar 24
4
multiple paired t-tests
Hi R users,
I have a very large data set that has two conditioning variables for the
test I want to perform.
A toy set can be simulated:
type<-sample(1:3,100,replace=TRUE)
class<-sample(1:20,100,replace=TRUE)
value<-rnorm(100)
data<-cbind(type,class,value)
(though type and class are alphanum)
I want to perform the three pair-wise t-tests between types for each
class in data.
Can
2018 Feb 04
1
Unexpected behaviour from read.table
I?ve been struggling with seemingly ?corrupt? data.frames for a few days, and believe I?ve narrowed the problem down to some odd behaviour from read.table
I receive a tab delimited file from an external provider where strings are encoded as =?content?. Not sure why, perhaps as most users open it in Excel.
My specific issue is that trailing spaces in any of the strings are causing strange results
2007 Jul 17
1
A simple question
Hi all,
I am a newbie of R, and have a very simple question. When I run the
following t test
result = t.test(weight ~ group)
If I want to get the t value, I can do
tvalue = result$statistic
with tvalue being the following:
t
1.191260
However, if I just want the number 1.191260, not the character "t",
how can I achieve that?
Thank you very much,
Gang
2009 Jan 14
5
How to compute p-Values
Hello.
How can I compute the Bootstrap p-Value for a one- and two sided test, when I have a bootstrap sample of a statistic of 1000 for example?
My hypothesis are for example:
1. Two-Sided: H0: mean=0 vs. H1: mean!=0
2. One Sided: H0: mean>=0 vs. H1: mean<0
I hope you can help me
Thanks in advance
Regards,
Andreas
2013 Oct 18
1
No P.values in polr summary
Hi everyone,
If I compute a "Ordered Logistic or Probit Regression" with the polr
function from MASS package. the summary give me : coefficients, Standard
error and Tvalue.. but not directly the p.value.
I can compute "manualy" the Pvalue, but Is there a way to directly obtain
the pa.value, and I wonder why the p.valeu is not directly calculated, is
there a reason?
exemple
2012 May 10
1
Error t value matrix
Hi all,
I want to make the following:
I want to run a linear regression on each column of a matrix "estima" on
the correspondent column on the matrix "estima2".
You see I want to regress estima[,1] on estima2[,1] this way to all
columns....
At the same time I want to make a regression adding each time a new
observation.
You see, the first regression will regress only one
2009 Nov 04
1
vglm(), t values and p values
Hi All,
I'm fitting an proportional odds model using vglm() from VGAM.
My response variable is the severity of diseases, going from 0 to 5 (the
severity is actually an ordered factor).
The independent variables are: 1 genetic marker, time of medical observation,
age, sex. What I *need* is a p-value for the genetic marker. Because I have ~1.5
million markers I'd rather not faffing
2012 Aug 27
2
Assigning colors on low p-values in table
Hi all R-users,
I?m trying to assign colors on those p-value in my table output that fall
above a certain critical value, let?s say a p-value >0.05.
My table looks like this:
Assets ADF-Level P-Value
ADF-First D P-Value ADF-Second D P-Value
[1,] Liabilities -2.3109 0.1988 -3.162
0.025 -6.0281
2007 Jan 29
3
Multiple comparisons when interacction
In the model:
lm.1 <- lm(variable ~ BLOC + TIL * YEAR , data=selvanera)
I found TIL*YEAR interaction significant. Then I am trying to compare
means of the different levels of TIL inside every YEAR using:
mc.2 <- glht(lm.1, linfct = mcp(TIL*YEAR="Tukey"))
summary(mc.2, test = univariate())
but it does not work.
There is any way of doing this, like the SLICE option in
2012 Nov 12
5
Matrix to data frame conversion
I have a matrix which I wanted to convert to a data frame. As I could not
succeed and resorted to export to csv and reimport it again. Why did I fail
in the attempt and how can I achieve what I wanted without this
roundabouts?
The original matrix:
> str(comb_model0)
num [1:90, 1:4] 3.5938 0.0274 0.0342 0.0135 0.0207 ...
- attr(*, "dimnames")=List of 2
..$ : chr [1:90]
2011 Mar 10
1
Help writing a Scheffe Contrast function for R
Hello,
As a new user of R (less than a month) I have got my hands on several books and am pouting through the net looking for help in gaining understanding of this powerful tool. I am becoming more proficient with using basic functions to conduct basic statistics. I am now looking to learn how to write code. After a few small worthless functions I decided to try to create a function that was
2011 Dec 12
2
Automated Regressions
Hello R-Experts,
I've got a question, concerning the automation of a number of regressions
(lm) with the help of a loop (for i in ....).
The situation is as follows (the code follows after that):
I have my data in an access database. I have historical data for 2000 parts,
for each of this parts I want to do a regression analysis, so I need to do
2000 regressions (just for one country, there
2008 Jan 19
1
How do we get two-tailed p-values for rlm?
How do we get 2-tailed p-values for the rlm summary?
I'm using the following:
> fit <- rlm(oatRT ~ oatoacData$erp, psi=psi.bisquare, maxit=100,
na.action='na.omit')
> fitsum <- summary(fit, cor=F)
> print(fitsum)
Call: rlm(formula = oatRT ~ oatoacData$erp, psi = psi.bisquare, maxit = 100,
na.action = "na.omit")
Residuals:
Min 1Q Median
2004 Oct 27
1
writing lm summary to file?
Hi,
I want to write the summary from a regression. I am doing this because I do not see a way of get the std error, tvalues from the coefficients diagnostic. n$coef does not give this only get the intercept and slope. I tried to use write and write.table and got error in both cases. I jumped thru the hoops below to no avail. Also note, this is in windows. I used to use unix, and do not
2001 Nov 27
3
Equations as arguments to functions
I am trying to pass an equation as an arguement to a function, which seems
pretty straightforward given lazy evaluation.
I constructed the following little test to make sure I sort of knew what I
was doing:
go <- function(X,eq) { C <<- X*2; d <<- eq}
a _ rnorm(100)
go(10,eq=a[.5*length(a)]+C+1)
> C
[1] 20
> d
[1] 21.10551
> a[.5*length(a)]
[1] 0.1055086
Everything