similar to: [LLVMdev] Strange code generation issue

Displaying 20 results from an estimated 80 matches similar to: "[LLVMdev] Strange code generation issue"

2015 Feb 23
3
[LLVMdev] Eliminating redundant loads
On 23 February 2015 at 01:29, Kamal Sharma <kgs1.rice at gmail.com> wrote: > Hi Dibyendu, > > It would be very helpful if you could post the original source code or > snippet. > That way, one can investigate deeper to understand the problem. > > Regards, > Kamal Sharma > Hi Kamal, Sure. I guess I ought to create a test that one can look in isolation. I am
2015 Feb 22
2
[LLVMdev] Eliminating redundant loads
On 22 February 2015 at 20:58, David Jones <djones at xtreme-eda.com> wrote: > Not sure if this is your problem, but it was mine: > > You must create (or obtain) a DataLayout *and install it into the Module*. > > It is possible to generate machine code for IR and not install the > DataLayout into the Module. Rather, the DataLayout is used locally at the > point where code
2015 Feb 22
2
[LLVMdev] Eliminating redundant loads
Hi, I am generating following code: %base = getelementptr inbounds %ravi.CallInfo* %6, i32 0, i32 4, i32 0 %7 = load %ravi.TValue** %base %8 = bitcast %ravi.TValue* %7 to i8* %9 = bitcast %ravi.TValue* %5 to i8* call void @llvm.memcpy.p0i8.p0i8.i32(i8* %8, i8* %9, i32 16, i32 8, i1 false) %10 = load %ravi.CallInfo** %L_ci %base1 = getelementptr inbounds %ravi.CallInfo* %10, i32 0,
2015 Feb 23
2
[LLVMdev] Eliminating redundant loads
On 22 February 2015 at 22:54, Hal Finkel <hfinkel at anl.gov> wrote: >> I tried setting the module's DataLayout to the engine's DataLayout. >> Don't see any improvement. >> The memcpy() is to perform a struct assign, so I tried replacing that >> with member by member store. >> But even then the loads are not being eliminated so I guess the >>
2007 Jun 20
2
Extracting t-tests on coefficients in lm
I am writing a resampling program for multiple regression using lm(). I resample the data 10,000 times, each time extracting the regression coefficients. At present I extract the individual regression coefficients using brg = lm(Newdv~Teach + Exam + Knowledge + Grade + Enroll) bcoef[i,] = brg$coef This works fine. But now I want to extract the t tests on these coefficients. I cannot
2009 Mar 24
4
multiple paired t-tests
Hi R users, I have a very large data set that has two conditioning variables for the test I want to perform. A toy set can be simulated: type<-sample(1:3,100,replace=TRUE) class<-sample(1:20,100,replace=TRUE) value<-rnorm(100) data<-cbind(type,class,value) (though type and class are alphanum) I want to perform the three pair-wise t-tests between types for each class in data. Can
2018 Feb 04
1
Unexpected behaviour from read.table
I?ve been struggling with seemingly ?corrupt? data.frames for a few days, and believe I?ve narrowed the problem down to some odd behaviour from read.table I receive a tab delimited file from an external provider where strings are encoded as =?content?. Not sure why, perhaps as most users open it in Excel. My specific issue is that trailing spaces in any of the strings are causing strange results
2007 Jul 17
1
A simple question
Hi all, I am a newbie of R, and have a very simple question. When I run the following t test result = t.test(weight ~ group) If I want to get the t value, I can do tvalue = result$statistic with tvalue being the following: t 1.191260 However, if I just want the number 1.191260, not the character "t", how can I achieve that? Thank you very much, Gang
2009 Jan 14
5
How to compute p-Values
Hello. How can I compute the Bootstrap p-Value for a one- and two sided test, when I have a bootstrap sample of a statistic of 1000 for example? My hypothesis are for example: 1. Two-Sided: H0: mean=0 vs. H1: mean!=0 2. One Sided: H0: mean>=0 vs. H1: mean<0 I hope you can help me Thanks in advance Regards, Andreas
2013 Oct 18
1
No P.values in polr summary
Hi everyone, If I compute a "Ordered Logistic or Probit Regression" with the polr function from MASS package. the summary give me : coefficients, Standard error and Tvalue.. but not directly the p.value. I can compute "manualy" the Pvalue, but Is there a way to directly obtain the pa.value, and I wonder why the p.valeu is not directly calculated, is there a reason? exemple
2012 May 10
1
Error t value matrix
Hi all, I want to make the following: I want to run a linear regression on each column of a matrix "estima" on the correspondent column on the matrix "estima2". You see I want to regress estima[,1] on estima2[,1] this way to all columns.... At the same time I want to make a regression adding each time a new observation. You see, the first regression will regress only one
2009 Nov 04
1
vglm(), t values and p values
Hi All, I'm fitting an proportional odds model using vglm() from VGAM. My response variable is the severity of diseases, going from 0 to 5 (the severity is actually an ordered factor). The independent variables are: 1 genetic marker, time of medical observation, age, sex. What I *need* is a p-value for the genetic marker. Because I have ~1.5 million markers I'd rather not faffing
2012 Aug 27
2
Assigning colors on low p-values in table
Hi all R-users, I?m trying to assign colors on those p-value in my table output that fall above a certain critical value, let?s say a p-value >0.05. My table looks like this: Assets ADF-Level P-Value ADF-First D P-Value ADF-Second D P-Value [1,] Liabilities -2.3109 0.1988 -3.162 0.025 -6.0281
2007 Jan 29
3
Multiple comparisons when interacction
In the model: lm.1 <- lm(variable ~ BLOC + TIL * YEAR , data=selvanera) I found TIL*YEAR interaction significant. Then I am trying to compare means of the different levels of TIL inside every YEAR using: mc.2 <- glht(lm.1, linfct = mcp(TIL*YEAR="Tukey")) summary(mc.2, test = univariate()) but it does not work. There is any way of doing this, like the SLICE option in
2012 Nov 12
5
Matrix to data frame conversion
I have a matrix which I wanted to convert to a data frame. As I could not succeed and resorted to export to csv and reimport it again. Why did I fail in the attempt and how can I achieve what I wanted without this roundabouts? The original matrix: > str(comb_model0) num [1:90, 1:4] 3.5938 0.0274 0.0342 0.0135 0.0207 ... - attr(*, "dimnames")=List of 2 ..$ : chr [1:90]
2011 Mar 10
1
Help writing a Scheffe Contrast function for R
Hello, As a new user of R (less than a month) I have got my hands on several books and am pouting through the net looking for help in gaining understanding of this powerful tool. I am becoming more proficient with using basic functions to conduct basic statistics. I am now looking to learn how to write code. After a few small worthless functions I decided to try to create a function that was
2011 Dec 12
2
Automated Regressions
Hello R-Experts, I've got a question, concerning the automation of a number of regressions (lm) with the help of a loop (for i in ....). The situation is as follows (the code follows after that): I have my data in an access database. I have historical data for 2000 parts, for each of this parts I want to do a regression analysis, so I need to do 2000 regressions (just for one country, there
2008 Jan 19
1
How do we get two-tailed p-values for rlm?
How do we get 2-tailed p-values for the rlm summary? I'm using the following: > fit <- rlm(oatRT ~ oatoacData$erp, psi=psi.bisquare, maxit=100, na.action='na.omit') > fitsum <- summary(fit, cor=F) > print(fitsum) Call: rlm(formula = oatRT ~ oatoacData$erp, psi = psi.bisquare, maxit = 100, na.action = "na.omit") Residuals: Min 1Q Median
2004 Oct 27
1
writing lm summary to file?
Hi, I want to write the summary from a regression. I am doing this because I do not see a way of get the std error, tvalues from the coefficients diagnostic. n$coef does not give this only get the intercept and slope. I tried to use write and write.table and got error in both cases. I jumped thru the hoops below to no avail. Also note, this is in windows. I used to use unix, and do not
2001 Nov 27
3
Equations as arguments to functions
I am trying to pass an equation as an arguement to a function, which seems pretty straightforward given lazy evaluation. I constructed the following little test to make sure I sort of knew what I was doing: go <- function(X,eq) { C <<- X*2; d <<- eq} a _ rnorm(100) go(10,eq=a[.5*length(a)]+C+1) > C [1] 20 > d [1] 21.10551 > a[.5*length(a)] [1] 0.1055086 Everything