similar to: [LLVMdev] How to obtain CFG using llvm-gcc?

Hi, llvm-gcc is deprecated. It would be wise to avoid using it unless you have to! You don't say what form you want the control flow graphs in. AFAIK you can think of LLVM bitcode modules (emitted by using -emit-llvm flag) as a collection of global variables and functions. Each function is essentially a control flow graph. You can quickly take a look at a CFG by doing something like...

This is rather off-topic for LLVM, it's a C programming question and the C answer is: you can't. C doesn't expose any way to find the upper limit of 'Ptr' you just have to keep track of what size you used yourself. On Sun, Dec 15, 2013 at 6:22 PM, 李永超 <lyc364 at gmail.com> wrote: > Hi, > How can I obtain the upper bound of a pointer in the code? For example, I

Hi, How can I obtain the upper bound of a pointer in the code? For example, I have a pointer Ptr which points to a block of memory that is allocated by malloc, say, Ptr = malloc(size); Then what should I do if I am going to get the upper bound of the memory block that is pointed to by Ptr in the runtime? Thanks, Ben -------------- next part -------------- An HTML attachment was scrubbed...

On Thu, Jul 24, 2008 at 2:00 PM, Mark Leone <markleone at gmail.com> wrote: > Is irreducibility a problem for existing LLVM passes? There aren't any LLVM passes that expect a reducible CFG at the moment; of course, some passes are more effective with reducible CFGs. > It looks like > there was once an open project for a pass to make irreducible graphs > reducible. Was that

Hi, I'm confused about the entry and exit blocks of an LLVM CFG. I understand that every CFG has one and only one entry block, and this is confirmed by the existence of the getEntryBlock function in the Function class. But what about exit (a.k.a. return) blocks? At first I assumed that LLVM CFGs have one and only one exit block, too, but the following code is a counter-example:

> > Message: 4 > Date: Tue, 12 Aug 2008 13:23:52 -0700 > From: "Bill Wendling" <isanbard at gmail.com> > Subject: Re: [LLVMdev] A case where llvm created different cfg for > same code > To: "LLVM Developers Mailing List" <llvmdev at cs.uiuc.edu> > Message-ID: > <16e5fdf90808121323g1ae2a2e3lb6c5bd62521df621 at mail.gmail.com> >

Thanks Eli. It's not introducing loops, just unstructured conditionals (e.g. X's in the control-flow graph, rather than diamonds). You can see it using "opt -view-cfg" on the code below. Sounds like it's not a bug. Thanks for the info. - Mark ; Tail duplication yielded this code, which has non-structured control flow. ; Note that "then.i2" and

Dear Trevor, I'm too lazy to convert your .dot file into a graph file, but I'll make some comments anyway. :) First, LLVM does not guarantee that a function has a single exit block. Multiple basic blocks can have a return instruction as their terminator instruction. There is a pass (Unify Function Exit nodes i.e., -mergereturn <http://llvm.org/docs/Passes.html#mergereturn>)

I am getting a segmentation fault as soon as I touch the Basic block *b value defined as :  std::string getPHIAssigns(const PHINode *PH)  { const BasicBlock *b = PH->getParent();    errs() << b->size(); where as getPHIAssigns is being called from               for (BasicBlock::iterator ins=b->begin(), e3=b->end(); ins!=e3; ++ins, ++l) // get instructions                

Thanks Gregory, my mistake, your explanation was half right and your code was fully right, I meant to say the key is setting the first two digits in the foreground and background to "00" (which means transparent) this will delete the color of the border, and then making the shadowing variable equal to "none" this will delete the shadowing black line that appears by default. See

Thank you Gregory your code worked to remove the border in syslinux! It wasn?t the Alpha (that changes the opacity of the border color), but it was the ?shadowing? that had to be changed, so ?none? in the shadowing column worked(you notice the border come back if you change ?none? to ?std?) reference this link for terms: https://wiki.syslinux.org/wiki/index.php?title=Menu#MENU_COLOR ! I am also

Hi Surinder, I don't see anything obviously wrong with your code. I suggest that (1) you build LLVM with assertions enabled, (2) you run the verifier on your bitcode, and (3) run your program under valgrind. Ciao, Duncan. > I am getting a segmentation fault as soon as I touch the Basic block > *b value defined as : > > std::string getPHIAssigns(const PHINode *PH) > {

It seems that tail duplication can make a reducible CFG irreducible (example below). Is that intentional? Are there other optimizations that have that property? Is irreducibility a problem for existing LLVM passes? It looks like there was once an open project for a pass to make irreducible graphs reducible. Was that ever implemented? - Mark ; "opt -inline -tailduplicate" makes an

Hi, getMetadata(“dbg”) returns NULL for such a small program as follows: int main(){ char a[10], b[2]; if(a[0] != 0 && a[1] != 0){ strcpy(a, b); } return 0; } The compiling command is: llvm-gcc --emit-llvm -g -c ./src.c I also tried the solutions I found through Google: http://stackoverflow.com/questions/14943447/llvm-line-number-of-an-instruction

Hi, The following two segments of code are actually the same, but llvm created different cfg for them. Form1: 1 #define N 10 2 int test(int A[N][N]) 3 { 4 int i, j; 5 int result =0; 6 for(j=0; j+2<N; ++j) { 7 //for(i=0; i<j && i+j+1<N; i++) { 8 for(i=0; i<j && i<N-j-1; i++) { 9 A[i+j+1][j] = A[j + 2][j-i] + i; 10 } 11 } 12 13 for (i=0; i<N-2; ++i) 14 for (j=0;

Thank you Gregory your code worked to remove the border in syslinux! It wasn?t the Alpha (that changes the opacity of the border color), but it was the ?shadowing? that had to be changed, so ?none? in the shadowing column worked(you notice the border come back if you change ?none? to ?std?) reference this link for terms: https://wiki.syslinux.org/wiki/index.php?title=Menu#MENU_COLOR ! I am also

On Mar 13, 2010, at 11:54 AM, James Stanier wrote: > It > analyses the CFG and recognises specific region schema, such as if- > then, > if-then-else, while-loop, etc., and builds a "control tree" which > represents > the hierarchical structure of the input program. I am not sure if my definition of a control flow tree is the same as yours, but if it is, I am very

> Thanks Gregory, my mistake, your explanation was half right and your code was > fully right, I meant to say the key is setting the first two digits in the > foreground and background to "00" (which means transparent) this will delete the > color of the border, and then making the shadowing variable equal to "none" this > will delete the shadowing black line

Am Mi., 15. Jan. 2020 um 20:27 Uhr schrieb Chris Lattner < clattner at nondot.org>: > One you achieve consensus on data structure, there is the question of what >> IR to use within it. I would recommend starting with some combination of >> “existing LLVM IR operations + high level control flow representation”, >> e.g. parallel and affine loops. The key here is that

R 3.4.1 OS X Colleagues, I am just learning to use the quantmod package and I have encountered something that I don?t understand. This works: getSymbols("^DJI") This does not work: getQuote("^DJI?) It returns only NAs: Trade Time Last Change % Change Open High Low Volume ^DJI <NA> N/A N/A N/A N/A N/A N/A N/A Two questions: 1. Is there some way to obtain the