similar to: [LLVMdev] lower-lever IR (A-normal form)

R-help - I have this set of aggregated tables (sample data below via dput()). And I would like to have delayValue as the column variables with the "temp" (temp1, temp2, temp3) values as the row variables. However I would like to have the temp variables *aggregated into single rows* so that I have the frequency ("Freq" | counts) of each time each "delayValue" occurs

Hi all, I have a C code in Linux, it has 7 pointers and compile e run OK, but when I run in R happens problems with calloc function, it returns NULL. ############################################### > int *temp1,*temp2,*temp3,*temp4; temp1 = (int *)calloc(col,sizeof(int)); if(temp1 == NULL){ printf("\n\n No Memory1!"); exit(1); } temp2 = (int *)calloc(col,sizeof(int));

Dear all, I have a very simple question about how I can include HPD confidence lines in a Marginal posterior distribution scatterplot I have the following code to draw the scatterplot(s) from an output table; par(mfrow=c(2,2)) plot(temp1[,5], temp1[,6], xlab="log10(r)", ylab="log10(tf)", pch=46) plot(temp2[,5], temp2[,6],

Hi, i would like to ask you, if i can get a lower-level representation than the llvm IR.For example, having the following instruction in the llvm IR, call void @llvm.memcpy.i32(i8* %19, i8* getelementptr inbounds ([2 x [2 x [3 x i8]]]* @main.s, i32 0, i32 0, i32 0, i32 0), i32 12, i32 1) i would like to get something like this (in A-normal form (without nested instructions):%temp = i8*

hi, I considered multivariate multiple regression for respons, predictor, each 5 dimension. on going process, through initb <- eigen(temp)$vectors[,1:3] temp <- vhalf%*%Kproduct(Ir,initb) (herein 'vhalf' is root for inverse of covariance matrix and 'Kproduct' is Kronecker product) and then process regression. However, I have tried using the

i have a time Series of IBM closing px from 1/1/2000 to today I want to graph the time serie by dividing the graph by year and month all the monthly graphs with the same year will go to one page. so from 1/1/2000 to 11/19/2010. i will have 11 pages, and each page will have 12 graphs (jan to dec) except for 2010. I am able to do it in R, but when i use sweave, I can only print the last page.

Hi all- I am stumped. The code in A. returns errors at lines 14 and 15 and fails to load series1 and series2. However, in B., if temp1 and temp2 are called again (which returns a "Table exists" error; see lines 14-17 in B.) series1 and series2 load correctly. Any ideas? Also-I am open to any suggestions to improve the code as I am a horrific programmer. Thanks A. 1 >

This is a rather interesting, but I don't think it is a bug - it is just things that "you are not supposed to do"... you are assuming a certain evaluation order of the 4 "$" operators in " D$ABC[D$M] = D$V[D$M] " as in: temp1 <- D$M # 2nd and 4th temp2 <- D$V[temp1] # 3rd D$ABC[temp1] = temp2 # 1st What R did was this:

HI Irucka, Please check this: temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L, 2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342, 12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA, -4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L, 3L, 4L, 5L, NA), Data1 = c(1.52,

> > > what if another pointer points to the same instruction? > You can have many pointers to the same instruction. However, the address in memory where that instruction lives is unique. Instruction pointers (or Value pointers) are thus commonly used as keys in hash tables or similar. Instructions or Values are almost never copied, so that you won't find the same instruction at

Full_Name: Bill Wheeler Version: 2.0.1 OS: Windows 2000 Submission from: (NULL) (67.130.36.229) The program to reproduce the error is below. I am calling rpart with a user-defined split function for a binary response variable and one continuous independent variable. The split function works for some datasets but not others. The error is: Error in "$<-.data.frame"(`*tmp*`,

I have a GeForce 8800GT that I am trying to lower the fan speed on. I can change the fan RPM from high to not-as-high but I want more control over it. It is too loud and it was quieter with the blob. Maybe the temps are too high to make it quieter. # echo 1 >/sys/devices/pci0000:00/0000:00:02.0/0000:01:00.0/i2c-6/6-002e/pwm1_enable # sensors fam15h_power-pci-00c4 Adapter: PCI adapter power1:

I am using R 2.1.1 in an windows XP environment. I have 2 dataframes, temp1 and temp2. Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric. I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe. (i.e. temp1$column

Hi, I am writing a function to plot a pdf of a distribution, GNL.pdf.fn = function(x,mu,sigma,alpha,beta,rho) { y = x-rho*mu cf.fn = function(s){ cplex = complex(1,0,1) temp1 = alpha*beta*exp(-sigma*s^2/2) temp2 = (alpha-cplex*s)*(beta+cplex*s) out = (temp1/temp2)^rho out } temp.fn = function(s){ (Mod(cf.fn(s)))*cos(Arg(cf.fn(s))-s*y) } int.fn =

Hi, i would like to ask you, if i can get a lower-level representation than the llvm IR.For example, having the following instruction in the llvm IR, call void @llvm.memcpy.i32(i8* %19, i8* getelementptr inbounds ([2 x [2 x [3 x i8]]]* @main.s, i32 0, i32 0, i32 0, i32 0), i32 12, i32 1) i would like to get something like this (in A-normal form (without nested instructions):%temp = i8*

Naresh, I am not sure how you are creating your data.frame so it has no, I think, column names. There are two scenarios including one where it is not really a valid data.frame and one where it can be handled before any other use as shown below. If it cannot be used, you might need to modify how your SQL or the function you call creates it so it includes either names it chooses or that you supply.

There you go, once again helping strengthen ;) John Get Outlook for iOS<https://aka.ms/o0ukef> ________________________________ From: R-help <r-help-bounces at r-project.org> on behalf of avi.e.gross at gmail.com <avi.e.gross at gmail.com> Sent: Tuesday, January 28, 2025 12:01:25 AM To: 'Naresh Gurbuxani' <naresh_gurbuxani at hotmail.com>; r-help at r-project.org

temp = "~aparch(" temp1 = paste(temp,1, sep = "") temp2 = paste(temp1,1, sep = ",") temp3 = paste(temp2, ")",sep = "") temp 3 is a character but I want to convert to formula object. How do I do this? -- View this message in context: http://r.789695.n4.nabble.com/how-to-convert-string-to-object-tp2999281p2999281.html Sent from the R help mailing

On 2025-01-28 1:55 p.m., Naresh Gurbuxani wrote: > Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns. > > Something like: > > Myquery <- ?SELECT date, price, stock FROM stocktab WHERE stock = ?ABC? AND date > ?2025-01-01?;? > > Prices <- dbGetQuery(con, myquery) > SetDT(Prices) > Prices[,

This solution worked. Thanks Sent from my iPhone > On Jan 28, 2025, at 3:09?PM, Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > > ?On 2025-01-28 1:55 p.m., Naresh Gurbuxani wrote: >> Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns. >> Something like: >> Myquery <- ?SELECT date,