similar to: [LLVMdev] LLVM Backend for Z80. ADD -> replaced -> OR

Displaying 20 results from an estimated 1000 matches similar to: "[LLVMdev] LLVM Backend for Z80. ADD -> replaced -> OR"

2012 Apr 25
0
[LLVMdev] LLVM Backend for Z80. ADD -> replaced -> OR
Hi Peter, I think the problem is that you did not explicitly define stack alignment in Z80TargetMachine.cpp DataLayout("e-p:16:8:8-i8:8:8-i16:8:8-i32:8:8-n8") Try to add S16 to the string if your stack is 2-byte aligned. Refer to http://llvm.org/docs/LangRef.html#datalayout . If it does not work, try to specify the layout in the input module using target layout directive. David On
2012 Apr 25
1
[LLVMdev] LLVM Backend for Z80. ADD -> replaced -> OR
Hello. I have played with DataLayout and found a solution with is uknown to me. I added S16 and also s0:16:16, but it had not worked. Then I found that in Z80FrameLowering.h I am calling TargetFrameLowering with stack aligment set to 8. So I changed it to 2 bytes. But this also didn't help. Then I changed llc to show TargetDataLayout and found that a option is set to a0:0:64. So I changed
2012 Apr 18
0
[LLVMdev] [cfe-dev] LLVM Backend for Z80
Hi Peter, (I'm CC'ing the LLVMdev list as there might be others able to help you) I don't know this assertion, so can't help you with that particular problem. But concerning "more debug info": Do you know the following two links? http://llvm.org/releases/3.0/docs/ProgrammersManual.html#DEBUG You can find some example debug code e.g. in method Select(SDNode *Node) in
2013 Feb 02
1
[LLVMdev] Trouble with instructions for lowering load/store.
Hello. I write backend for Z80 cpu and I have some trouble with lowering load/store nodes to different machine opcodes. Some target instructions work with specified registers (not all registers in RegisterClass). Often it's one or two registers. I don't understand how use ComplexPattern in this case. But if I don't use ComplexPattern I'll have other problems - not all
2016 Oct 04
2
LLVM z80 backend and llvm-dis missing?
Inspired by Jason Turner's talk at CppCon 2016: Jason Turner “Rich Code for Tiny Computers: A Simple Commodore 64 Game in C++17” I got interested in writing a Zilog Z80 backend for LLVM. Jason actually did no such thing, but instead wrote a x86-to-6502 translator (reassembler he calls it) https://github.com/lefticus/x86-to-6502 So I'm now trying to bootstrap this project. Goal: - be
2018 Jul 18
2
Lowering SEXT (and ZEXT) efficiently on Z80
I'm working on a Z80 backend and am trying to efficiently lower SEXT, specifically 8 to 16 bit, in LowerOperation() according to the following rules: The Z80 has 8 bit registers and 16 bit registers, which are aliased versions of two 8 bit registers. 8 bit registers are named A, H, L, D, E and some more. 16 bit registers are HL (composed of H + L), DE (D + E) - and some more - with L and
2006 Sep 13
3
group bunch of lines in a data.frame, an additional requirement
Thanks for pointing me out "aggregate", that works fine! There is one complication though: I have mixed types (numerical and character), So the matrix is of the form: A 1.0 200 ID1 A 3.0 800 ID1 A 2.0 200 ID1 B 0.5 20 ID2 B 0.9 50 ID2 C 5.0 70 ID1 One letter always has the same ID but one ID can be shared by many letters (like ID1) I just want to keep track of the ID, and get
2012 Apr 14
3
Choose between duplicated rows
Dear r experts, Sorry for this basic question, but I can't seem to find a solution? I have this data frame: df <- data.frame(id = c("id1", "id1", "id1", "id2", "id2", "id2"), A = c(11905, 11907, 11907, 11829, 11829, 11829), v1 = c(NA, 3, NA,1,2,NA), v2 = c(NA,2,NA, 2, NA,NA), v3 = c(NA,1,NA,1,NA,NA), v4 = c("N",
2011 Apr 25
2
Problem with ddply in the plyr-package: surprising output of a date-column
Hi Together, I have a problem with the plyr package - more precisely with the ddply function - and would be very grateful for any help. I hope the example here is precise enough for someone to identify the problem. Basically, in this step I want to identify observations that are identical in terms of certain identifiers (ID1, ID2, ID3) and just want to save those observations (in this step,
2008 Jul 09
2
Parsing
Dear R users, I have a big text file formatted like this: x x_string y y_string id1 id1_string id2 id2_string z z_string w w_string stuff stuff stuff stuff stuff stuff stuff stuff stuff // x x_string1 y y_string1 z z_string1 w w_string1 stuff stuff stuff stuff stuff stuff stuff stuff stuff // x x_string2 y y_string2 id1
2006 Jan 14
3
In place editing and external control
Dear all, First I''d like to thank authors for so nice Scriptaculous and Prototype libraries, which helped me already a lot! I have question regarding externalControl parameter in InPlaceEditor. If I understand correctly, I can use that to have one image as a trigger to enter edit mode? I tried with below code but without success: <span id="id1">My text</span>
2005 Nov 09
3
dataframe without repetition
Hello, with a data.frame like this : > toto <- data.frame(id=c("id1","id1","id2","id3","id3","id3"),dpt=c("13","13","34","30","30","30")) > toto id dpt 1 id1 13 2 id1 13 3 id2 34 4 id3 30 5 id3 30 6 id3 30 what is the most efficient ways to obtain : id
2010 Sep 07
1
average columns of data frame corresponding to replicates
Hi Group, I have a data frame below. Within this data frame there are samples (columns) that are measured more than once. Samples are indicated by "idx". So "id1" is present in columns 1, 3, and 5. Not every id is repeated. I would like to create a new data frame so that the repeated ids are averaged. For example, in the new data frame, columns 1, 3, and 5 of the original
2011 Aug 02
2
Data frame to matrix - revisited
Hi, I've tried to look through all the previous related Threads/posts but can't find a solution to what's probably a simple question. ? I have a data frame comprised of three columns e.g.: ? ID1?ID2?Value a?b?1 b?d?1 c?a?2 c?e?1 d?a?1 e?d?2 ? I'd like to convert the data to a matrix i.e.: ? ?a b c d e a n/a 1 2 1 n/a b 1 n/a n/a 1 n/a? c 2 n/a n/a n/a 1 d 1 1 n/a n/a 2 e n/a n/a 1
2013 Apr 12
1
Removing rows that are duplicates but column values are in reversed order
Hi, From your example data, dat1<- read.table(text=" id1?? id2?? value a????? b?????? 10 c????? d??????? 11 b???? a???????? 10 c????? e???????? 12 ",sep="",header=TRUE,stringsAsFactors=FALSE) #it is easier to get the output you wanted dat1[!duplicated(dat1$value),] #? id1 id2 value #1?? a?? b??? 10 #2?? c?? d??? 11 #4?? c?? e??? 12 But, if you have cases like the one
2007 Apr 20
2
Fastest way to repeatedly subset a data frame?
Hi - I have a data frame with a large number of observations (62,000 rows, but only 2 columns - a character ID and a result list). Sample: > my.df <- data.frame(id=c("ID1", "ID2", "ID3"), result=1:3) > my.df id result 1 ID1 1 2 ID2 2 3 ID3 3 I have a list of ID vectors. This list will have anywhere from 100 to 1000 members, and
2010 Jun 03
2
deduplication
Colleagues, I am trying to de-duplicate a large (long) database (approx 1mil records) of diagnostic tests. Individuals in the database can have up-to 25 observations, but most will have only one. IDs for de-duplication (names, sex, lab number...) are patchy. In a first step, I am using Andreas Borg's excellent record linkage package (), that leaves me with a list of 'pairs' looking
2010 Oct 12
5
aggregate with cumsum
Hello everybody, Data is myd <- data.frame(id1=rep(c("a","b","c"),each=3),id2=rep(1:3,3),val=rnorm(9)) I want to get a cumulative sum over each of id1. trying aggregate does not work myd$pcum <- aggregate(myd[,c("val")],list(orig=myd$id1),cumsum) Please suggest a solution. In real the dataframe is huge so looping with for and subsetting is not a
2008 Jan 10
1
data.frame manipulation: Unbinding strings in a row
Hi all, I have a data.frame I received with data that look like this (comma separated strings in last row): ID Shop Items ID1 A1 item1, item2, item3 ID2 A2 item4, item5 ID3 A1 item1, item3, item4 But I would like to unbind the strings in col(2) items so that it will look like this: ID Shop Items ID1 A1 item1 ID1 A1 item2 ID1 A1 item3 ID2 A2 item4 ID2 A2 item5 ID3 A1 item1 ID3 A1 item3 ID3 A1
2005 Aug 10
1
Why only a "" string for heading for row.names with write.csv with a matrix?
Consider: > x <- matrix(1:6, 2,3) > rownames(x) <- c("ID1", "ID2") > colnames(x) <- c("Attr1", "Attr2", "Attr3") > x Attr1 Attr2 Attr3 ID1 1 3 5 ID2 2 4 6 > write.csv(x,file="x.csv") "","Attr1","Attr2","Attr3" "ID1",1,3,5