similar to: [LLVMdev] How to get the operand value in the instruction

Sorry, I have typo in my question. I will be careful next time. This is how I obtain the source operands of an instruction. // ----------------------------------------------------------------- BasicBlock::iterator it; ... for(int k=0; k<OpNum; k++){ errs()<<it->getOperand(k)<<" "; } ... // -------------------------------------------------------------------- Also I

Hello Everyone, I need some help in retrieving the numeric value of an instruction operand from LLVM IR. this is what the IR looks like for a simple add function that adds two i32 integers define i32 @summ(i32 %a, i32 %b) #0 { entry: %add = add nsw i32 %b, %a ret i32 %add } i would like to know the integer value of %a and %b. I've tried -i->getOpcodeName() which gives me the

Launcher <st.liucheng at gmail.com> writes: > I am able to access the source operands of an instruction using either > getOperand() or op_iterator, However, I can't find any method available for > destination operand. Someone suggests that instruction itself can represent > the destination operand. > http://lists.cs.uiuc.edu/pipermail/llvmdev/2011-January/037518.html

I am able to access the source operands of an instruction using either getOperand() or op_iterator, However, I can't find any method available for destination operand. Someone suggests that instruction itself can represent the destination operand. http://lists.cs.uiuc.edu/pipermail/llvmdev/2011-January/037518.html The getOperand() returns an unsigned value like 0x9063498, while I can't

Hi, > Sorry, I have typo in my question. > I will be careful next time. > > This is how I obtain the source operands of an instruction. > // ----------------------------------------------------------------- > BasicBlock::iterator it; > ... > for(int k=0; k<OpNum; k++){ > errs()<<it->getOperand(k)<<" "; try this:

hey john, yes indeed, that's what I'm trying, retreiving the values of %a and %b in an LLVM pass, sorry about the confusion. On Apr 24, 2016 7:18 AM, "John Criswell" <jtcriswel at gmail.com> wrote: > Dear Ammar, > > It is not clear what you are asking. %a and %b in your code below are not > constants; there is no way, at compile time, to determine what

Hi John, Thank you so much for the valuable answer! :) However, i have one tough issue that i need to solve, in my pass : let's say here %s = add %a, %b I need to check if the value of %a or %b is 2 or 4 and then apply a transformation to the other operand accordingly, for example if the value of %a = 2 the i'll multiply %b by 2 in my transform pass. I'm having a hard time

Hi Everyone, I asked a question on the dev list related to the topic to which John Criswell and Jeremy Lakeman kindly provided some valuable insight. I'm still stuck on the issue and i'm hoping i didn't phrase the question well enough. I have a *foo.c* file that is : *#include <stdio.h>* *int foo(int a, int b){* * return a+b;* *}* *int main() {* *int x=foo(3,1); *

Nipun Arora wrote: > Hi, > > How can one extract the operand of an instruction in an LLVM pass? > Like I can get the opcode bt I'd like to get the operands as well > Use the getOperand() method of class Instruction (which I think is inherited from Value or User or some other LLVM class). It takes a single parameter that is an index specifying which operand to return. The

if (ConstantInt *c = (ConstantInt *) dyn_cast<ConstantInt>(index)){ errs() << "And it's a constant!!!!!!1111oneone!! (" <<c->getZExtValue() << ")\n"; } -- "Believe you can, believe you can't; either way you're right."  -Henry Ford -----Original Message----- From: llvmdev-bounces at cs.uiuc.edu [mailto:llvmdev-bounces at

On Jun 2, 2011, at 9:46 AM, Griffin Wright wrote: > > Hello all: > > I apologize for what I imagine is a rather silly question, but I'm still > somewhat new to LLVM and am stuck. I am reworking some code that was > originally in the backend involving MachineInstructions and > MachineOperands, and I now need for it to function as an LLVM IR pass, > using just

Hello, how to get the numerical value of an constant operand? For ex. %tmp = mul i32 %indvar, 6 , in this instruction second operand is a numerical constant with value 6. But i am only able to print it by using getOperand(1), not able to store it in any integer variable. Using getName() returns a empty string. Is there any way to solve this problem? Thank you. John Criswell-2 wrote: > >

Typical PHI instruction in LLVM goes like this: %P = phi i32* [%A, %BB1], [%B, %BB2] When I try to access all the source operands, only %A and %B are included. I checked the methods in instruction.h, but I didn't find any methods obtaining the label fields i.e. %BB1, %BB2. I notice that each label of a basic block is related with a value which can be referenced in 'br'

Thanks for the quick reply. I am able to get the numerical value. But i also need the numerical value to be in value type, so that it can be used as operand of other instruction. For that i am trying to create a new ConstantInt, but i am unable to find create() function for ConstantInt. Thanks again for the quick and helpful reply. Ben Perry-3 wrote: > > if (ConstantInt *c = (ConstantInt

Gabor Greif wrote: > Am 30.06.2010 um 23:31 schrieb John Criswell: > > >> Stupid question: is making the getOperand() method of CallInst >> going to work? For example, if I have the following code: >> >> void >> method (Instruction * I) { >> I->getOperand(2); >> ... >> } >> >> void method2 (CallInst * CI) {

Can anyone tell how to get the result name or instruction name of all instruction? For example if the instruction is "x=add y,z", here i need "x". Using getName(), i am getting some instructions result name, but llvm produces some instruction like "%0=add i32 tmp, 1", here getName() shows empty string as result name. So please help. John Criswell wrote: > >

On Fri, Jul 1, 2011 at 12:35 AM, ankur deshwal <a.s.deshwal at gmail.com> wrote: > Hi, > > I was trying to use the following code in a if condition > I->getOperand(0)->hasName() > > where I is an instruction with following condition already true - > I->getOpcode() == Instruction::Call > > When I compiled a C code with llvm-2.9, I see a function call with

Hi Duncan, Thank you for your response! Now it works. But I have another problem: Do you know how can I iterate through a Value*? For instance, I have : Instruction *I1; // I take only I1 that are ICmp errs()<<"\n "<<*I1->getOperand(0)<<" \n"; // %3 = load i32* %c, align 4 As expected. Now I want to get %c from the previous to use "%c" in

Hi Duncan, Thanks for pointing out my mistake. I will reword my questions. //C code int var1; //global int a, b; foo(a, b); bar(c); generates following //LLVM IR %1 = load a; %2 = load b; call foo(%1, %2) call bar(@var1) CallInst.getOperand(1).getNameStr() on foo, returns null, but on bar returns var1. Similarly, for call void @p_ptr(i64 ptrtoint (%struct.my_struct* @abc to i64)) nounwind,

Hi, How can one extract the operand of an instruction in an LLVM pass? Like I can get the opcode bt I'd like to get the operands as well Thanks Nipun -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.llvm.org/pipermail/llvm-dev/attachments/20090211/3a073512/attachment.html>