similar to: [LLVMdev] Data layout of structs

Displaying 20 results from an estimated 4000 matches similar to: "[LLVMdev] Data layout of structs"

2010 Nov 17
1
[LLVMdev] Copy Instruction from one Basic block to another
I want to do the following: suppose the program structure: bb / \ bb1 bb2 \ / bb3
2012 Jul 25
2
[LLVMdev] Question about an unusual jump instruction
Dear all, I'm working on an exploratory backend on llvm. In the instruction set I'm using I have an instruction (called DECJNZ) that decrements a register and, if the decremented value is not zero, jumps (with a relative jump) to a given offset. I've described in tablegen this instruction as follow: def DECJNZ : Instruction { let Namespace = "MyTarget"; let
2012 Jul 25
0
[LLVMdev] Question about an unusual jump instruction
On Wed, Jul 25, 2012 at 12:48 AM, Michele Scandale <michele.scandale at gmail.com> wrote: > Dear all, > > I'm working on an exploratory backend on llvm. In the instruction set I'm using > I have an instruction (called DECJNZ) that decrements a register and, if the > decremented value is not zero, jumps (with a relative jump) to a given offset. > > I've
2011 Nov 21
1
[LLVMdev] Fwd: Order of Basic Blocks
---------- Forwarded message ---------- From: Ryan Taylor <ryta1203 at gmail.com> Date: Mon, Nov 21, 2011 at 10:30 AM Subject: Re: [LLVMdev] Order of Basic Blocks To: Benjamin Kramer <benny.kra at googlemail.com> This worked, though the RPO_iterator apparently wasn't what I was looking for anyways, it seems it doesn't rreally go top->down. I have a simple example code,
2015 Mar 24
2
[LLVMdev] RFC - Improvements to PGO profile support
Example. Assuming the cap is 'C' void bar() { // ENTRY count is 4*C, after capping it becomes 'C' ... } void test() { // BB1: count(BB1) = C bar(); // BB2: count(BB2) = C bar(); } void test2() { // BB3: count(BB3) = C bar(); // BB4: count(BB4) = C bar(); } What would inliner see here ? When it sees callsite1 -- it might mistaken that is the
2010 Jul 17
2
[LLVMdev] How to insert a basic block in an edge
Hi all, Suppose in a CFG bb1 has two succesor bb3 and bb4, and bb3 has two predecessor bb1 and bb2. Now how can I insert a basic block between bb1 and bb3 that at the edge bb1-->bb3 . In general how can I insert a basic block on an edge? Regards, Chayan
2010 Jul 18
2
[LLVMdev] How to insert a basic block in an edge
Hi, I have tried to use SplitEdge function, but failed. Actually the third parameter is a variable of type Pass and it need to be non-null. But I could not figure out how to use it. Please help me out. Regards, Chayan On Sat, Jul 17, 2010 at 10:16 PM, Nick Lewycky <nicholas at mxc.ca> wrote: > Chayan Sarkar wrote: >> >> Hi all, >> >> Suppose in a CFG bb1 has two
2016 Sep 21
2
Propagation of debug information for variable into basic blocks.
> On Sep 21, 2016, at 2:23 PM, Daniel Berlin <dberlin at dberlin.org> wrote: > > > > // For all predecessors of this MBB, find the set of VarLocs that > // can be joined. > for (auto p : MBB.predecessors()) { > auto OL = OutLocs.find(p); > // Join is null in case of empty OutLocs from any of the pred. > if (OL == OutLocs.end()) >
2010 Jul 20
2
[LLVMdev] How to insert a basic block in an edge
Hi All, Still I could not figure out how to use Pass* while calling SplitEdge() function. Can anyone provide me some example? Regards, Chayan On Sun, Jul 18, 2010 at 11:49 PM, Nick Lewycky <nicholas at mxc.ca> wrote: > Chayan Sarkar wrote: >> >> Hi, >> >> I have tried to use SplitEdge function, but failed. Actually the third >> parameter is a variable of
2010 Jul 17
0
[LLVMdev] How to insert a basic block in an edge
Chayan Sarkar wrote: > Hi all, > > Suppose in a CFG bb1 has two succesor bb3 and bb4, and bb3 has two > predecessor bb1 and bb2. Now how can I insert a basic block between > bb1 and bb3 that at the edge bb1-->bb3 . > > In general how can I insert a basic block on an edge? Use llvm::SplitEdge in Transforms/Utils/BasicBlockUtils.h. The technique is to create a new bb with a
2010 Jul 18
0
[LLVMdev] How to insert a basic block in an edge
Chayan Sarkar wrote: > Hi, > > I have tried to use SplitEdge function, but failed. Actually the third > parameter is a variable of type Pass and it need to be non-null. But I > could not figure out how to use it. Please help me out. The only reason it needs a non-NULL Pass* is to call llvm::SplitBlock which uses P->getAnalysisIfAvailable unconditionally. Feel free to wrap
2011 Jan 25
2
[LLVMdev] Update PHINode after extracting code
Hi all, I have problem with ExtractCodeRegion (CodeExtractor.cpp). My original program is as follows. bb: ... %tmp.15 = load %struct.MYSQL_ROWS** %3, align 4 ... bb1: ... %tmp.1 = load %struct.MYSQL_ROWS** %6, align 4 ... bb4: ; preds = %bb1, %bb, %entry %tmp.0 = phi %struct.MYSQL_ROWS* [ null, %entry ], [ %tmp.15, %bb ], [ %tmp.1, %bb1 ]
2010 Jul 21
0
[LLVMdev] How to insert a basic block in an edge
Hi, I could not figure out, how to declare a Pass*. Can anyone give me an example, how to use SplitEdge() function ? Please help me out. Regards, Chayan On Tue, Jul 20, 2010 at 10:12 AM, Chayan Sarkar <chayan.ju at gmail.com> wrote: > Hi All, > > Still I could not figure out how to use Pass* while calling > SplitEdge() function. Can anyone provide me some example? > >
2011 Jan 27
0
[LLVMdev] Update PHINode after extracting code
I guess I didn't have a clear question. Suppose we have BB1 and BB2 both point to BB3. BB1 has variable x. BB2 also as variable x. BB3 will have PHINode for x with 2 value from BB1 and BB2. BB1 BB2 \ / BB3 Now if BB1 and BB2 is extracted into a function (using ExtractCodeRegion), they will be replaced by a basic block called codeRepl (which has a call to the extracted
2008 Jan 22
3
[LLVMdev] Walking all the predecessors for a basic block
Hi all, Is there a way to walk through ALL the predecessors of a basic block in a CFG. I tried to iterate over the preds using this method for (pred_iterator PI = pred_begin(BB), E = pred_end(BB); PI != E; ++I) { BasicBlock *PredBB = *PI; } but this only gives the immediate predecessors for a basic block. For example, in this sample control flow graph. entry -> bb1 -> bb2 -> bb4
2013 Oct 10
2
[LLVMdev] Are there implicit rules or conventions for an llvm frontend to generate llvm IR?
Hi, this question might be a bit silly: apart from the language reference(http://llvm.org/docs/LangRef.html#switch-instruction) page, are there additional rules for a regular llvm frontend to generate llvm IRs? There are a few cases that I got from clang/llvm-gcc/dragonegg when compiling *C* source code into llvm IR: 1. It seems that there is ONLY ONE ReturnInst(and NO InvokeInst) for such llvm
2009 Sep 03
2
[LLVMdev] Non-local DSE optimization
Hi, It looks like PDT.getRootNode() returns NULL for: define fastcc void @c974001__lengthy_calculation. 1736(%struct.FRAME.c974001* nocapture %CHAIN.185) noreturn { entry: br label %bb bb: br label %bb } Isn't it a bug in PostDominatorTree? Please note that this crashes: opt -postdomtree -debug dom_crash.bc I think this should be reported as a bug, -Jakub On Sep 3, 2009, at
2008 Jan 22
0
[LLVMdev] Walking all the predecessors for a basic block
Hi Pabhat, Have you checked out DepthFirstIterator? (include/llvm/ADT/ DepthFirstIterator.h). It provides an iterator abstraction to perform a forward/reverse DFS traversal of a graph. Many of the LLVM datatypes that represent graphs have a template specialization of the GraphTraits<> class which allows separate algorithms to treat them as graphs, walk them, etc. (Both BasicBlock
2009 Sep 06
0
[LLVMdev] Non-local DSE optimization
Jakub Staszak wrote: > Hi, > > It looks like PDT.getRootNode() returns NULL for: > > define fastcc void @c974001__lengthy_calculation. > 1736(%struct.FRAME.c974001* nocapture %CHAIN.185) noreturn { > entry: > br label %bb > > bb: > br label %bb > } > > > Isn't it a bug in PostDominatorTree? > > Please note that this crashes: >
2010 Jun 24
2
[LLVMdev] How to prevent an instruction to be executed more than once?
Hi LLVM-devs, I am looking for a way to prevent an instruction to be executed more than once, or duplicated .. I know that by default everything can be duplicated, but is there a work-around? The structure of the code is BB1 BB2 | | | | | | |----------| | v BB3 where the first instruction in BB3 is inserting an inline assembly