similar to: [LLVMdev] A question about LLVM assembly

We have frequent timeout problems after upgrading our imap servers from dovecot 1.1.16 to dovecot 1.2.11. One server acts as proxy only, and the other one is the "real" imap server". The credentials for the proxy service are stored in a remote MYSQL database. There were no trouble with dovecot 1.1.16. But now, with the most recent version, we get frequent login failures. It

temp.ttt <- "ttt <- 1\nttt" conn.ttt <- textConnection(temp.ttt) source(conn.ttt, echo=TRUE) ## name of variable is echoed close(conn.ttt) cat(file="c:/temp/temp.R", temp.ttt) ## name of variable not echoed source("c:/temp/temp.R", echo=TRUE) temp.abc <- "abc <- 1\nabc" conn.abc <- textConnection(temp.abc) source(conn.abc, echo=TRUE)

You may also want to check this out: plot(ttt, type = "p") points(ttt, col = ifelse(ttt < 8, "black", "red")) Eivind K. Dovik Bergen, NO On Tue, 1 May 2018, Christopher W Ryan wrote: > Excellent! Worked like a charm. Thanks. > > --Chris Ryan > > On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote: > >> The

Excellent! Worked like a charm. Thanks. --Chris Ryan On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote: > The ts method for plot() is quirky. You can use the default method: > > plot(as.vector(time(ttt)), as.vector(ttt), type = "p", col=ifelse(ttt<8, > "black", "red")) > > > Bill Dunlap > TIBCO Software

Dear all I have made some lattice graphs (bwplot(dead ~ treat | group,...). 'group' is a factor with three levels (Artemia larvae, Abalone larvae and Abalone spat), and the result is a graph with three panels corresponding to the levels in 'group', ordered in alphabetical order from bottom to top, as expected. How does one re-order the order in which the levels of

How would I color points conditional on their value in a plot of a time series. Something like this: ## demonstration data ttt <- ts(rpois(12, lambda = 8), start = c(2000, 1), freq = 4) ttt plot(ttt, type = "p") ## doesn't work--all points the same color plot(ttt, type = "p", col = ifelse(ttt < 8, "black", "red")) ## also doesn't work--all

The ts method for plot() is quirky. You can use the default method: plot(as.vector(time(ttt)), as.vector(ttt), type = "p", col=ifelse(ttt<8, "black", "red")) Bill Dunlap TIBCO Software wdunlap tibco.com On Tue, May 1, 2018 at 1:17 PM, Christopher W Ryan <cryan at binghamton.edu> wrote: > How would I color points conditional on their value in a plot

Hello! I would like to visualize the hospitalization within one year of several patients using a bar chart. For each patient the stay in a hospital should be illustrated with a dark colour a if there is a stay at home between 2 hopital stays, it should be illustrated with a bright colour. e.g. P1 |//////| |///| |////////| P2 |//////////| P3 |//|

Hello, everyone, I don't quite understand the following message: > TTT <- t.test(1:10, y=c(7:20)) > class(TTT) [1] "htest" > TTT@p.value Error: Trying to get slot "p.value" from an object whose class ("htest") is not defined > TTT$p.value [1] 1.855282e-05 Why the message says the class of TTT is not defined while class(TTT) gets

Hi: I have some problems when I use the function "solve" function in a loop. In the following code, I have a diagonal martix "ttt" whose elements change in every iteration in a loop. I defined a "dpoMatrix"class before the loop so I do not need to define this class every time in the loop. The reason is to save some computing time. The code is below. The inverse

Hello, I am forwarding this from ESS mailing list, as it's a failure of internal R completion system: This fails: utils:::.assignLinebuffer('iris[iris$Spec') utils:::.assignEnd(15) utils:::.guessTokenFromLine() utils:::.completeToken() utils:::.retrieveCompletions() ## -> [1] "iris[iris$Spec" This works utils:::.assignLinebuffer('iris[ iris$Spec') # note the

At times we want to convert a two-sided formula to a one-sided formula. In S we can do this by dropping the second entry in the formula. In R that object no longer has a formula class. R> ttt <- score ~ age | Infant R> class(ttt) [1] "formula" R> length(ttt) [1] 3 R> ttt[-2] [[1]] ~ [[2]] age | Infant R> class(ttt[-2]) NULL R> do.call("~",

I have a timeseries object, ts, and want to get the first date in the series into a string so I can concatenate it with a SQL query. Input and output are shown below. I must be missing something very basic, but I can't seem to pry the data ("2008-07-01") into a string variable. Any suggestions would be appreciated. Thank you, Andrew =====script: class(ts) (ts[1,0]) #returns

I am trying to copy some digital images to a directory on my Redhat 7.3 Samba 2.2.3a-6 server and am getting extra files in the directory. I have included my SMB.Conf file contents below in case that is relevant. The files being copied reside on a Windows 2000 workstation and were created by Jasc Image robot. These files would have been accessed by both a Windows 2000 machine as well as a Windows

Hi, I encountered a problem of not being able to read in an excel spreadsheet using read.xls() in the xlsReadWrite package. can anyone help? Here is an example code write.xls(matrix(1:9,nrow=3),"ttt.xls") read.xls("ttt.xls") Error in read.xls("ttt.xls") : Unexpected error. Message: Can't find the file "ttt.xls" The "ttt.xls" file was

Hi, guys. Is there any easy way to know the leaf BB node in the CFG which is not terminated by such a 'br' instruction? E.g., for the following LLVM assembly: ----------------------------------------------------------- int %foo2(int %k) { entry: br label %bb bb: ; preds = %bb, %entry %indvar = phi uint [ 0, %entry ], [ %indvar.next, %bb ] ;

Hello, we are using the vfs module recycle with the following config: vfs objects = recycle recycle: repository = .Papierkorb recycle:directory_mode = 0777 recycle:subdir_mode = 0777 recycle: keeptree = Yes recycle: exclude = *.tmp, *.temp, *.log, *.ldb recycle: exclude_dir = tmp recycle:versions = Yes Problem is that everybody can see deleted documents in the recycle bin. But if I set

I am trying to symbolically execute LLVM assembly language. I found a possible semantic inconsistancy of the LLVM assembly language, or maybe my understanding is wrong. The C code is: #include <stdlib.h> 1 int f(void) 2 { 3 int a; 4 int *b = (int *) malloc(3*sizeof(int)); 5 a = 3; 6 return 0; 7 } I compile it with llvm-gcc 4 front end. The generated

Why fails nls with "singular gradient" here? I post a minimal example on the bottom and would be very happy if someone could help me. Kind regards, ########### # define some constants smallc <- 0.0001 t <- seq(0,1,0.001) t0 <- 0.5 tau1 <- 0.02 # generate yy(t) yy <- 1/2 * ( 1- tanh((t - t0)/smallc) * exp(-t / tau1) ) + rnorm(length(t))*0.01 # show the curve

Dear all, I'd like to subset a df within a function, and use select for choosing the variable. Something like (simplified example): mydf <- data.frame(a= 0:9, b= 10:19) ttt <- function(vv) { tmpdf <- subset(mydf, select= vv) mean(tmpdf$vv) } ttt(mydf$b) But this is not the correct way. Any help? Thanks in advance Juli